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 To balance remember that the sum of the mass numbers (superscripts) and the sum of the atomic numbers (subscripts) on each side of the arrow are equal.

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Presentation on theme: " To balance remember that the sum of the mass numbers (superscripts) and the sum of the atomic numbers (subscripts) on each side of the arrow are equal."— Presentation transcript:

1  To balance remember that the sum of the mass numbers (superscripts) and the sum of the atomic numbers (subscripts) on each side of the arrow are equal  When a radioactive nucleus emits a beta particle,  the product nucleus has an atomic number that increases by 1 and a mass number that does not change  The beta particle ( 0 -1 e ) is written as a product  When a radioactive nucleus captures a beta particle,  The product nucleus has an atomic number that decreases by 1 and a mass number that does not change  The beta particle ( 0 -1 e ) is written as a reactant

2  If carbon – 14 undergoes beta decay what will the products be? C  ___ + e 14 Must be an beta particle!!! 6 0

3  If carbon – 14 undergoes beta decay what will the products be? C  ___ + e 14 To solve for this Mass # we need to remember that the Mass # of reactants = Mass # of products 14 = x + 0 x = 14 6 0 14

4  If carbon – 14 undergoes beta decay what will the products be? C  ___ + e 14 To solve for this Atomic # we need to remember that the Atomic # of reactants = Atomic # of products 6 = x + -1 x = 7 6 0 14 7

5  If carbon – 14 undergoes beta decay what will the products be? C  ___ + e 14 6 0 14 7 What element is this? Look at the atomic number here and then find it on your periodic table N

6  If Nickel captures a beta particle what will be its product? Ni + e  ___ Mass # of reactants = Mass # of products 59 = 0 + x X = 59 0 59 28 __ 59

7  If Nickel captures a beta particle what will be its product? Ni + e  ___ 0 59 28 __ 59 Atomic # 28 + -1 = 27 27

8  If Nickel captures a beta particle what will be its product? Ni + e  ___ 0 59 28 __ 59 27 What element is this? Look at the atomic number here and then find it on your periodic table Co


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