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How to find the lengths of segments. Chapter 1.5GeometryStandard/Goal 2.2
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1. Check and discuss assignment from yesterday. 2. Work on Quiz 1.1-1.3. 3. Read, write, and discuss how to find lengths of segments. 4. Work on assignment.
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The points of a line can be put into one-to-one correspondence with the real numbers so that the distance between any two points is the absolute value of the difference of the corresponding numbers.
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coordinate is its distance and direction from the origin of a number line. Congruent segments is two segments with the same length. Example:
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Use the Ruler Postulate to find the length of each segment. XY = | –5 – (–1)| = | –4| = 4 ZY = | 2 – (–1)| = |3| = 3 ZW = | 2 – 6| = |–4| = 4 Find which two of the segments XY, ZY, and ZW are congruent. Because XY = ZW, XY ZW.
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If three points A, B, and C are collinear and B is between A and C, Then AB + BC = AC
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Use the Segment Addition Postulate to write an equation. AN + NB = AB Segment Addition Postulate (2 x – 6) + ( x + 7) = 25 Substitute. 3 x + 1 = 25Simplify the left side. 3 x = 24Subtract 1 from each side. x = 8Divide each side by 3. AN = 10 and NB = 15, which checks because the sum of the segment lengths equals 25. If AB = 25, find the value of x. Then find AN and NB. AN = 2 x – 6 = 2(8) – 6 = 10 NB = x + 7 = (8) + 7 = 15 Substitute 8 for x.
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midpoint of a segment is a point that divides the segment into two congruent segments. ACB
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Use the definition of midpoint to write an equation. RM = MT Definition of midpoint 5 x + 9 = 8 x – 36Substitute. 5 x + 45 = 8 x Add 36 to each side. 45 = 3 x Subtract 5 x from each side. 15 = x Divide each side by 3. RM and MT are each 84, which is half of 168, the length of RT. M is the midpoint of RT. Find RM, MT, and RT. RM = 5 x + 9 = 5(15) + 9 = 84 MT = 8 x – 36 = 8(15) – 36 = 84 Substitute 15 for x. RT = RM + MT = 168 Segment Addition Postulate
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Kennedy, D., Charles, R., Hall, B., Bass, L., Johnson, A. (2009) Geometry Prentice Hall Mathematics. Power Point made by: Robert Orloski Jerome High School.
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