1. MM150 ~ Unit 9 Statistics ~ Part II

2. WHAT YOU WILL LEARN Mode, median, mean, and midrange Percentiles and quartiles Range and standard deviation z-scores and the normal distribution Correlation and regression

3. 9.1 Measures of Central Tendency

4. Definitions An average is a number that is representative of a group of data. The arithmetic mean, or simply the mean is symbolized by, when it is a sample of a population or by the Greek letter mu, , when it is the entire population.

5. Mean The mean, is the sum of the data divided by the number of pieces of data. The formula for calculating the mean is where represents the sum of all the data and n represents the number of pieces of data.

6. Example-find the mean Find the mean amount of money parents spent on new school supplies and clothes if 5 parents randomly surveyed replied as follows: $327 $465 $672 $150 $230

7. Median The median is the value in the middle of a set of ranked data. Example: Determine the median of $327 $465 $672 $150 $230. Rank the data from smallest to largest. $150 $230 $327 $465 $672 middle value (median)

8. Example: Median (even data) Determine the median of the following set of data: 8, 15, 9, 3, 4, 7, 11, 12, 6, 4. Rank the data: 3 4 4 6 7 8 9 11 12 15 There are 10 pieces of data so the median will lie halfway between the two middle pieces the 7 and 8. The median is (7 + 8)/2 = 7.5 3 4 4 6 9 11 12 15 7 8 (median) middle value

9. Mode The mode is the piece of data that occurs most frequently. Example: Determine the mode of the data set: 3, 4, 4, 6, 7, 8, 9, 11, 12, 15. The mode is 4 since it occurs twice and the other values only occur once.

10. Midrange The midrange is the value halfway between the lowest (L) and highest (H) values in a set of data. Example: Find the midrange of the data set $327, $465, $672, $150, $230.

11. Example The weights of eight Labrador retrievers rounded to the nearest pound are 85, 92, 88, 75, 94, 88, 84, and 101. Determine the a) mean b) median c) mode d) midrange e) rank the measures of central tendency from lowest to highest.

12. Example--dog weights 85, 92, 88, 75, 94, 88, 84, 101 a. Mean b. Median-rank the data 75, 84, 85, 88, 88, 92, 94, 101 The median is 88.

13. Example--dog weights 85, 92, 88, 75, 94, 88, 84, 101 c.Mode-the number that occurs most frequently. The mode is 88. d. Midrange = (L + H)/2 = (75 + 101)/2 = 88 e. Rank the measures, lowest to highest 88, 88, 88, 88.375

14. Measures of Position Measures of position are often used to make comparisons. Two measures of position are percentiles and quartiles.

15. To Find the Quartiles of a Set of Data 1.Order the data from smallest to largest. 2.Find the median, or 2 nd quartile, of the set of data. If there are an odd number of pieces of data, the median is the middle value. If there are an even number of pieces of data, the median will be halfway between the two middle pieces of data.

16. To Find the Quartiles of a Set of Data continued 3.The first quartile, Q 1, is the median of the lower half of the data; that is, Q 1, is the median of the data less than Q 2. 4.The third quartile, Q 3, is the median of the upper half of the data; that is, Q 3 is the median of the data greater than Q 2.

17. Example: Quartiles The weekly grocery bills for 23 families are as follows. Determine Q 1, Q 2, and Q 3. 170210270270280 33080170240270 22522521531050 751601307481 95172190

18. Example: Quartiles continued Order the data: 50 75 74 80 81 95130 160170170172190210215 225225240270270270280 310330 Q 2 is the median of the entire data set which is 190. Q 1 is the median of the numbers from 50 to 172 which is 95. Q 3 is the median of the numbers from 210 to 330 which is 270.

19. 9.2 Measures of Dispersion

20. Measures of dispersion are used to indicate the spread of the data. The range is the difference between the highest and lowest values; it indicates the total spread of the data. Range = highest value – lowest value

21. Example: Range Nine different employees were selected and the amount of their salary was recorded. Find the range of the salaries. $24,000$32,000 $26,500 $56,000 $48,000 $27,000 $28,500 $34,500 $56,750 Range = $56,750  $24,000 = $32,750

22. Standard Deviation The standard deviation measures how much the data differ from the mean. It is symbolized with s when it is calculated for a sample, and with  (Greek letter sigma) when it is calculated for a population.

23. To Find the Standard Deviation of a Set of Data 1. Find the mean of the set of data. 2. Make a chart having three columns: Data Data  Mean (Data  Mean) 2 3. List the data vertically under the column marked Data. 4. Subtract the mean from each piece of data and place the difference in the Data  Mean column.

24. To Find the Standard Deviation of a Set of Data continued 5.Square the values obtained in the Data  Mean column and record these values in the (Data  Mean) 2 column. 6.Determine the sum of the values in the (Data  Mean) 2 column. 7.Divide the sum obtained in step 6 by n  1, where n is the number of pieces of data. 8.Determine the square root of the number obtained in step 7. This number is the standard deviation of the set of data.

25. Example Find the standard deviation of the following prices of selected washing machines: $280, $217, $665, $684, $939, $299 Find the mean.

26. Example continued, mean = 514 421,5160 180,625425939 28,900170684 22,801151665 46,225  215 299 54,756  234 280 (  297) 2 = 88,209  297 217 (Data  Mean) 2 Data  Mean Data

27. Example continued, mean = 514 The standard deviation is $290.35.

28. 9.3 The Normal Curve

29. Types of Distributions Rectangular Distribution J-shaped distribution

30. Types of Distributions continued Bimodal Skewed to right

31. Types of Distributions continued Skewed to left Normal

32. Properties of a Normal Distribution The graph of a normal distribution is called the normal curve. The normal curve is bell shaped and symmetric about the mean. In a normal distribution, the mean, median, and mode all have the same value and all occur at the center of the distribution.

33. Empirical Rule Approximately 68% of all the data lie within one standard deviation of the mean (in both directions). Approximately 95% of all the data lie within two standard deviations of the mean (in both directions). Approximately 99.7% of all the data lie within three standard deviations of the mean (in both directions).

34. z-Scores z-scores determine how far, in terms of standard deviations, a given score is from the mean of the distribution.

35. Example: z-scores A normal distribution has a mean of 50 and a standard deviation of 5. Find z-scores for the following values. a) 55b) 60c) 43 a) A score of 55 is one standard deviation above the mean.

36. Example: z-scores continued b) A score of 60 is 2 standard deviations above the mean. c) A score of 43 is 1.4 standard deviations below the mean.

37. To Find the Percent of Data Between any Two Values 1. Draw a diagram of the normal curve, indicating the area or percent to be determined. 2.Use the formula to convert the given values to z-scores. Indicate these z- scores on the diagram. 3. Look up the percent that corresponds to each z-score in Table 13.7.

38. To Find the Percent of Data Between any Two Values continued 4. a) When finding the percent of data between two z- scores on opposite sides of the mean (when one z-score is positive and the other is negative), you find the sum of the individual percents. b) When finding the percent of data between two z- scores on the same side of the mean (when both z-scores are positive or both are negative), subtract the smaller percent from the larger percent.

39. To Find the Percent of Data Between any Two Values continued c) When finding the percent of data to the right of a positive z-score or to the left of a negative z-score, subtract the percent of data between 0 and z from 50%. d) When finding the percent of data to the left of a positive z-score or to the right of a negative z- score, add the percent of data between 0 and z to 50%.

40. Example Assume that the waiting times for customers at a popular restaurant before being seated for lunch are normally distributed with a mean of 12 minutes and a standard deviation of 3 min. a)Find the percent of customers who wait for at least 12 minutes before being seated. b)Find the percent of customers who wait between 9 and 18 minutes before being seated. c)Find the percent of customers who wait at least 17 minutes before being seated. d)Find the percent of customers who wait less than 8 minutes before being seated.

41. Solution a. wait for at least 12 minutes Since 12 minutes is the mean, half, or 50% of customers wait at least 12 min before being seated. b. between 9 and 18 minutes Use table 9.4 page 387. 34.1% + 47.7% = 81.8%

42. Solution continued c. at least 17 min Use table 9.4 page 387. 45.3% is between the mean and 1.67. 50%  45.3% = 4.7% Thus, 4.7% of customers wait at least 17 minutes. d. less than 8 min Use table 9.4 page 387. 40.8% is between the mean and  1.33. 50%  40.8% = 9.2% Thus, 9.2% of customers wait less than 8 minutes.

43. 9.4 Linear Correlation and Regression

44. Linear Correlation Linear correlation is used to determine whether there is a relationship between two quantities and, if so, how strong the relationship is.

45. Linear Correlation – The linear correlation coefficient, r, is a unitless measure that describes the strength of the linear relationship between two variables. If the value is positive, as one variable increases, the other increases. If the value is negative, as one variable increases, the other decreases. The variable, r, will always be a value between –1 and 1 inclusive.

46. Scatter Diagrams A visual aid used with correlation is the scatter diagram, a plot of points (bivariate data). – The independent variable, x, generally is a quantity that can be controlled. – The dependent variable, y, is the other variable. The value of r is a measure of how far a set of points varies from a straight line. – The greater the spread, the weaker the correlation and the closer the r value is to 0. – The smaller the spread, the stronger the correlation and the closer the r value is to 1.

47. Correlation

49. Linear Correlation Coefficient The formula to calculate the correlation coefficient (r) is as follows:

50. There are five applicants applying for a job as a medical transcriptionist. The following shows the results of the applicants when asked to type a chart. Determine the correlation coefficient between the words per minute typed and the number of mistakes. Example: Words Per Minute versus Mistakes 934Nancy 1041Kendra 1253Phillip 1167George 824Ellen MistakesWords per MinuteApplicant

51. We will call the words typed per minute, x, and the mistakes, y. List the values of x and y and calculate the necessary sums. Solution 306811156934 xy = 2,281 y 2 = 510 x 2 =10,711 y =50 x=219 10 12 11 8 y Mistakes xyy2y2 x2x2 x 41 53 67 24 WPM 4101001681 6361442809 7371214489 19264576

52. Solution continued The n in the formula represents the number of pieces of data. Here n = 5.

53. Solution continued

54. Since 0.86 is fairly close to 1, there is a fairly strong positive correlation. This result implies that the more words typed per minute, the more mistakes made.

55. Linear Regression Linear regression is the process of determining the linear relationship between two variables. The line of best fit (regression line or the least squares line) is the line such that the sum of the squares of the vertical distances from the line to the data points (on a scatter diagram) is a minimum.

56. The Line of Best Fit Equation:

57. Example Use the data in the previous example to find the equation of the line that relates the number of words per minute and the number of mistakes made while typing a chart. Graph the equation of the line of best fit on a scatter diagram that illustrates the set of bivariate points.

58. Solution From the previous results, we know that

59. Solution Now we find the y-intercept, b. Therefore the line of best fit is y = 0.081x + 6.452

60. Solution continued To graph y = 0.081x + 6.452, plot at least two points and draw the graph. 8.88230 8.07220 7.26210 yx

61. Solution continued