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SATL -CALCIUM CHEMISTRY FAHMY A.F.M. BY LAGOWSKI,J.J. &

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Presentation on theme: "SATL -CALCIUM CHEMISTRY FAHMY A.F.M. BY LAGOWSKI,J.J. &"— Presentation transcript:

1 SATL -CALCIUM CHEMISTRY FAHMY A.F.M. BY LAGOWSKI,J.J. &

2 You have the following chemicals: Answer the following questions (1  10) 678 CaCO 3 CaO Ca (metal) 12345 Na 2 CO 3 Ca(OH) 2 CaCl 2 HCl H2OH2O H2OH2O

3 Q1(Use the following triangular diagrams to construct clockwise chemical relations between the (forgoing) chemicals CO 2 Ca(OH) 2 CaCO 3 CaO H2OH2Oheat CaCl 2 CaCO 3 CaO HCl Na 2 CO 3 heat CaO CaCl 2 Ca burn in air (O) HCl electrolysis A1 )

4 Q2) Use the following quadrilateral diagrams to consrtuct clockwise chemical relations between the (forgoing) chemicals. H2OH2O HCl CaCO 3 Ca(OH) 2 CaCl 2 Ca electrolysis CO 2 burn in air (O) HCl Ca(OH) 2 CaO CaCl 2 Ca electrolysis H2OH2O A)A)

5 Q3) Use the following pentagonal diagram to construct chemical relation clockwise chemical relation between the (forgoing) chemicals. H2OH2O HCl CaO CaCl 2 Ca Ca(OH) 2 CaCO 3 CO 2 burn in air (O) electrolysis A)A)

6 Q4) Draw the possible clockwise triangular chemical relations between your (forgoing) chemicals. 1) HCl CaO CaCl 2 Ca electro. burn in air (O) 2) Ca(OH) 2 CaCl 2 Ca HCl electro.H2OH2O 3) CO 2 Ca(OH) 2 CaCO 3 CaO heatH2OH2O 4) CaCl 2 CaCO 3 CaO Na 2 CO 3 heatHCl

7 Q5) Draw two anticlockwise triagular relations (forgoing) between your (Lab-1) chamicals. HCl CaCl 2 CaO CaCO 3 heatNa 2 CO 3 Ca(OH) 2 Ca CaCl 2 H2OH2O electro.HCl Q6 ) Use the following triangular diagram to construct the possible reversible chemical relations between the (forgoing) chemicals. Na 2 CO 3 HCl CaCl 2 CaCO 3 CaO HClheat A)A)

8 Q7) Draw the maximum chemical relations between the (forgoing) chemicals in quadrilateral diagrams, then give these relations in a list. H2OH2O Na 2 CO 3 CaCl 2 Ca(OH) 2 CaCO 3 CaO CO 2 HCl heat  CaO  Ca(OH) 2  CaCl  CaCO 3  CaO  CaCl 2  CaCO 3  CaO  Ca(OH) 2  CaCO 3 Ca(OH) 2  CaCl 2  CaCO 3 CaO  Ca(OH) 2  CaCl 2 7-1

9 burn in air (O) HCl Ca(OH) 2 CaO CaCl 2 Ca HClH2OH2O H2OH2Oelectrolysis 7-2 Ca  CaO  Ca(OH) 2  CaCl 2 Ca  CaO  CaCl 2 Ca  Ca(OH) 2  CaCl 2 CaO  Ca(OH) 2  CaCl 2 Ca  CaO  Ca(OH) 2

10 electrolysis CO 2 CaCO 3 CaCl 2 Ca(OH) 2 Ca HCl H2OH2O  Ca  Ca(OH) 2  CaCO 3  CaCl 2 Ca  Ca(OH) 2  CaCl 2 Ca(OH) 2  CaCO 3  CaCl 2 7-3

11 Ca  CaCl 2  CaCO 3  CaO Ca  CaO  CaCl 2  CaO  CaCl 2  CaCO 3 HCl heat CaCO 3 CaCl 2 CaO Ca HCl Na 2 CO 3 burn in air (O) 7-4

12 Q8) Use the following quadrilateral diagrams to consrtuct the possible reversible chemical relations between your (forgoing) chemicals

13 electroly. HCl Ca(OH) 2 CaO CaCl 2 Ca burn in air (O) heat to redness H2OH2O HCl CaCO 3 CaCl 2 CaO Ca HCl electrolysis burn in air heat Na 2 CO 3 HCl (O) CaCl 2 Ca(OH) 2 CaCO 3 CaO H 2 O heat to redness HClheat Na 2 CO 3 HCl A

14 Q9) Draw the maximum chemical relations between the (forgoing) chemicals in a pentagonal diagram, then give these relations in a list H2OH2O HCl CaO CaCl 2 Ca Ca(OH) 2 CaCO 3 HCl heat CO 2 burn in air (O) electrolysis  Ca  CaO  Ca(OH) 2  CaCO 3  CaCl 2  Ca  CaO  Ca(OH) 2  CaCl2 CaCO 3  CaCl 2  Ca  CaO

15  CaO  Ca(OH) 2  CaCO 3 CaCO 3  CaO  CaCl 2 Ca(OH)2  CaCO3  CaCl2 CaO  Ca(OH)2  CaCl2 CaO  Ca(OH) 2  CaCO 3  CaCl 2  Ca  CaO  CaCl 2

16 CaCO 3 CO 2 burn in air HCl electro. CaCl 2 Ca CaO Ca(OH) 2 HCl Na 2 CO 3 H 2 O heat to redness (O) HCl ---- ----- CO 2 ------------ ----- Ca(OH) 2 ------ Q10)From (forgoing) chemicals complete the following pentagonal diagram.


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