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EXPONENTS JEOPARDY. Simplifying Powers Evaluating Expressions Problem Solving 1611162126 2712172227 3813182328 4914192429 51015202530 EXPONENTS.

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Presentation on theme: "EXPONENTS JEOPARDY. Simplifying Powers Evaluating Expressions Problem Solving 1611162126 2712172227 3813182328 4914192429 51015202530 EXPONENTS."— Presentation transcript:

1 EXPONENTS JEOPARDY

2 Simplifying Powers Evaluating Expressions Problem Solving 1611162126 2712172227 3813182328 4914192429 51015202530 EXPONENTS

3 Simplifying Powers 3232

4 2424

5 (  1) 5 Simplifying Powers

6 4444

7 (  3) 4

8 Simplifying Powers (-4) 4

9 Simplifying Powers (-8) 3

10 Simplifying Powers (  14) 2

11 Simplifying Powers (1/6) 3

12 Simplifying Powers 2525

13 x4  yx4  y Evaluate the expression for x  –2 and y  3.

14 2x  y22x  y2

15 Evaluate the expression for the given values of the variables. n 3  5 for n  4

16 Evaluate the expression for the given values of the variables. 4x 2  y 3 for x  5 and y   2

17 Evaluate the expression for the given values of the variables. m p  q 2 for m  5, p  2, and q  4

18 a 4  2(b  c 2 ) for a  2, b  4, and c   1 Evaluate the expression for the given values of the variables.

19 n 3  5p for n  4 and p  3

20 Evaluate the expression for the given values of the variables. x 2  y 3 for x  5 and y   3

21 Evaluate the expression for the given values of the variables. ac  b c for a  12, b   6, and c  2

22 Evaluate the expression for the given values of the variables. s 4  (t  r) 5 for s  2, t  7, and r  8

23 Solve A population of bacteria doubles in size every minute. The number of bacteria after 5 minutes is 15 2 5. How many are there after 5 minutes?

24 Solve The formula for the volume of a cube is V  e 3 where e is the length of a side of the cube. Find the volume of a cube with side length 6 cm.

25 Solve The distance in feet traveled by a falling object is given by the formula d  16t 2 where t is the time in seconds. Find the distance an object falls in 4 seconds.

26 Solve The surface area of a cube can be found using the formula S  6e 2 where e is the length of a side of the cube. Find the surface area of a cube with side length 6 cm.

27 Solve John’s father offers to pay him 1 cent for doing the dishes the first night, 2 cents for doing the dishes the second, 4 cents for the third, and so on, doubling each night. Write an expression using exponents for the amount John will get paid on the tenth night.

28 Solve Find the area of a circle if the radius is 20 in. (Hint: A   r 2.) Use 3.14 for .

29 Solve Find the volume of a regular cube if the length of a side is 10 cm. (Hint: V  l 3.)

30 Solve Find the area of square with a side of 6 m. (Hint: Area  s 2.)

31 Solve The number of diagonals of an n-sided figure is ½(n 2 – 3n). Use the expression to find the number of diagonals for a 6-sided figure.

32 Solve The volume of a cube is calculated by using the formula V = s 3, where s is the length of the sides of the cube. What is the volume of a cube that has sides 8 meters long?


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