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Published byApril Cummings Modified over 8 years ago
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Usually consider solids (salts) Dissolving in water – “like dissolves like” ◦ Forming aqueous solutions. Remember pure liquids and solids are not part of K expressions Solubility product constant = K sp ◦ equilibrium constant for solubility ◦ chart of K sp ’s page 761 MgF 2 (s) ⇄ Mg 2+ (aq) + 2F - (aq) K sp = [Mg 2+ ][F - ] 2
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May still need to do ICE calculations if do not know concentrations of species in reaction or if don’t know solubility of each ion. Will be do Q to K comparisons to determine if a solid will form in from solution. ◦ Look at reaction equation ◦ May need a net ionic equation ◦ Consider solubility rules ◦ Q = ion product (just like Q from ch13) If Q > K, precipitation occurs (shifts right) If Q < K, no precipitation occurs (shifts left)
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Compare Ksp values to determine solubility or rank solubility. Larger Ksp value = more soluble ◦ Breaks up fully into ions and wants to stay Smaller Ksp value = less soluble Solubility can be affected by pH ◦ Need to consider if conjugate acid or base Or by addition of extra stuff (Le Chatelier’s Principle)
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Complex ion – a charged species consisting of a metal ion surrounded by ligands (a molecule or ion having a lone pair of electrons that can be donated) ◦ # ligands attached is called coordination # ◦ Occurs in a stepwise method – ligands are added 1 at a time Equilibrium constant called formation constants or stability constants = K f ◦ K 1, K 2, etc – one for each step ◦ May need to determine one first, then use to find the others.
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To get overall complex ion formation equation, need to add all steps together. If reactions are added, the K expressions are multiplied ◦ Kf = K 1 * K 2
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