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Published byMorgan McKinney Modified over 8 years ago
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Gauss’s Law (II) Examples: charged spherical shell, infinite plane, long straight wire Review: For a closed surface S: Net outward flux through S
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Calculating E for symmetric charge distributions 1)Use symmetry to sketch the behaviour of E (possible only for very symmetric distributions) 2)Pick an imaginary “Gaussian surface” S 3)Calculate the flux through S, in terms of an unknown |E| 4)Calculate the charge enclosed by S from geometry 5)Relate 3) and 4) by Gauss’s Law, solve for |E|
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Example: Uniformly-Charged Thin Sheet ++++ ++++ + ++ E Gaussian surface Find E due to an infinite charged sheet
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Solution
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Example: Infinite Line Charge (Long thin Wire) +++++++++ r L Find E at distance r from the wire
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Solution
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Conductors (in Electrostatic Equilibrium) 1) inside a conductor. 2) just outside a conductor. 3)Any net charge on a conductor resides on the surface only.
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Example: Hollow Thin Spherical Shell + + + + + + + + + + + + + r r a P1P1 P2P2 Total charge Q Find E outside at P 1 : (r > a): Find E inside at P 2 : (r < a):
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Solution
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1) If, charges would move!!! 2) If, charges would move!!! E=0 inside E + E ll Consequences if E was not zero:
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3) inside, so any Gaussian surface inside the conductor encloses zero net charge. + + + + + + +++++++++ + + + + + ++++++++ Since E = 0 everywhere. So net charge =0
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+ - + + + - - - - conductor
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Surface Charge Density on a Conductor + + + + + E = 0 inside dA 1 dA 2 E What is E at the surface of the conductor?
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Solution
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Example: Metal ball of radius R 1 has charge +Q Metal shell of radius R 2,and R 3 has total charge -3Q ) Find: charges on each surface. (and E) -3Q +Q R1R1 R2R2 R3R3
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Solution
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Quick Recap Conductor: Infinite Sheet of charge: Why is the lower value half of the upper? At surface of conductor
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