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2.8.1 MATHPOWER TM 12, WESTERN EDITION 2.8 Chapter 2 Exponents and Logarithms.

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Presentation on theme: "2.8.1 MATHPOWER TM 12, WESTERN EDITION 2.8 Chapter 2 Exponents and Logarithms."— Presentation transcript:

1 2.8.1 MATHPOWER TM 12, WESTERN EDITION 2.8 Chapter 2 Exponents and Logarithms

2 In 1987, the world’s population was 5 billion and was increasing at a rate of 1.6% per annum. An equation for this, as a function of time is: P = 5(1.016) t In the study of exponents and logs, different bases are often used. It would simplify matters to use the same base every time. Mathematicians have found that using base e is very advantageous. Express this using base e: Let 1.016 = e k.By definition, k = ln 1.016. ln 1.016 = 0.0158733= 0.016 (to 2 significant digits) Hence, 1.016 = e 0.016.The equation can now be written as: P = 5e 0.016t Growth Rate Initial population The exponent of base e is the growth rate. 2.8.2

3 If 1987, the world’s population was 5 billion and was increasing at a rate of 1.6% per annum. Predict the world population in 2010. P = 5e 0.016t t = 27 years P = 5e 0.016 x 27 P = 7.70 Therefore, the projected world population would be 7.7 billion people. 2.8.3 Population Growth

4 Light passes through glass with an absorption coefficient of 0.25. Find the thickness of glass that will reduce the light’s intensity to half its initial intensity. I(t) = I o e -0.25t t = thickness of the glass I = intensity I o = initial intensity 50 = 100e -0.25t 0.5 = e -0.25t Take the natural logarithms of both sides: ln 0.5 = -0.25t t = 2.77 Therefore, the glass would be 2.8 mm thick. 2.8.4 An Application of Natural Logs

5 Suggested Questions: Page 119 1-19 odd, 29 Pages 124 and 125 1 1- 4 Review Page 128 1-13 2.8.5


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