1. Projectile Motion Chapter 3 Section 3

2. What is Projectile Motion? Projectile Motion – Motion that is launched into the air that is subject to gravity and described in two dimensions. Projectile Motion – Motion that is launched into the air that is subject to gravity and described in two dimensions. Examples of projectiles: Examples of projectiles: –baseballs –footballs –bullets –arrows –etc….

3. How to describe Projectiles Projectile Motion is motion in 2- dimensions. Projectile Motion is motion in 2- dimensions. When solving for problems dealing with 2- dimensional motion, it is best to break the motion into 1-dimensional parts When solving for problems dealing with 2- dimensional motion, it is best to break the motion into 1-dimensional parts –(Vertical and Horizontal) Once solved in 1-dimensional, recombine the components to find the final resultant. Once solved in 1-dimensional, recombine the components to find the final resultant.

4. Components of Projectiles Breaking projectile motion in to components can greatly simplify the problem. Breaking projectile motion in to components can greatly simplify the problem. –Motion can be described in the x-direction and the y-direction. Vx VyV

5. Kinematic Equations The kinematic equations are still used to solve for projectile motion and are applied in one dimension at a time. The kinematic equations are still used to solve for projectile motion and are applied in one dimension at a time. The setup is the same, but different variables are used to help expression the motion in the x- and y-directions… The setup is the same, but different variables are used to help expression the motion in the x- and y-directions…

6. Kinematic Variable

7. Trajectories Objects that are in a projectile motion follow parabolic trajectories Objects that are in a projectile motion follow parabolic trajectories –Figure 3-18 pg 99 in book shows a great example…

8. Horizontal Motion of Projectiles Objects that have an initial horizontal velocity retain that velocity as the objects continues in its parabolic trajectory. Objects that have an initial horizontal velocity retain that velocity as the objects continues in its parabolic trajectory. Example: Example: –If a person runs off a cliff with a velocity of 20m/s, that person will continue to move at 20m/s horizontally as the person falls to the ground below. Horizontal velocity is considered a constant in projectile problems. Horizontal velocity is considered a constant in projectile problems.

9. Vertical Motion of Projectiles As an object is in projectile motion, it continues to have gravity acting on it and falls towards the earth at an acceleration of 9.8m/s² straight downward. As an object is in projectile motion, it continues to have gravity acting on it and falls towards the earth at an acceleration of 9.8m/s² straight downward. Projectile motion is nothing more than free fall with an initial horizontal velocity. Projectile motion is nothing more than free fall with an initial horizontal velocity. –Figure 3-19 pg 99 in book

10. Kinematic Equations for Projectile Motion

11. Impact Velocity and Speed

12. Projectiles Launched at an Angle Projectiles are mostly launched at some angle to the horizontal in real-world application. Projectiles are mostly launched at some angle to the horizontal in real-world application. –Examples  Bullets  Footballs  Baseballs The projectile has an initial vertical component of velocity as well as a horizontal component of velocity. The projectile has an initial vertical component of velocity as well as a horizontal component of velocity.

13. Maximum Range To achieve maximum range of a projectile, it should be fired at a 45 degree angle to the horizontal. To achieve maximum range of a projectile, it should be fired at a 45 degree angle to the horizontal.

14. Projectile Cases There are 3 different cases in which a projectile can be described. There are 3 different cases in which a projectile can be described. –Case 1: Object with only horizontal velocity and no vertical velocity falling with negative vertical displacement. –Case 2: Object that is shot upward at some angle and has both horizontal and vertical velocity and lands with zero vertical displacement. –Case 3: Object that is shot at some angle and has both horizontal and vertical velocity with negative or positive vertical displacement.

15. Case 2 Equations With some algebra and trigonometry, the kinematic equations can be rearranged to solve for certain situations. With some algebra and trigonometry, the kinematic equations can be rearranged to solve for certain situations.

16. Special Case 2 Equations

17. Vector Diagram V ix V iy ViVi θ

18. Finding the Components

19. Example Problem #1 A car is traveling at 37.0 km/hr on a perfectly horizontal road when it suddenly loses control and runs off a cliff which is 17.30 meters tall. How far did the car travel before crashing into the ground below the cliff? A car is traveling at 37.0 km/hr on a perfectly horizontal road when it suddenly loses control and runs off a cliff which is 17.30 meters tall. How far did the car travel before crashing into the ground below the cliff?

20. Example Problem #1 Answer dx = 19.33m dx = 19.33m

21. Example Problem #2 A quarterback throws a football with a velocity of 27.50m/s at an angle of 35 degrees above the horizontal. A quarterback throws a football with a velocity of 27.50m/s at an angle of 35 degrees above the horizontal. a)What is the maximum height? b)What is the maximum range? c)How long is the football in the air? d)What is the impact speed of the football hitting the ground?

22. Example Problem #2 Answer a) 12.69 m b) 72.52 m c) 3.22 s d) 52.42 m/s

23. Example Problem #3 A person throws a ball with a velocity of 23.40 m/s at 55 degrees above the horizontal to a friend on top of a small building, which is 21.70 m tall. If the person is standing 24.0 meters away from the building on the ground, will the ball make it over the top of the building and onto the roof? A person throws a ball with a velocity of 23.40 m/s at 55 degrees above the horizontal to a friend on top of a small building, which is 21.70 m tall. If the person is standing 24.0 meters away from the building on the ground, will the ball make it over the top of the building and onto the roof?

24. Example Problem #3 Answer No, the ball does not make it to the top of the roof. The ball only goes 18.61m high and the building is 21.70m tall. No, the ball does not make it to the top of the roof. The ball only goes 18.61m high and the building is 21.70m tall.

25. Example Problem #4 In a scene in a action movie, a stuntman jumps from the top of one building to the top of another building 4.0m away. After a running start, he leaps at an angle of 15º with respect to the flat floor while traveling at a speed of 5.0m/s. Will he make it to the other roof, which is 2.5m shorter than the building he jumps from? In a scene in a action movie, a stuntman jumps from the top of one building to the top of another building 4.0m away. After a running start, he leaps at an angle of 15º with respect to the flat floor while traveling at a speed of 5.0m/s. Will he make it to the other roof, which is 2.5m shorter than the building he jumps from?

26. Example Problem #4 Answer 4.13 m jump across the buildings 4.13 m jump across the buildings Yes, he makes the jump. Yes, he makes the jump.