2. Bellwork: Fri. Jan. 8, 2016 In seals, the gene for the length of the whiskers is controlled by a single gene. The dominant allele (W) codes long whiskers & the recessive allele (w) codes for short whiskers. If a homozygous dominate male seal and homozygous recessive female seal mate, what is the probability that their pups will have long whiskers? Draw a Punnett Square indicate the cross: ______ X ______ and show the: genotypic ratio:______:______ phenotypic ratio:_____:______

4. End Show 11–3 Exploring Mendelian Genetics Slide 3 of 31 More on Genetics

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15. https://www.youtube.com/watch?v=-Vb-qGOJxlA

16. NOTES: Probabilities predict the average outcome of a large number of events. Probability cannot predict the precise outcome of an individual event! In genetics, the larger the number of offspring, the closer the resulting numbers will get to expected values. Probabilities Predict Averages

17. Genotype Phenotype (Physical) –Physical characteristics Genotype (Genetic) –Genes we inherit from our parents. “Gene” make-up.

18. Phenotype –Eyes –Smile –Ears –Nose –Facial structure –Neck Notice the similarities:

19. "No one ever believes we are twins because I am white and Maria is black," - Lucy

20. law of segregation : when gametes are made, each member of allele pair separates from the other member to form the genetic make-up of the gamete (monohybrid cross: ) NOTES

21. Independent Assortment: To determine if the segregation of one pair of alleles affects the segregation of another pair of alleles in a two- factor cross. (dihybrid cross)

22. The Test Cross For example, what if you have a rabbit with black hair and want to know if it is homozygous dominant or heterozygous? What if you want to figure out an unknown genotype of an organism with a dominant phenotype?

23. Mendel realized that it is possible to find the genotype of an organism simply by crossing. This does not require modern technology.

24. Test Cross: crossing an organism with an unknown genotype and dominant phenotype with a homozygous recessive organism to determine the unknown genotype.

25. Is it YY or Yy? (both “appear” yellow) To identify the genotype of yellow- seeded pea plants as either homozygous dominant (YY) or heterozygous (Yy), you could do a test cross with plants of genotype _______. Phenotype

26. If the unknown genotype is homozygous dominant (YY)… The offspring will ALL have a yellow phenotype.

27. If the unknown genotype is heterozygous (Yy)… Half of the offspring will be yellow and half will be green.

28. So if we take our black rabbit (unknown genotype) and cross it with a brown rabbit (homozygous recessive genotype) we get: B? x bb bb BBb ??b?b?b?b If the unknown genotype is homozygous dominant, what results would you expect from the offspring?

29. So if we take our black rabbit (unknown genotype) and cross it with a brown rabbit (homozygous recessive genotype) we get: BB x bb bb BBb BBbBbBbBb ALL of the offspring will be black.

30. So if we take our black rabbit (unknown genotype) and cross it with a brown rabbit (homozygous recessive genotype) we get: B? x bb bb BBb ??b?b?b?b If the unknown genotype is heterozygous, what results would you expect from the offspring?

31. Example only not in notes 2013 In fruit flies, the allele W for long wings is dominant over the allele w for short wings. Calculate the probability of heterozygous offspring resulting from a cross between two homozygous recessive parents. Cross: ____ x _____ (looking for Ww “baby” flies) Genotypic ratio: Phenotypic ratio: Probability: All ww  4:0 All short-winged: 4:0 P(Ww) = 0 Ww = 0 = 0%

32. In fruit flies, the allele W for long wings is dominant over the allele w for short wings. Calculate the probability of long-winged offspring resulting from a cross between a heterozygous parent and a homozygous recessive parent. Cross: _____ x ______ Genotypic ratio: Phenotypic ratio: Probability: 2 Ww and 2 ww, so 0:2:2 2 long-winged and 2 short-winged, so 2:2 P(WW or Ww)= 2/4 = 0.5 = 50%

33. The Dihybrid Cross: cross involving two sets of traits (alleles) – a monohybrid cross involves one set of traits (alleles)

34. Genotypic Ratio: Phenotypic Ratio:

36. Genotypic Ratio: RRYY: RRYy: RRyy: RrYY: RrYy: Rryy: rrYY: rrYy: Rryy: 1:1:2:2:4:2:2:1:1 Phenotypic Ratio: Round Yellow Round Green Wrinkled Yellow Wrinkle Green 9:3:3:1

37. A Summary of Mendel's Principles Genes are passed from parents to offspring. There are dominant and recessive alleles. Allele pairs from each parent separate in gamete formation: law of segregation. Genes for different traits (on different chromosomes) can segregate independently during the formation of gametes: independent assortment. Genes that segregate independently do not influence each other's inheritance. alleles for different genes usually segregate independently of one another unless they are on the same chromosome

38. Mendel didn’t know about Chromosomes or DNA We now know that genes located close together on a chromosome may be inherited together http://www.google.com/imgres?imgurl=http://www.schenectady.k12.ny.us/putman/biology/data/images/inheritance/5vtxrn.gif&imgrefurl=http://www.schenectad y.k12.ny.us/putman/biology/data/inheritance/vertical5.html&usg=__AOM- Msycdjh3B4VDEsYOV75bXAs=&h=383&w=374&sz=7&hl=en&start=21&zoom=1&tbnid=RD2sZ4MpKWVDFM:&tbnh=123&tbnw=120&ei=RzIHT4qDF4qEsAK 3tpyRCg&prev=/search%3Fq%3DLinked%2BGenes%26um%3D1%26hl%3Den%26safe%3Dactive%26sa%3DN%26gbv%3D2%26rlz%3D1R2GGLL_en%26tb m%3Disch&um=1&itbs=1

39. Copyright Pearson Prentice Hall

40. https://www.youtube.com/watch?v=G3LLt ZUdpvA&list=PLD2bkg3sRPUOjPf9Du8tS 48vhan5dNi0L&index=89https://www.youtube.com/watch?v=G3LLt ZUdpvA&list=PLD2bkg3sRPUOjPf9Du8tS 48vhan5dNi0L&index=89

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42. But… some alleles aren’t completely dominate or recessive

43. Bellwork: Tues. Jan 13, 2015 Show a cross between two heterozygous guinea pigs. What % of the offspring will have short hair? ________ What %of the offspring will have long hair? _______ Two short haired guinea pigs are mated several times. Out of 100 offspring, 25 of them have long hair. What are the probable genotypes of the parents? ________ x ___________ Short hair is dominant long hair is recessive

44. Incomplete & Codominance

45. Incomplete Dominance: when one allele is not completely dominant over another. The heterozygous phenotype is a “mix of the two homozygous phenotypes. A cross between red (RR) and white (WW) four o’clock plants produces pink-colored flowers (RW).

47. Incomplete dominance – when one allele is not completely dominant over the other allele WW = White RR = Red WW X RR RW = Pink Genotypic Ratio:__________ Phenotypic Ratio:_________

48. What happens if you cross the offspring (F 1 ) generation? RW x RW Genotypic ratio Phenotypic Ratio Phenotypic Ratio: Genotyopic Ratio:

49. Is a lot like incomplete dominance - A hybrid organism shows a third phenotype --- not the usual dominant versus recessive traits. BUT in codominance both traits show up AT THE SAME TIME!! Codominance

50. Co-dominance: when both alleles contribute to the phenotype. A cross of black chicken (BB) with a white chicken (WW) produces all speckled offspring (BW). BB = black feathers BW = black and white feathers WW = white feathers Genotypic Ratio: Phenotypic Ratio:

51. Or…. Roan coat color in horses and cows.

52. Co-dominance : Roan fur. Cattle can be o red (RR = all red hairs), o white (rr = all white hairs), or o roan (Rr = red & white hairs together). Notice how this cross looks just like the others we have done earlier with dominant and recessive alleles – I would have to tell you this is a co- dominant cross!!!. Cross: ______ X _______ Genotypic Ratio:_____________ Phenotypic Ratio:____________

53. Now let’s cross two roans: Cross:_____ X______ Genotypic Ratio: Phenotypic Ratio:

54. roan horses

55. https://www.youtube.com/watch?v=YJHG fbW55l0https://www.youtube.com/watch?v=YJHG fbW55l0

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57. Bellwork: Thurs. Jan. 13, 2011 Dihybrid: 2-Factor Cross: First Generation: F 1 Mendel crossed true-breeding plants that produced round yellow peas (genotype RRYY) with true-breeding plants that produced wrinkled green peas (genotype rryy): Cross: RRYY x rryy (R) = Round seeds (r) = wrinkled seeds (Y) = Yellow seeds (y) = green seeds Genotypic Ratio: ______________ Phenotypic Ratio: ______________

58. The Punnett square predicts a Genotypic Ratio: 1:1:2:2:4:2:2:1:1 Phenotypic Ratio: 9:3:3:1 F 2 Represents: Independent Assortment

59. Brown Hair (B) Blonde Hair (b) Bellwork: Thurs. Jan. 8, 2015 Cross a female with blonde hair to a male with heterozygous brown hair: 1 st, write the cross: ________ x ________ Genotypic ratio:_____________ Phenotypic ratio:_____________ What % will have blonde hair?______ What % will have brown hair?______ What fraction will have brown hair?___ What fraction will have blonde hair? ___ YES!!! Write all of the RED words & punnett square!!!!!!

60. Bellwork: Mon???. Jan. 20??, 201? Dihybrid: 2-Factor Cross: First Generation: F 1 Mendel crossed true-breeding plants that produced round yellow peas (genotype RRYY) with true-breeding plants that produced wrinkled green peas (genotype rryy): Cross: RRYY x rryy (R) = Round seeds (r) = wrinkled seeds (Y) = Yellow seeds (y) = green seeds Genotypic Ratio: ______________ Phenotypic Ratio: ______________

61. Bellwork: Mon. Jan. 9, 2012 Mendel crossed true-breeding plants that produced round yellow peas (genotype RRYY) with true-breeding plants that produced wrinkled green peas (genotype rryy): Set up the Punnet Square for this cross: RRYY x rryy