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Published byJustin Fleming Modified over 8 years ago
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Monday, December 2 nd
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Grades Left the Semester 1.1 more quiz 2.1 more Warm up(Daily grade) 3. Exponential Test (Test Grade) 4. Semester I Final (Final grade) 5.3 Weekly Reviews-(daily Grade)
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Weekly Review 1.We will have three weekly Reviews 2.Each will count as a Daily Grade 3.They are eligible to replace QUIZ grades
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High School GPA A: 4.0 B: 3.0 C. 2.0 D. 1.0 F-Receive no Credit. You will have to retake first semester all over again during semester II.
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Tutoring Option 1: Ms. Evans Tuesday and Thursdays Before School 6:40-7:00 After School 2:10-2:30
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Tutoring Option 2: Lunch Tuesday and Thursdays Either lunch Go to room 400 FIRST, then to lunch
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Tutoring Option 3: Algebra Department *Check Schedule in Back
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Discussion Question What’s the difference between exponential growth and exponential decay equations?!
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Growth & Decay in graph
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Growth & Decay in Equation
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Growth and Decay in Table x-2012 y2481632 x-2012 y3216842
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For compound interest annually means “once per year” (n = 1). quarterly means “4 times per year” (n =4). monthly means “12 times per year” (n = 12). Reading Math
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Write a compound interest function to model each situation. Then find the balance after the given number of years. $1200 invested at a rate of 2% compounded quarterly; 3 years. Step 1 Write the compound interest function for this situation. = 1200(1.005) 4t Write the formula. Substitute 1200 for P, 0.02 for r, and 4 for n. Simplify.
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Step 2 Find the balance after 3 years. ≈ 1274.01 Substitute 3 for t. A = 1200(1.005) 4(3) = 1200(1.005) 12 Use a calculator and round to the nearest hundredth. The balance after 3 years is $1,274.01.
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Write a compound interest function to model each situation. Then find the balance after the given number of years. $15,000 invested at a rate of 4.8% compounded monthly; 2 years. Step 1 Write the compound interest function for this situation. Write the formula. Substitute 15,000 for P, 0.048 for r, and 12 for n. = 15,000(1.004) 12t Simplify.
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Step 2 Find the balance after 2 years. ≈ 16,508.22 Substitute 2 for t. A = 15,000(1.004) 12(2) = 15,000(1.004) 24 Use a calculator and round to the nearest hundredth. The balance after 2 years is $16,508.22.
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Write a compound interest function to model each situation. Then find the balance after the given number of years. $1200 invested at a rate of 3.5% compounded quarterly; 4 years Step 1 Write the compound interest function for this situation. Write the formula. Substitute 1,200 for P, 0.035 for r, and 4 for n. = 1,200(1.00875) 4t Simplify.
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Step 2 Find the balance after 4 years. 1379.49 Substitute 4 for t. A = 1200(1.00875) 4(4) = 1200(1.00875) 16 Use a calculator and round to the nearest hundredth. The balance after 4 years is $1,379.49.
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1. The number of employees at a certain company is 1440 and is increasing at a rate of 1.5% per year. Write an exponential growth function to model this situation. Then find the number of employees in the company after 9 years. y = 1440(1.015) t ; 1646 2. $12,000 invested at a rate of 6% compounded quarterly; 15 years A = 12,000(1 +.06/4) 4t, =$29,318.64 Write a compound interest function to model each situation. Then find the balance after the given number of years.
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