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Published byHolly Holland Modified over 8 years ago
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The Temperature-Pressure Relationship Gay-Lussac’s Law The pressure of a gas is directly proportional to the temperature of a gas Temperature goes up; pressure goes up P 1 = P 2 T 1 T 2 The pressure of a gas is directly proportional to the temperature of a gas Temperature goes up; pressure goes up P 1 = P 2 T 1 T 2
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Gay-Lussac’s Law example problems The gas left in a used aerosol can is at a pressure of 103 kPa at 25 o C. If the can is thrown into a fire, what is the pressure of the gas when it reaches 928 o C? 103 kPa = P 2 298 K 1201 K P 2 = 415 kPa The gas left in a used aerosol can is at a pressure of 103 kPa at 25 o C. If the can is thrown into a fire, what is the pressure of the gas when it reaches 928 o C? 103 kPa = P 2 298 K 1201 K P 2 = 415 kPa
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Gay-Lussac’s Law example problems Your turn A container of propane has a pressure of 108.6 kPa at a morning temperature 15 o C. By mid afternoon the temperature has reached 32 o C. What is the pressure inside the propane tank? Your turn A container of propane has a pressure of 108.6 kPa at a morning temperature 15 o C. By mid afternoon the temperature has reached 32 o C. What is the pressure inside the propane tank?
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Gay-Lussac’s Law example problems Answer 108.6 kPa = P 2 288 K305 K P 2 = 115 kPa Answer 108.6 kPa = P 2 288 K305 K P 2 = 115 kPa
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The combined gas law P 1 x V 1 = P 2 x V 2 T 1 T 2 P 1 x V 1 = P 2 x V 2 T 1 T 2
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The combined gas law example problem The volume of a gas-filled balloon is 30.0 L at 40 o C and 153 kPa. What volume will the balloon have at STP? 153 kPa x 30.0 L = 101.3 kPa x V 2 313 273 V 2 = 3.95 L The volume of a gas-filled balloon is 30.0 L at 40 o C and 153 kPa. What volume will the balloon have at STP? 153 kPa x 30.0 L = 101.3 kPa x V 2 313 273 V 2 = 3.95 L
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The combined gas law example problem Your turn A gas-filled balloon is 25.0 L at 35 o C and 145 kPa. What is the temperature if the volume increases to 28 L and a pressure of 152 kPa? Your turn A gas-filled balloon is 25.0 L at 35 o C and 145 kPa. What is the temperature if the volume increases to 28 L and a pressure of 152 kPa?
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The combined gas law example problem Answer 145 kPa x 25.0 L = 152 kPa x 28 L 308 K T 2 T 2 = 362 K = 88.6 o C Answer 145 kPa x 25.0 L = 152 kPa x 28 L 308 K T 2 T 2 = 362 K = 88.6 o C
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