1. Avogadro’s Principle: The partial pressures, volumes and #moles of gases in the same container and at the same temperature are proportional to their reaction coefficients. 3 H 2 (g) + N 2 (g)  2 NH 3 (g) 2.5 mol7.5 mol5.0 mol 3 atm1 atm 2 atm 3xx2x 30 L 90 L 60 L Ex C: 5.0 mol of ammonia were formed. How many moles of nitrogen and hydrogen were used? Ex B: 90 L of hydrogen were used. How many liters of nitrogen were also used? How many liters of ammonia were formed? Ex A: The final partial pressure of ammonia is 2 atm. What were the partial pressures of the nitrogen and hydrogen that reacted?

2. Avogadro’s Principle: The partial pressures, volumes and #moles of gases in the same container and at the same temperature are proportional to their reaction coefficients. 3 H 2 (g) + N 2 (g)  2 NH 3 (g) 3xx2x Ex D: The final partial pressure of ammonia is 1 atm. How many grams of hydrogen reacted if the reaction is done in a 1.0 L flask at 25°C? Step 1: Find the partial pressure of hydrogen. 1 atm 1.5 atm Step 2:Use the ideal gas law to solve for the number of moles of hydrogen. PV = nRT  (1.5 atm)(1.0L) = n(0.0821 L-atm)(298K)n = 0.0613 mol Step 3: Multiply the moles by gfm to get grams. (0.0613 mol)(2.015 g/mol) =0.124 g of H 2 gas were needed for the reaction

3. 1. If 2.5 L of methane (CH 4 ) are reacted with oxygen, how many liters of carbon dioxide (CO 2 ) will be formed? ___CH 4 (g) + ___O 2 (g)  ___CO 2 (g) + ___H 2 O (g) 1221 2.5 L xx2x 2.5 L 2. How many liters of oxygen are needed to react with the methane in question 1? 5.0 L 3. How many liters of water vapor will be formed from the combustion of 2.5 L of methane? 5.0 L A: 2.5 L of CO 2 will be formed A: 5.0 L of O 2 are needed for the reaction A: 5.0 L of H 2 O will be formed

4. 1221 xx2x ___CH 4 (g) + ___O 2 (g)  ___CO 2 (g) + ___H 2 O (g) 4. If 2 atm of methane gas are reacted with oxygen, what will the pressures of carbon dioxide and water vapor be after the reaction is complete? 2 atm 4 atm 5. How many atm of oxygen will be needed to react with the 2 atm of methane in question #4? 4 atm A: 2 atm of CO 2 and 4 atm of water vapor will be formed A: 4 atm of oxygen will be needed for the reaction