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Week 2 Physics 133. LaO 0.5 F 0.5 BiS 2 Starting elements and compounds: La 2 O 3 La 2 F 3 La Bi 2 S 3 S A(La 2 O 3 ) + B(La 2 F 3 ) + C(La) + D(Bi 2.

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Presentation on theme: "Week 2 Physics 133. LaO 0.5 F 0.5 BiS 2 Starting elements and compounds: La 2 O 3 La 2 F 3 La Bi 2 S 3 S A(La 2 O 3 ) + B(La 2 F 3 ) + C(La) + D(Bi 2."— Presentation transcript:

1 Week 2 Physics 133

2 LaO 0.5 F 0.5 BiS 2 Starting elements and compounds: La 2 O 3 La 2 F 3 La Bi 2 S 3 S A(La 2 O 3 ) + B(La 2 F 3 ) + C(La) + D(Bi 2 S 3 ) + E(S)= LaO 0.5 F 0.5 BiS 2 System of equations: 2 A +2 B + C=1 3A=0.5 3B=0.5 2D=1 3D+E=2 C=1/3 A=1/6 B=1/6 D=1/2 E=1/2

3 LaO 0.5 F 0.5 BiS 2 Starting CompoundLa2O3La2F3LaBi2S3S Molar Mass325.817334.814138.91514.15532.065 Ratio0.16667 0.333330.50000 Total Molar Mass*Ratio54.3028355.8023346.30333257.0775016.03250429.51850 Normalized to 1g0.126430.129920.107800.598520.03733

4 CeRhIn 5 Starting compounds: Ce Rh In A(Ce) + B(Rh) + C(In) = CeRhIn 5 Trivial system of equations! A=1 B=1 C=5

5 CeRhIn 5 Starting CompoundCeRhIn Molar Mass140.12102.91114.82 Ratio115Total Molar Mass*Ratio140.12102.91574.1817.13 Normalized to 1g0.171480.125940.70258


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