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Published byMoses Brown Modified over 8 years ago
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Graphs of a falling object And you
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Objective 1: Graph a position –vs- time graph for an object falling from a tall building for 10 seconds Calculate the position of the object at each second interval. Δx = V o t + ½ at 2 Note that V o = 0 Δx (at 1 sec) = ½ (9.8) 1 2 = 4.9 m Δx (at 2 sec) = ½ (9.8) 2 2 = 19.6 m … to 10 seconds Plot the postion points on your graph and draw in a curve of best fit (using a ruler)
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NOW…at the 2,4,6,8,10 s intervals – draw in a tangent line and calculate the slope at that point Make a second graph of Velocity –vs- time using the data points you calculated at the 2,4,6,8,10 second intervals on the first graph. Draw in a line of best fit and calculate the slope This slope represents the rate of acceleration of the falling object This rate should be ~ 9.8 m/s 2
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NOW let’s work backwards… At the 8 second interval of the velocity –vs – time graph, calculate the area under the line of best fit. What are the units? What does this area represent? Now calculate the distance an object travels when it falls for 8 seconds using an equation. These 2 values should be the same!!!!!
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