1. B.E. ELECTRICAL ENGINEERING DEPARTMENT OF ELECTRICAL ENGINEERING SIGMA INSTITUTE OF ENGINEERING BAKROL, VADODARA Active Learning Assignment topic on: Prepared By:Guided By: Chirag Patel (130500109031)Mr Nirav Parmar Jigar Patel (130500109032)Asst. Professor Priyal Patel (130500109036)Electrical Department SIE, Bakrol, Vadodara.

2. Op Amps Applications Audio amplifiers – Speakers and microphone circuits in cell phones, computers, mpg players, boom boxes, etc. Instrumentation amplifiers – Biomedical systems including heart monitors and oxygen sensors. Power amplifiers Analog computers – Combination of integrators, differentiators, summing amplifiers, and multipliers

3. Symbols for Ideal and Real Op Amps OpAmpuA741 LM111LM324

4. Terminals on an Op Amp Non-inverting Input terminal Inverting input terminal Output terminal Positive power supply (Positive rail) Negative power supply (Negative rail)

5. Op Amp Equivalent Circuit v d = v 2 – v 1 A is the open-loop voltage gain v2v2 v1v1 Voltage controlled voltage source

6. Ideal Op Amp i 2 = 0 i 1 = 0 Because Ri is equal to ∞W, the voltage across Ri is 0V. v 1 = v 2 v d = 0 V v1v1 v2v2

7. Almost Ideal Op Amp Ri = ∞ W – Therefore, i 1 = i 2 = 0A Ro = 0 W Usually, v d = 0V so v 1 = v 2 – The op amp forces the voltage at the inverting input terminal to be equal to the voltage at the noninverting input terminal if there is some component connecting the output terminal to the inverting input terminal. Rarely is the op amp limited to V - < v o < V +. – The output voltage is allowed to be as positive or as negative as needed to force v d = 0V.

8. Example #1: Voltage Comparator i 2 = 0 i 1 = 0 i s = 0 Note that the inverting input and non-inverting input terminals have rotated in this schematic.

9. Example #1 (con’t) The internal circuitry in the op amp tries to force the voltage at the inverting input to be equal to the non-inverting input. – As we will see shortly, a number of op amp circuits have a resistor between the output terminal and the inverting input terminals to allow the output voltage to influence the value of the voltage at the inverting input terminal.

10. Example #2: Closed Loop Gain i 2 = 0 i 1 = 0 isis ifif v1v1 v2v2

11. Example #2 (con’t) isis ifif i2i2 ioio isis ifif i1i1 For an almost ideal op amp, Ri = ∞ W and Ro = 0 W. The output voltage will never reach V + or V -.

12. Example #2 (con’t) isis ifif i2i2 i isis ifif i1i1 The op amp outputs a voltage Vo such that V1 = V2. Virtual ground

13. Example #2 (con’t) i1i1 i2i2 i isis ifif

14. Example #2: Closed Loop Gain This circuit is known as an inverting amplifier. C A B

15. Types of Gain isis ifif i2i2 i isis ifif i1i1 ioio

16. Types of Closed Loop Gain GainVariable Name EquationUnits Voltage GainAVAV v o /v s None or V/V Current GainAIAI i o /i s None or A/A Transresistance GainARAR v o /i s V/A or W Transconductance Gain AGAG i o /v s A/V or W -1

17. Example #3: Closed Loop Gain with Real Op Amp isis ifif i2i2 i v1v1 v2v2 isis ifif i1i1

18. Example #3 (con’t) i s = i 1 + i f i = i f - i 1 = i 2 v d = v 2 – v 1 = Ri (- i 1 ) = Ri (i 2 ) V o = Av d - Ro(- i) V s = R1(i s ) – v d V s = R1(i s ) + Rf(i f ) + V o V o /V s = (-R f /R1){Ab/[1 +Ab]}, where b = R1/(R1+R f )

19. Summary The output of an ideal op amp is a voltage from a dependent voltage source that attempts to force the voltage at the inverting input terminal to equal the voltage at the non-inverting input terminal. – Almost ideal op amp: Output voltage limited to the range between V + and V -. Ideal op amp is assumed to have Ri = ∞ W and Ro = 0 W. – Almost ideal op amp: v d = 0 V and the current flowing into the output terminal of the op amp is as much as required to force v 1 = v 2 when V + < v o < V -. Operation of an op amp was used in the analysis of voltage comparator and inverting amplifier circuits. – Effect of Ri 0 W was shown.

20. Thank you!