Download presentation
Presentation is loading. Please wait.
Published byKatherine Hines Modified over 8 years ago
1
Sec. 12 – 2 Chords and Arcs Objectives: 1) To use chords, arcs, & central s. 2) To recognize properties of lines through the center of a circle.
2
More Circle Properties C Q P R Chord – A segment whose endpts are on a circle. Ex: PQ Central s – in a circle, whose vertex is at the center of the circle. Rays of central s are radii of the circle. Sum of central s (w/ no common interior pts) are 360°
3
Central s and Arcs A central will divide a circle into 2 arcs. Minor Arc – –Less than ½ of the circle – –Meas. is always less than (<) 180°. – –Name it using 2 letters – –Ex: PQ Major Arc – –More than ½ of the circle – –Meas. is always more than (>) 180°. – –Name it using 3 letters – –Ex: PRQ C Q P R ** All arcs are measured by their corresponding central s.
4
Things to remember about Arcs Central s have chords. Chords have Arcs. Arcs have Central s. Semicircle –When the measure of an arc = 180°. –Cuts the circle in half. –Name it using 3 letters.
5
Ex.1: Naming Arcs Name a minor arc. Name a major arc. Name a semicircle. T A B C AB, BC, CD, or BD ADB, DBA, ABD ADC or CBA D
6
Ex.2: Meas. of arcs and central T A B D 22° C mDC = m ATB = mAB = m ATD = mAD = mADC = m ATC 22° 90° 158° 180°
7
More with Chords 1) Chords equidistant from the center are . - If TP RP, then AB CD - If TP RP, then AB CD 2) chords are equidistant from the center. - If CD AB, then TP RP 3) If 1 & 2 are true, then TP bisects AB & RP bisects CD. - If AT BT, then CR DR - If AT BT, then CR DR A T B P R D C ll
8
Ex.3: Solve for the missing Variables m B = 32 A B P D l l l l 9cm 12.5cm 16 AB = m P = m 1 = m 2 = BP = 25cm 148 74 15.4cm a 2 + b 2 = c 2 9 2 + 12.5 2 = BP 2 81 + 156.25 = BP 2 BP = 15.4cm
9
3 more special appications In a circle, a diameter that is to a chord bisects the chord & its arc. In a circle, a diameter that bisects a chord (that is not a diameter) is to the chord. In a circle, the bisector of a chord contains the center of the circle.
10
Ex.4: Solve for the missing sides. A B D C 7m 3m BC = AB = AD = 7m 14m 7.6m a 2 + b 2 = c 2 3 2 + 9 2 = AD 2 9 + 81 = AD 2 AD = 7.6m
11
What have we learned??? Central measure = arc measure Minor Arc –Naming using 2 letters (<180 ) Major Arc –Naming using 3 letters (>180 ) The bisector of the circle contains the center of the circle. A T B C D 123
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.