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ZAMSTAR restricted randomisation CREATE Investigators Meeting 2005 Charalambos (Babis) Sismanidis LSHTM.

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Presentation on theme: "ZAMSTAR restricted randomisation CREATE Investigators Meeting 2005 Charalambos (Babis) Sismanidis LSHTM."— Presentation transcript:

1 ZAMSTAR restricted randomisation CREATE Investigators Meeting 2005 Charalambos (Babis) Sismanidis LSHTM

2 ZAMSTAR overview  Zambia and South Africa tuberculosis and AIDS reduction study  24 communities (16 in Zambia, 8 in SA) are randomised in 4 arms (2x2 factorial).  Primary outcome: culture +ve TB prevalence (survey on 5,000 patients sampled in each cluster) after 3 years of intervention application

3 Description of interventions  TB/HIV @ clinic Strengthened DOTS VCT TB/HIV at health centre access (offering IPT) Basic HIV care HIV prevention (condoms, STI management)  Enhanced Tuberculosis Case Finding (ECF) Open access to sputum smear at health centre Schools education campaign Community mobilisation and mobile tuberculosis laboratory  Household level TB & HIV combined activities (HH) Household counsellor visiting all TB households Household members encouraged to test for HIV TB preventive therapy for HIV+ve and children <6  Both ECF & HH

4 ZAMSTAR primary aims  Does enhanced tuberculosis case finding (ECF) by a strategy of community mobilisation and improved access to sputum microscopy, reduce prevalence of tuberculosis in the community?  Do combined TB/HIV activities at the household level (HH), reduce prevalence of tuberculosis?  Does ECF plus HH (ECF+HH), yield additional benefits for tuberculosis control through additional case detection, improved case holding, treatment/prophylaxis of latent infection and reduction in HIV incidence?

5 Does ECF reduce the prevalence of tuberculosis in the community?

6 Does HH reduce the prevalence of tuberculosis in the community?

7 Stratification  The 24 clusters are stratified by country of cluster origin. 16 from Zambia, 8 in SA  Randomisation will be performed separately for each of the two strata

8 Zambia – Step I  4 equally numbered groups of As, Bs, Cs & Ds to form from 16 available communities (i.e. 4 communities in each group).  Arm A will include 4 communities out of the 16: 16!/12!4! = 1820 choices Arm B another 4 from the remaining 12 communities: 12!/8!4! = 495 choices Arm C another 4 from the remaining 8: 8!/4!4! = 70 choices Arm D 4 from the remaining 4: 4!/4!0! = 1 choice  This amounts to=1820*495*70*1=63,063,000

9 Zambia – Step II  BUT since we do not have a fixed sequence by which intervention arms will be picked (sequence ABCD is a generic example) we need to multiply the previous total by 4! (i.e. all possible permutations for an array of 4 elements).  TOTAL: 63,063,000*4! = 1,513,512,000

10 South Africa – Step I  4 equally numbered groups (= intervention arms) of As, Bs, Cs & Ds to form from 8 available communities (i.e. 2 communities in each group).  Arm A will have 2 communities out of 8 = 8!/6!2! = 28 choices Arm B another 2 from the remaining 6 communities (6!/4!2!) = 15 choices Arm C another 2 from the remaining 4 = 4!/2!2! = 6 choices Arm D 2 from the remaining 2 = 1 choice  Which amounts to = 28*15*6*1=2520

11 South Africa – Step II  Similarly since we do not have a fixed sequence by which intervention arms will be picked we need to multiply the previous total by 4!  TOTAL: 2520*4! = 2520*24 = 60,480

12 Computational headaches  Because of the very large number of possible permutations it has not so far been possible to list them all  Single file size not allowed to be >12GB  Current code produces multiple identical observations (which are then dropped)

13 Restricting randomisation  Possible restrictions: HIV prevalence TB infection (TST in children) Open/Closed communities (Social Science) Political restrictions (not all clusters in a community in the control arm-should this be extended to all arms?)

14 Changing lanes  THRio approach?  Instead of listing all possible permutations to get the exact proportion by which randomisation is restricted, I will now be randomly drawing a set number of permutations to estimate this proportion.  Then randomly draw one permutation from a list of ‘acceptable’ ones


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