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Published byRudolph Warren Modified over 8 years ago
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20.2 Electrical Forces
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What was the first method of charging an object? Friction – rubbing electrons onto one object creating a negative charge and leaving an excess amount of protons on the other object creating a positive charge
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Charging Method #2 Conduction Conduction is charging an object by touching a charged object to a neutral object. Example: Electroscope from yesterday, touching a live wire
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Charging Method #3 Induction Induction is charging an object by bringing a charged object near a neutral object, causing the charges inside the neutral object to move. Example: Electroscope from yesterday
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Charging Examples – which method?
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Induction usually causes polarization Polarization causes a difference in charge on two sides of an object Wall
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How do we measure the size of a charge? Charge is measured in Coulombs (C) Represented by the letter q Charge of an electron (fundamental charge) q = -1.6 x 10 -19 C (proton is the same but positive)
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Electric Force Attractive (opposite charges) Repulsive (same charges) Varies inversely with the square of the distance (1/d 2 ) Varies directly with the size of the each of the charges called q (q 1 x q 2 ) A Positive force is repulsive, A Negative force is attractive F = kq 1 q 2 d2d2 F = force K = coulomb’s constant = 9 x 10 9 N m 2 / C 2 q = charge of particles d = distance
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Electric Force vs. Gravitational force Both are field forces Both are inverse proportional to the square of the distance Can be added as vectors Electric can be Attractive or Repulsive Gravitational force is much weaker than Electric force
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Example Problem #1 Two positive identical charges of 6.0 x 10 -6 C are separated by a distance of 0.50m. What is the force between the charges?
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Example Problem #2 A negative charge of -6.0 x 10 -6 exerts an attractive force of -65n on a second charge 0.05 meters away. What is the size of the second charge?
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Problem #3 What is the force on the middle charge? F 36 = 405n F -56 = 300n
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Problem #4 How would you find the force on the charge on the left? F 36 = 405n F -35 = -54n
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Problem #5 How would you find the force on the charge on the right? F 65 = 300n F -35 = -54n
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