1. Ch 11 Problem solving

2. #31 Step 1: calculate the heat required to evaporate using  H vap 50 g x 2.4 kJ/g = 120kJ convert = 1.2 x10 5 J The solve for mass using Q = m·C p ·ΔT m = Q/C p ·ΔT 1.2 x10 5 J / (4.18 J/g-K x 13 K) = 2.2x10 3 g H 2 O

3. #33 1. Q = m·C p of solid ·ΔT 3. Q = m·C p of liquid ·ΔT 2. g  mol then mol x  H fus 4. g  mol then mol x  H vap Step 5 add kJ from #1-4 0.4365kJ + 8.172kJ + 33.12 kJ+ 62.77kJ = 105kJ

4. WDP #48

5. WDP #44

6. WDP #46

7. WDP # 50 part 1

8. WDP #50 part 2 Your book gives the specific heat of steam as 1.84 J/g-K, while this book gives it as 2.03 J/g-K

9. WDP #51 With the formula rearranged it would look like: m = Q/C p ·ΔT g H 2 O = 2.26 x 10 3 J 4.18 J/g-K* 15K = 36.0 g H 2 O