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ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical.

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1 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 1 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 25 Tutorial: QtrCirc Submerged Dam

2 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 2 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics Problem  Determine the Resultant Point-Force and its Location on the Dam Face (Center of Pressure) that are Equivalent to the Water Pressure acting on ¼-Circle Surface AB

3 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 3 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

4 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 4 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics MATLAB Code % Bruce Mayer, PE % ENGR36 07Dec14 % ENGR36_Submerged_Dam_1412.m % clear; clf; clc; % G = 62.4; r = 6; b = 10; Rx = 3*G*r*b K = 1-pi/4; Ry = G*r^2*b*K Fs = 3*G*r*b FB = 6*G*r*b W = pi*G*b*r^2/4 SumM = @(u) FB*r/2 + Rx*sqrt(r^2- u.^2) - Fs*r/3 - 4*W*r/(3*pi) - Ry*u fplot(SumM,[0,6]), grid R = norm([Rx,Ry]) T = sqrt(1/(1+4*K^2)) X = r*T Y = sqrt(r^2 - X^2)

5 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 5 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

6 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 6 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

7 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 7 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

8 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 8 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

9 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 9 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

10 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 10 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

11 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 11 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

12 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 12 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

13 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 13 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics MuPAD integration int(cos(q), q) int(sin(u)*cos(u), u) Fx = int(cos(z), z=0..PI/2)- int(sin(z)*cos(z), z=0..PI/2) int(sin(q), q) int(sin(u)*sin(u), u) Fy = int(sin(z), z=0..PI/2)- int(sin(z)*sin(z), z=0..PI/2)

14 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 14 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

15 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 15 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

16 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 16 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

17 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 17 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

18 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 18 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

19 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 19 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

20 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 20 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics

21 ENGR36_Flat_n_Belt_Friction_Balance_H13e_P8_133.pptx 21 Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics


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