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4.3 Matrix of Linear Transformations y RS T R ′S ′ T ′ x
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Example 2 Find a matrix B that represents a linear transformation from T(f) = f ’ + f ” from P 2 to P 2 with respect to the standard basis Β =(1, x, x 2 )
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Example 2 T(f) = f ’ + f ”
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Similar matrices Had we used a different basis, we could describe this same transformation using that basis. Two matrices that describe the same transformation with regard to a different basis are called similar matrices and are related by the formula SAS -1 = B In this formula A is similar to B
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An Application Write a matrix that will find the 2 nd derivative of a polynomial of degree 3 or lower. Use this matrix to find the 2 nd derivative of x 3 + 2x 2 + 4x +1
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Application solution Start with a basis: 1,x,x 2,x 3 Find the second derivative of each of the elements of the basis. Write the answer in terms of coordinates of the basis. 0 0 2 0 0 0 0 6 0 0
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Application part B Use matrix multiplication to find the second derivative of x 3 + 2x 2 + 4x +1
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Application part B Multiply the coordinate matrix times the matrix that represents x 3 + 2x 2 + 4x +1 in terms of our basis 1,x,x 2,x 3 0 0 2 0 1 4 0 0 0 6 4 = 6 0 0 0 0 2 0 0 0 0 0 1 0 y ” =6x + 4
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A Matrix of transformation
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Forming a Matrix of transformation
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Example 3
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Solution to 3a
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Solution to 3b Because there is an invertible matrix that describes the transformation T we call T an isomorphism
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Problem 6 Find the matrix of transformation
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6 solution What does this mean? If I had the vector as my x it means that I had 1 of the first element, 0 of the second and 1 of the 3 rd Or the matrix 1 1 and ran it through the transformation I would get 0 1 The matrix 1 3 using the answer from above as A as x 0 3 yields which are coordinates for the answer [ ]
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Homework p.181 1-19 odd lim sin(x) = 6 n --> ∞ n Proof: cancel the n in the numerator and denominator.
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Example 1 Express using coordinates
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Example 1 Solution
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Example 4
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Solution to example 4 a
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Solution to example 4b
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Solution to 4 c
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Example 6
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Example 6 solution
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Why are similar matrices related by B = S -1 AS Note: start at the lower left hand corner of the diagram and move to the upper right hand corner by each direction
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