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Published byCory Wheeler Modified over 8 years ago
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Intramolecular Forces Forces (chemical bonds) within a molecule Typical value: 350 kJ/mol C-C bond Intermolecular Forces Forces between molecules Typical value: 20 kJ/mol H-bond 1 kJ/mol van der Waals
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Dipole-dipole Forces If present usually dominate intermolecular interactions.
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Water Held together by O-HH hydrogen bonds
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Hydrogen bond donors: O-H, N-H, S-H, X-H Hydrogen bond acceptors: O, N, X, S For example: The amide hyrdrogen bond is the dominate intermolecular force in proteins.
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London Dispersion Forces or van der Waals Forces
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G vap = H vap - T S vap What determines the B.P. of a liquid? = 0 at the B.P. H vap = T S vap For simple liquids, all s vap values are about the same. So B.P. is proportional to H vap
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Four General Classifications for Solids 1. Metals Fe, Co, Ag 2. Covalent Network Solids Diamond, SiO 2 3. Ionic Solids NaCl ZnS 4. Molecular Solids I 2 Sugar
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Bragg’s Law
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Determination of Crystal Structures using X-Ray diffraction. Diffraction of any wave will take place when you have a grid with a spacing similar to the wavelength of the wave. X-Rays have wavelengths on the order of 1 Ångstrom. Typical value 0.71Å
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Four General Classifications for Solids 1. Metals Fe, Co, Ag 2. Covalent Network Solids Diamond, SiO 2 3. Ionic Solids NaCl ZnS 4. Molecular Solids I 2 Sugar
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Close Packing of Spheres
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Hexagonal Close Packed Co, Ti, Mg
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Body Centered Cubic Fe, Cr, V
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Cubic Close Packed - Face Centered Cubic Ni, Cu, Au
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Efficiency of Close Packing What fraction of the volume is occupied? f v = volume spheres in unit cell / volume of cell f v = = 0.740
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The radius of Ag atom is 1.44 Å. Calculate the density. The Ag structure is fcc (ccp).
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=
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Close packing of spheres fills 0.74 % of the available space The remaining space can be allotted to three types of holes that occur between the spheres.
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r tet = 0.225 r oct = 0.414 r cub = 0.732
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Sodium Chloride Na +.95 Å Cl - 1.81Å Table 13.7 Ratio =.95 / 1.81 =.52 r tet = 0.225 r oct = 0.414 r cub = 0.732
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Zinc Sulfide Ratio = Zn +2 /S -2 =.35 r tet = 0.225 r oct = 0.414 r cub = 0.732 The Zinc atoms occupy 1/2 of the tetrahedral holes
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Glass Quartz
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Molecular Solids C 60
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Iodine I 2
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Acetylene HCCH
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Oxalic Acid
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G = H - T S = - RT ln K ln K = -( H/R) /T + S/R ln P = -( H/R)(1/T) + S/R P
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Triple point 4.588 torr 0.0098°C
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