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Published byMorgan Dixon Modified over 8 years ago
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Bell Work NOTE SCHEDULE! Wed = 8:17 am Fri = 7:50 am Due Dates Acid FRQ & Buffer Sim = TODAY Lab Notebook = Wed Buffer FRQ = Fri
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Buffers Weak acid & salt (common ion; conjugate base) HC 2 H 3 O 2 & NaC 2 H 3 O 2 Weak base & salt (common ion; conjugate acid) NH 3 & NH 4 Cl Resist changes in pH from [H + ] and [OH - ] Based on ratio of buffer components, [HA]/[A - ] or [B]/[BH + ] Salt;CB Weak Acid
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Buffer Animation http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/buffer12.swf http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/buffer12.swf
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Choosing A Good Buffer Equally Protects Against Acids & Bases [HA] = [A - ] [B] = [BH + ] Works in the pH range you wish to maintain Acidic use a weak acid & basic salt buffer Alkaline use a weak base & acidic salt buffer
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Choosing A Good Buffer Works in the pH range you wish to maintain….ex: pH @ 4.6 weak acid and salt [ ] should match [H + ] = Ka or[OH - ] = Kb [H + ] = 10 -4.6 = 2.5 x 10 -5 [H + ] = 2.5 x 10 -5 pH = -log [H + ] = 4.6 Ka = 1.8 x 10 -5 pKa = -log Ka= 4.7 acetic acid Small Nasty # Small Nasty # Log It Large Nice # Large Nice #
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Choosing A Good Buffer Acidity of soln matches the acidity of the buffer pH = -log [H + ] pKa = - log Ka pH = pKa or pOH = pKb
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Henderson – Hasselbalch Equation (H-H) weak acid salt conjugate base ion Ratio of buffer components determines pH change TAKE THE LOG OF THE ENTIER EQUATION -log [ H + ] = -log Ka [HA] [A - ] pH = pKa + log [A - ]/[HA] pOH = pKb + log [BH + ]/[B] Log vs -log Flip Log vs -log Flip
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Titration Buffer Zone Half of acid has reacted ½ HA H + + A - [HA ] acid = [A - ] conjugate Buffer Region [H+] = Ka [HA] [A - ] -log [H + ] = - log Ka pH = pKa and [H+] = Ka
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Titration Indicators Choosing an Indicator Indicator changes color over the equivalence point pH range
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Titration Indicators Choosing an Indicator pKa of indicator is within ± 1 unit of the pH
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Hydrolysis Reacting (not dissolving) a salt or salt ion with water Tool to determine if a salt is acidic of basic Basic = proton acceptor; creates OH - ions Acidic = proton donor; creates H + ions pH water changes based on behavior of the salt Ka vs Kb
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Sample Problem HAH3O+A- I0.010000 C- 1.66 x 10 -3 + 1.66 x 10 -3 E0.0100 – 1.66 x10 -3 1.66 x10 -3 Original 10 -2, ions are 10 -3 Can’t ignore Original 10 -2, ions are 10 -3 Can’t ignore
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Sample Problem
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1.66% = [H + ] x 100 [HC 3 H 5 O 3 ] [H + ] = 0.0166 x 0.50 M = 0.0083 M [H+] = [C 3 H 5 O 3 ] Ka = [0.0083] [0.0083] = 1.4 x 10 -4 [0.50] Only 1.66% Keq ~ Original Only 1.66% Keq ~ Original Account for ions Still Get Same Account for ions Still Get Same
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Sample Problem [H + ] = 0.0083 MKa = 1.4 x 10 -4 pH = -log [H + ] = - log (0.0083) pH = 2.08
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Sample Problem Weak acid and salt with common ion; Buffer! You have 2 options ICE or HH equation You have 2 options ICE or HH equation Ka = 1.4 x 10 -4 pH = -log (1.4x10 -4 ) log 0.18 = 3.41 0.50
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Sample Problem Strong 100% H + Strong 100% H + Only 1.66% Turns into H + Only 1.66% Turns into H + Added Volumes Will Change M Added Volumes Will Change M Ka = 1.4 x 10 -4
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Sample Problem Add H+ Will Shift eq Add H+ Will Shift eq Change Insignificant Change Insignificant Ka = 1.4 x 10 -4
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Sample Problem Add H+ Will Shift eq Add H+ Will Shift eq Before Adding In HCl After Adding In HCl 1.66% = [C 3 H 5 O 3 - ] x 100 [HC 3 H 5 O 3 ] [C 3 H 5 O 3 - ] = 0.0166 x 0.50 M = 0.0083 M [C 3 H 5 O 3 - ] = 0.00070 M How Does This Illustrate LeChatelier's Principle? How Does This Illustrate LeChatelier's Principle? How Does This Illustrate conjugate pairs Relationship? How Does This Illustrate conjugate pairs Relationship?
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Things To Do Turn In Acid Base FRQ / Buffer Simulation Lab Report = Due Wed Buffer FRQ = Due Fri
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Homework Lab Report = Due Wed Equilibrium Practice = Due Fri
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