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RC Circuits Physics 102 Professor Lee Carkner Lecture 16
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Series and Parallel V = 6 for each branch so I 2 = V/R = 6/6 = 1 A and I 3 = V/R = 6/10 = 0.6 A Equivalent resistance total: 1/R eq = 1/6 +1/10, R eq = 3.75 so I 1 = I eq = V/R eq = 6/3.75 = 1.6 A through battery ( V=6) + - V = 6 V 10 4 6 I1I1 I3I3 I2I2
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Kirchhoff’s Rules Left loop: 6 - 6I 2 = 0 Right loop: 6I 2 - 6I 3 - 4I 3 = 0 I 1 = I 2 +I 3 Voltage: For battery V = 6 V, for 6 , V = 6I 2 = 6 V, for 2nd 6 , V = 6I 3 = 3.6 V, for 4 , V = 4I 3 = 2.4V + - V = 6 V 4 6 I1I1 I3I3 I2I2
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Kirchhoff Tips Find the currents Each single branch has a current Indicate current direction Apply junction rule Currents in equal currents out
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More Kirchhoff Tips Apply the loop rule Sum of all V equal to zero From - to + terminal the V is equal to + Moving with the current the V is - IR Solve equations Need as many equations as unknowns Check your work
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Today’s PAL Use Kichhoff’s rules to find the current through each resistor
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Capacitance The value of C depends on its physical properties: C = 0 A/d How can we combine capacitors in circuits?
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Simple Circuit Battery ( V) connected to capacitor (C) The capacitor experiences potential difference of V and has stored charge of Q = C V +- + - VV C Q
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Capacitors in Parallel Potential difference across each is the same ( V) But: Q 2 = C 2 V The equivalent capacitance is: C eq = C 1 + C 2 +- VV C1C1 C2C2
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Capacitors in Series Charge stored by each is the same (Q) Equivalent capacitor also has a charge of Q Since V = Q/C: The equivalent capacitance is: 1/C eq = 1/C 1 + 1/C 2 +- VV C1C1 C2C2 + -- +
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Capacitors in Circuits Remember series and parallel rules extend to any number of capacitors Keep simplifying until you find the equivalent capacitance for the whole circuit
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Resistors and Capacitors If you add a resistor to a charged capacitor, the capacitor will discharge through it If we charge a capacitor with a resistor in the circuit, it will also take time for the capacitor to fully charge = RC This is the time to charge a capacitor to about 63% of the final value
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Charging a Capacitor
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Charge on the Capacitor We can write an expression for the charge on a capacitor: Q(t) = C [1-e (-t/ ) ] Capacitor charges rapidly at first and then the rate of charge separation slows At about t = 4 the capacitor is nearly fully charged
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Time Curve
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Meters We use meters to measure current, resistance, capacitance, voltage, etc. Want to minimize their effect
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Using an Ammeter
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Using a Voltmeter
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Types of Meters Ammeter Must be placed in series Voltmeter Must be placed in parallel
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Next Time Read 22.1-22.2 Homework Ch 21, P: 29, Ch 22, P: 2 Final: Section 1: Tuesday, Feb 25, 9-11 am Section 2: Thursday, Feb 27, Noon-2pm
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