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Published byAustin Holt Modified over 8 years ago
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Presented by: Ms. Bowie
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By the end of the Presentation you should: ◦ Understand the difference between position, distance and displacement; ◦ Understand the difference between speed and velocity; ◦ Be able to solve simple problems involving average speed and velocity; ◦ Carry out simple calculations involving distance, displacement, speed, velocity and acceleration.
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We can describe an object’s position, in one dimension, using a number line. The initial position can be recorded as “zero” on the number line. In this case, my crazy frog ended up at position “9” on the number line.
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Position can also include information about where the object ends up relative to the initial position using + and – signs. Again, in this case, my crazy frog ended up at position +9.
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By convention, a positive integer generally represents motion to the right or up. A negative integer generally represents motion to the left or down. The symbol for position is usually “x”.
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For example, assuming divisions are 1 m, we could say: ◦ The rocket is +3 m relative to the ghost. ◦ The teddy driving car is +6 m relative to the ghost. ◦ The rocket is -3 m relative to the teddy driving car. ◦ The ghost is -6 m relative to the teddy driving car.
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Distance is how much an object’s position changes. How far an object has travelled is referred to as the total distance travelled (or simply, it’s distance). The unit of measure for distance is the meter (m). Distance is a scalar. Scalar means that it has magnitude, but no direction is given.
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Practice Problem #1 An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. What distance did the elephant travel? 500 m300 m 1300 m
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Practice Problem #1 - SOLUTION An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. What distance did the elephant travel? x = d 1 + d 2 + d 3 ∴x = 1300 m + 500 m + 300 m = 2100 m Notice that there is no direction noted as distance is a scalar. d 2 = 500 md 3 = 300 m d 1 =1300 m
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Displacement (Δd) is a vector that describes a straight line from the starting position to the final position. Displacement (d f – d i ) is also measured in meters (m) It is sometimes called the position vector as it points from your initial position to the final vector.
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Problem #2 An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. What is the displacement? d 2 = 500 md 3 = 300 m d 1 =1300 m Displacement vector didi dfdf
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Problem #2 An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. What is the displacement? Δd = d f – d i = 500 m east d 2 = 500 md 3 = 300 m d 1 =1300 m Displacement vector didi dfdf 500 m
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Average speed is the rate at which distance is travelled. It is a scalar. It is measured in m/s Speed is scalar (to help you remember) Note: the line above indicates “average”
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Problem #3 An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. What is the average speed if the entire journey took 600 seconds? V = 2100 m = 3.5 m/s 600 s Since speed is a scalar we do not need to indicate direction.
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Average velocity is the rate at which displacement changes. It is a vector. It is measured in m/s Velocity is Vector (to help you remember) Note: the line above indicates “average”
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Problem #3 An elephant walked 1300 m East to the watering hole. It then walked 500 m West to its favourite food, the acacia tree. However, it was scared by a pack of hyenas and ran 300 m West. The entire journey took 600 s. What is the average velocity? v =Δx/Δt = d f – d i / t= 500 m – 0 m /600 s v =500 m / 600 s v =0.833 m/s east dfdf d 2 = 500 md 3 = 300 m d 1 =1300 m Displacement vector didi 500 m
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Sid travels 4 m east and 3 m north in search of an acorn. The entire journey takes him 20 seconds. Find: 1.Sid’s distance travelled 2.Sid’s displacement 3.Sid’s average speed 4.Sid’s average velocity
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Sid travels 4 m east and 3 m north in search of an acorn. The entire journey takes him 20 seconds. 1.Sid’s distance travelled Δd = d 1 + d 2 Δd = 4 m + 3 m = 7 m (Notice that no direction is given because distance is a scalar) 4 m E 3 m N
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Sid travels 4 m east and 3 m north in search of an acorn. The entire journey takes him 20 seconds. 1.Sid’s displacement Δd = d f - d i c 2 = a 2 + b 2 c 2 = 4 2 + 3 2 c 2 = 16+ 9 c = √25 c = 5 m 4 m E 3 m N Δd = df – d i didi dfdf
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Sid travels 4 m east and 3 m north in search of an acorn. The entire journey takes him 20 seconds. 1.Sid’s average speed v = 7 m/ 20 s v = 0.35 m/s 4 m E 3 m N
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Sid travels 4 m east and 3 m north in search of an acorn. The entire journey takes him 20 seconds. 1.Sid’s displacement v = 5m/20 s c = 0.25 m/s NE 4 m E 3 m N Δd = df – d i didi dfdf
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Acceleration is the rate at which velocity changes. Acceleration is a vector. The units are m/s/s or simply m/s 2
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The units m/s 2 might sound odd but think of it like this: If you have an acceleration of 5 m/s 2 this means that your speed is increasing by 5 m/s every second. So: ◦ at time 1 the speed is 5 m/s. ◦ at time 2 s, the speed is 10 m/s and ◦ at time 3 s, the speed is 15 m/s…
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Problem #4 Marty the Moose accelerates from rest to a velocity of 9 m/s in a time span of 3 seconds northward on Cole Harbour Rd. Calculate Marty’s acceleration. a = v f – v i t f – t i a = 9 m/s – 0 m/s = 9 = 3 m/s 2 N 3 – 0 3
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d f (m) d i (m) Δd (m) t f (s) t i (s) Δt (s) Velocity (m/s) +20.0+17.36.55.0 +26.9+5.38.32.1 +26.8-15.40105.4 55012510 60-20010030-2 Complete the Chart http://www.youtube.com/watch?v=rZo8-ihCA9E&feature=related
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