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سیستمهای کنترل خطی پاییز 1389 بسم ا... الرحمن الرحيم دکتر حسين بلندي- دکتر سید مجید اسما عیل زاده
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Recap. Transient Response: First order system transient response –Step response specs and relationship to pole location Second order system transient response 2
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Error
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The error signal: e(t) = 1-y(t)=e -at us(t) Normalized time t/
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General First-order system Step response starts at y(0+)=k, final value kz/p 1/p = is still time constant; in every , y(t) moves 63.2% closer to final value
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Unit ramp response:
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Note: In step response, the steady-state tracking error = zero.
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Unit impulse response:
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Performance of a second-order system 10
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Prototype 2 nd order system:
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Characteristic equation 12
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Unit step response: 1) Under damped, 0 < ζ < 1
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cos = =-Re/|root| = cos -1 (Re/|root|) = tan -1 (-Re/Im) d =Im =-Re
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To find y(t) max:
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Response to unit step input 21
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Natural frequency n - the frequency of natural oscillation that would occur for two complex poles if the damping were equal to zero Damping ratio - a measure of damping for second-order characteristic equation 22
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Characteristic equation 23
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Finding n and for a second-order system 24
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Second-order responses for underdamped 25
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Unit impulse response R(s)=1 T(s)=Y(s) 26
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Standard performance measures Peak time Settling time Percent overshoot Peak response 28
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fig_04_14 29
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Settling time The settling time is defined as the time required for a system to settle within a certain percentage of the input amplitude. 30
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Settling time 31
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Rise time The time it takes for a signal to go from 10% of its value to 90% of its final value 32
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Rise time 33
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Peak time Peak time is the time required by a signal to reach its maximum value. 34
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Peak time 35
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Percent overshoot Percent Overshoot is defined as: P.O. = [(M pt – fv) / fv] * 100% M pt = The peak value of the time response fv = Final value of the response 36
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Percent overshoot 37
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Finding transient response 38
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Gain design for transient response 40
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Controllable Canonical Form
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Observable Canonical Form Diagonal Form
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Jordan Form
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حل معادلات فضاي حالت در محدوده فركانس
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حل معادلات فضاي حالت در محدوده زمان عكس تبديل لاپلاس مي گيريم: از معادله
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سؤال: چگونه ماتريس را محاسبه كنيم؟ (2). (3). (1).
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Example 1)
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Example2) If
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روش سوم: تابع يك ماتريس مربعي ) Function of a square matrix) يك تابع باشد كه در Spectrum (دامنه يا طيف) و اگر نيز يك چند جمله اي باشد كه داراي مقادير مساوي مانند در دامنه باشد سپس تابع مي باشد، بشكل زير تعريف مي گردد: اگر تعريف شده باشد كه يك تابع مقدار-ماتريسي ( Matrix Valued )
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يعني كه اگر يك ماتريس باشد، اگر كه مقدار از روي شود، ما مي توانيم يك چندجمله اي پيدا كنيم كه داراي درجه داده مي باشد بطوريكه: بطوريكه برابر با در دامنه كه تمامي توابع عبارتند از: مي باشد. از اين تعريف مي دانيم
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طريقه عمل : 1. مقادير ويژه را محاسبه نمائيد. 2. 3. مثال : اگر را محاسبه نمائيد.
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1) 2)
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مثال:.1.2
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مثال: (1
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From
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مثال:
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حل معادلات حالت
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حل : (1 (2 (3 (4
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مثال: حل:
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حل:
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مثال : حل :
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