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Organic Chemistry Chemistry of Carbon Compounds (except oxides, carbides, & carbonates)
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Bonding Capacity H can form only 1 bond O and S like to form 2 bonds The halogens (F, Cl, Br, I) form only 1 bond N and P form 3 bonds
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Why so many C compounds? Carbon atoms can bond with other carbon atoms in chains, rings, and networks covalentBonds are covalent
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Lewis Diagram of C C Carbon has 4 unpaired electrons so it can form 4 covalent bonds
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Properties of Covalent Substances molecular (also called molecular substances) Low melting & boiling points Poor conductors of heat & electricity May be soft or brittle Generally nonpolar – van der Waals forces Tend to dissolve in nonpolar solvents React more slowly than ionic compounds
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Chemical Formulas show kind & number of atoms CH 2 Cl 2 CH 4 CH 3 OH CH 3 Cl
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Structural Formulas Show kind & number of atoms Also show bonding patterns and approximate shapes of molecules 2-D rep of 3-D object so structural formulas aren’t totally realistic H H–C–H H
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Structural Formulas – A single line represents one pair of electrons (a single bond) = A double line represents two pairs of electrons (a double bond) ● A triple line represents three pairs of electrons (a triple bond)
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Shape 4 unpaired electrons around C atom located at the corners of a tetrahedron 109.5 apart
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Vocabulary HydrocarbonsHydrocarbons: organic compounds containing only C and H Homologous SeriesHomologous Series: – group of compounds with related structures and properties – each member of series differs from the one before it by adding one more unit
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Vocabulary Interlude Saturated SSaturated: organic compounds containing only Single bonds UnsaturatedUnsaturated: organic compounds containing one or more double or triple bonds
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Homologous Series The molecules have a fixed, numerical relationship among the numbers of atoms
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Condensed Structural Formula Shows kind & number of atoms Shows some structural information, but not all the details structural formula: H H H CCC H–C–C–C–H H H H CCC becomes: CH 3 CH 2 CH 3
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ALKANES C n H 2n+2
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Alkanes Homologous series of saturated hydrocarbons Release energy when burned CH 4 H H–C–H H C 2 H 6 H H H–C–C–H H H
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Alkanes (C n H 2n+2 ) C 3 H 8 H H H H–C–C–C–H H H H CH 3 CH 2 CH 3 Chemical Formula Structural Formula Condensed Structural Formula
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4 th straight-chain alkane C 4 H 10 H H H–C–C–C–C–H H H Or CH 3 CH 2 CH 2 CH 3
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Alkanes: base unit CH 4 CH 3 CH 3 or C 2 H 6 CH 3 CH 2 CH 3 or C 3 H 8 CH 3 CH 2 CH 2 CH 3 or C 4 H 10 CH 3 CH 2 CH 2 CH 2 CH 3 or C 5 H 12 CH 2 Difference between each is CH 2
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Naming straight-chain Alkanes Name describes molecule so you can draw it aneaneAll alkanes have the suffix –ane The prefix depends on the number of C’s
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10Dec 9Non 8Oct 7Hept 6Hex 5Pent 4But 3Prop 2Eth 1Meth # of C atomsPrefix
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C 5 H 12 C 4 H 10 C3H8C3H8 C2H6C2H6 Meth + ane CH 4 NameFormulaEthanePropane Butane Pentane
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Properties of Alkanes Change systematically with number of C’s As the number of C’s increases, the boiling point increases –The molecules get heavier & harder to change into the gas phase
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Properties of Alkanes Low Reactivity Except readily undergo combustion – fuels Nonpolar – Don’t dissolve well in water Low melting pts & boiling pts. (M.P. & B.P. increase with molecular mass) High vapor pressures
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A.Low melting point B.High melting point C.Soluble in polar solvents D.Insoluble in nonpolar solvents Which property is generally characteristic of an organic compound? Correct response = A
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A.CH 4 B.C 2 H 6 C.C 3 H 8 D.C 4 H 10 Which of the following compounds has the highest boiling point? Correct answer = D nonpolar coval cmpd: Bp depends on the strength of the van der Waals interactions (van der Waals forces ↑ as size of molecule ↑ - bigger molecule = bigger electron cloud)
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Branched-chain alkanes Beginning with butane, C 4 H 10, there is more than 1 way to arrange the atoms H H–C–H H H–C–C–C–H H H H
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Branched alkane: can’t link all the C’s without lifting pencil off paper Methyl propane
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Isomers Compounds with same molecular formula but different structural arrangement The more C atoms there are the more isomers can have more possible ways to arrange them
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Isomers Different structures, different propertiesDifferent structures, different properties Isomers have different chemical and physical properties
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A note about isomers --- If you are comparing 2 structural formulas & you can superimpose them, they are not isomers – they are the same molecule! If you can rotate or flip one of the structural formulas & then superimpose it on the other one, they are not isomers – they are the same molecule!
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? same
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Naming Branched-Chain Alkanes The goal of the name is to describe the molecule so you can draw it
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Naming branched-chain alkanes longest continuous chainFind longest continuous chain of C atoms –Bends don’t count! base namebase name derived from # of C’s in the continuous chain BranchesfirstBranches named first “yl” at end –count # C atoms & add “yl” at end assigning # to C attached to in the backbone# location of the branch by assigning # to C attached to in the backbone –# C's so get lowest number for branch more than one of the same type of branch: Use di, tri, etc.
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H H–C–H H H–C–C–C–H H H H methyl Branch has 1 carbon – methyl Branch has to be at C-2 (Only give the number if necessary) Methyl propane C 4 H 10 CH 3 CH(CH 3 )CH 3 propane Longest continuous chain has 3 carbon atoms – propane
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H H–C–H H H H H–C–C–C–C–H H H H H–C–H H Longest continuous chain has 6 hexane carbon atoms: it’s a hexane methyl Branch is 1 carbon long – methyl 2 Branch is located at C-2 2-methyl hexane C 7 H 16 CH 3 CH(CH 3 )CH 2 CH 2 CH 2 CH 3
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A note about branches If you have several branches with the same # of C atoms, you can condense the name a little 2-methyl 3-methyl pentane becomes: –2,3-dimethyl pentane
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H H – C – H H H H H – C – C – C – C – H H H H–C–H H–C–H H H Longest continuous chain has 6 carbon atoms: hexane Branch is 1 carbon long: methyl Branch is located at C-3 3-methyl hexane C 7 H 16 CH 3 CH 2 CH 2 CH(CH 3 )CH 2 CH 3 CH 3 (CH 2 ) 2 CH(CH 3 )CH 2 CH 3
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Alkenes hydrocarbonsAnother homologous series of hydrocarbons one unsaturatedEach member contains at least one double covalent bond between C atoms So alkenes are unsaturated General formula = C n H 2n
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Naming Alkenes Names: # of C’s in parent chain gives prefix Suffix = -ene 1 st member is C 2 H 4: ethene H H C=C H H Alkenes with 4 or more C’s: Use # to show which C attached to
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Naming Alkenes Number C atoms in backbone & give double bond the lowest possible number H H H C=C–C–C–H H H C 4 H 8 CH 2 CHCH 2 CH 3 H H H H H–C–C=C–C–H H H C 4 H 8 CH 3 CHCHCH 3 1-butene 2-butene
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Naming Branched-Chain Alkenes Parent chain = longest chain that contains the double bond Also, position of double bond, not branches, determines numbering of backbone Give 1 st C in bond lowest possible #
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Properties of Alkenes Nonpolar – low solubility in H 2 O Fairly low M.P. & B.P. More reactive than alkanes : –double bond = site of reactivity
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Alkynes Homologous series of unsaturated hydrocarbons that contain one triple bond Each member contains one C≡C bond –Alkynes are unsaturated General formula = C n H 2n-2
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Naming Alkynes Name: Prefix depends on # of C’s –Suffix = yne If necessary, number the 1 st carbon atom at which the triple bond occurs
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H–C C–HC 2 H 2 ethyne CHCH H H–C C–C–H H H H H–C C–C–C–H H H H–C–C C–C–H H H C3H4C3H4 propyne CHCCH 3 C4H6C4H6 1-butyne CHCCH 2 CH 3 C4H6C4H6 2-butyne CH 3 CCCH 3
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3 Homologous Series of HC’s -yneC n H 2n-2 Alkynes -eneC n H 2n Alkenes -aneC n H 2n+2 Alkanes EndingGeneral FormulaName of Series
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A.C 2 H 2 B.C 2 H 4 C.C 6 H 6 D.C 6 H 14 Which compound belongs to the alkene series? Correct answer = B. Alkenes follow the format C n H 2n A & C are C n H n, D is C n H 2n+2
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A.C 2 H 2, C 2 H 4, C 2 H 6 B.C 2 H 4, C 3 H 4, C 4 H 8 C.C 2 H 4, C 2 H 6, C 3 H 6 D.C 2 H 4, C 3 H 6, C 4 H 8 In which group could the hydrocarbons all belong to the same homologous series? Correct answer = D Members of homologous series all have same relationship between atoms Every compound in set D fits the formula C n H 2n
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A.Ethene B.Ethyne C.Propene D.Propane Which of the following is a saturated hydrocarbon? Correct answer = D The alkanes are saturated
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