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Phy2005 Applied Physics II Spring 2016 Announcements: Test 2 Wednesday, March 23 2 practice tests posted on course Tests page Review session in class March 21 in class + 1 evening tba PH travel next week APS Spring meeting; Prof. Lee subs
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Science news page Link to NYT video “Total Solar Eclipse Will End the Day Before It Begins”
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Non-magnetic metal plate induced current in metal: Eddy current Last time: Eddy currents I There is an emf around any loop where flux is changing!
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Last Time t x -A x0x0 T (period) x = Asin(2 ft) frequency: f = 1/T angular frequency: = 2 f = 2 /T “repeat time” 0T x rms
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Last time: Iron Core AC V NpNp NsNs V p /V s = N p /N s p=primary s=secondary
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http://www.howstuffworks.com/ Hot Neutral GND
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Power Transmission Gainesville has a population of 120,000. On average approximately 200 W/person of electric power is required. Let’s assume that GRU transmits power with 120 V. How much current should be carried in the power line? P t = 120,000 x 200 W = 24,000,000 W = 24 MW P = IV, I = P/V = 24,000,000/120 = 200,000 A However, if we deliver power with 500,000 V, I = 24,000,000/500,000 = 48 A Now Joule heating (I 2 R) due to wire resistance (R) is reduced By (48/200,000) 2 = 5.8 x 10 -8
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From now on, when you see voltage or current in lower case, those indicate AC voltage or current. I: DC currenti: AC current V: DC voltagev: AC voltage
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R V = V o R v = v o sin(2 ft) P = V 2 /R = I 2 R = IV t P = V o 2 /R: constant in timeP = (v o sin(2 t)) 2 /R: varying in time T = 1/f V, V 2
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v2v2 t We need to take the average (mean) of the time dependent power over one cycle!! P = (v o sin(2 t)) 2 /R: varying in time = /R = v o 2 /2 So on average replace
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Root Mean Square (rms) Root does not mean square! You have a variable x. Square, take average, and put square-root. Use rms values of v and i for AC to evaluate average power. = v rms 2 /R = i rms 2 R = i rms v rms
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Ex 22-2 A sinusoidal AC voltage source with a 20 V amplitude and a 15 Hz frequency is applied across an electric heater with 10 resistance. (a) Write down a mathematical expression for the voltage. (b) What is the rms value of the voltage source? (c) How much power is dissipated in this heater? (a) v = 20sin(94.2t) (b) v rms = 14.14 V (c) = 20 W
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Ex 22-3 A 75-W light bulb is operated on its rated 120 V/60 Hz power. Find the rms current drawn by the bulb. = i rms v rms i rms = 75/120 = 0.625 A
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ACADEMIC HONESTY Each student is expected to hold himself/herself to a high standard of academic honesty. Under the UF academic honesty policy. Violations of this policy will be dealt with severely. There will be no warnings or exceptions.UF academic honesty policy
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Q1 A current is given by i = 2sin(40t) A. Find the peak current (A), the rms current (B), and the frequency. (A) (B) (C) 1. 2 A2.83 A 40 Hz 2. 4 A2.83 A 20 Hz 3. 2A1.41 A 6.37 Hz 4. 4 A1.41 A 12.7 Hz
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http://www.educatorscorner.com/ R C L
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Increase current through the coil from 0 to i in t. Loop area: A Length of coil: ℓ Winding density: n = N/ ℓ Causes flux change for each loop from = 0 to = AB where B = o n i V ind = - n ℓ / t = - n ℓ A( o n) i/ t = - n 2 o A ℓ ( i / t) L: self inductance geometrical quantity [L] = Henry For a long solenoid B = o nI n: number of turns/m V ind = -L( i/ t)
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Joseph Henry 1797-1878 American physicist Henry discovered the electromagnetic phenomenon of self-inductance. He also discovered mutual inductance independently of Michael Faraday, (1791–1867), though Faraday was the first to make the discovery and publish his results. [2][3][4] Henry developed the electromagnet into a practical device. He invented a precursor to the electric doorbell (specifically a bell that could be rung at a distance via an electric wire, 1831) [5] and electric relay (1835). [6] The SI unit of inductance, the henry, is named in his honor.electromagneticinductanceMichael Faraday [2][3][4]electromagnetdoorbell [5]relay [6] SIinductancehenry
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