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List the three (3) equations used in this chapter.
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d = d o + v o ·t + ½ a·t 2
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List the three (3) equations used in this chapter. d = d o + v o ·t + ½ a·t 2 v = v o + a·t
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List the three (3) equations used in this chapter. d = d o + v o ·t + ½ a·t 2 v = v o + a·t a = (Δv) / t = (v – v o ) / t
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Record the meaning of each variable.
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d o = initial position
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Record the meaning of each variable. d o = initial position d = current (or final) position
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Record the meaning of each variable. d o = initial position d = current (or final) position v o = initial velocity
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Record the meaning of each variable. d o = initial position d = current (or final) position v o = initial velocity v = current (or final) velocity
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Define the following.
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Position – location related to reference point
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Define the following. Position – location related to reference point Velocity – change in position per time
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Define the following. Position – location related to reference point Velocity – change in position per time Acceleration – change in velocity per time
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Which parts of your car can instantly cause acceleration? Explain each.
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Acceleration =
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Which parts of your car can instantly cause acceleration? Explain each. Acceleration = change in velocity
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Which parts of your car can instantly cause acceleration? Explain each. Acceleration = change in velocity Gas – increases (changes) speed Brake – decreases (changes) speed
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Consider a position-time graph (d-t)
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Slope = velocity
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Consider a position-time graph (d-t) Slope = velocity Y-int = initial position
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Consider a position-time graph (d-t) Slope = velocity Y-int = initial position Flat line = no change in position (no motion)
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Consider a position-time graph (d-t) Slope = velocity Y-int = initial position Flat line = no change in position (no motion) Line = constant change (constant velocity)
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Consider a position-time graph (d-t) Slope = velocity Y-int = initial position Flat line = no change in position (no motion) Line = constant change (constant velocity) Curve = changing velocity (acceleration)
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Consider a velocity-time graph (v-t)
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Slope = acceleration
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Consider a velocity-time graph (v-t) Slope = acceleration Y-int = initial velocity
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Consider a velocity-time graph (v-t) Slope = acceleration Y-int = initial velocity Flat line = no change (constant velocity) (zero acceleration)
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Consider a velocity-time graph (v-t) Slope = acceleration Y-int = initial velocity Flat line = no change (constant velocity) (zero acceleration) Line = constant change (constant accel)
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What do all acceleration-time graphs in this class look like? Why?
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Flat lines
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What do all acceleration-time graphs in this class look like? Why? Flat lines All our accelerations will be constant (no change)
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Explain how an object can slow down with a positive acceleration.
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Negative velocity and positive accleration
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Explain how an object can slow down with a positive acceleration. Negative velocity and positive accleration +velocity and +acceleration (speed up) +velocity and (-)acceleration (slow down) (-)velocity and +acceleration (slow down) (-)velocity and (-)acceleration (speed up)
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What general rule can you follow to know if an object speeds up or slows down during acceleration?
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Acceleration and velocity direction:
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What general rule can you follow to know if an object speeds up or slows down during acceleration? Acceleration and velocity direction: Same sign = speed up Opposite sign = slow down
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Write an equation for a dune buggy that starts at the origin and travels to the right at 5.0 m/s.
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d = d o + v o ·t + ½ a·t 2
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Write an equation for a dune buggy that starts at the origin and travels to the right at 5.0 m/s. d = d o + v o ·t + ½ a·t 2 d = 0 + (5m/s) t + ½ (0) t 2
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Write an equation for a dune buggy that starts at the origin and travels to the right at 5.0 m/s. d = d o + v o ·t + ½ a·t 2 d = 0 + (5m/s) t + ½ (0) t 2 d = (5)t
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Write an equation for a car that starts at the origin at rest and accelerates to the right at 6.0 m/s 2.
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d = d o + v o ·t + ½ a·t 2
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Write an equation for a car that starts at the origin at rest and accelerates to the right at 6.0 m/s 2. d = d o + v o ·t + ½ a·t 2 d = 0 + (0 m/s) t + ½ (6 m/s 2 ) t 2
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Write an equation for a car that starts at the origin at rest and accelerates to the right at 6.0 m/s 2. d = d o + v o ·t + ½ a·t 2 d = 0 + (0 m/s) t + ½ (6 m/s 2 ) t 2 d = (3)t 2
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Write a velocity equation for the previous fan car.
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v f = v o + a·t
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Write a velocity equation for the previous fan car. v f = v o + a·t v f = 0 m/s + (6.0 m/s 2 )·t
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Write a velocity equation for the previous fan car. v f = v o + a·t v f = 0 m/s + (6.0 m/s 2 )·t v f = (6)t
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Using the previous two questions, show how you could find out when they would meet?
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Set both equations equal to each other
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Using the previous two questions, show how you could find out when they would meet? Set both equations equal to each other (5) t = (0.5) t 2
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Using the previous three questions, show how you could find out where they would meet?
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Use the calculated time in either equation
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13a) a = 0.75 m/s 2 13b) ∆d = 216 m 14a) V f = 10 m/s 14b) ∆d = 150 m 15) v 0 = 5 m/s 16) ∆d = 48 m 17) a = -125 m/s 2 (an answer of 25 m/s 2 means you forgot directions on your velocities) 18a) a = -2.5 m/s 2 18b) ∆d = 125 m
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d-ta-tv-t This shape can appear anywhere along the y-axis
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d-ta-tv-t This shape can appear anywhere along the y-axis
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d-ta-tv-t This shape can appear anywhere along the y-axis
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d-ta-tv-t This shape can appear anywhere along the y-axis
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d (m ) t ( sec) A B C D E F G
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