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Phase Diagrams Continued

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1 Phase Diagrams Continued
Class 6 CHE 333 Phase Diagrams Continued Prov08

2 1085C 420C

3 Substitutional Solid Solubilty
How much one element will dissolve in another is determined by the Hume Rothery rules Atomic radii should be within 15% of each other Crystal structure should be the same for each element for good solubility Electronegativities should be similar. The valences of the atoms should be similar. Good solubility Cu –Ni, Cu-Au; Cu r=0.128A, Ni r=0.125, Au r=0.144 Crystal structure Ti- HCP, Al - FCC Poor soluility Na-Cl Na electronegativity 0.9, Cl 3.0 Valences – Zn 2+, Cu 1+ Only indicate solubility from these rules. DOES NOT APPLY TO THE ELEMENTS H,C,O,N,B THESE FORM INTERSTITIAL SOLID SOLUTIONS.

4 Iron Carbon Phase Diagram
Fe - a then g then d 912C 1394C Steels Eutectoid S1 -> S2 + S3 -> a + F e3C Peritectic S1+L -> S2 d + L -> g 3367 SUBLIMES Fe3C- cementite A compound

5 Stainless Steel Phase Diagram
Ternary phase diagram for stainless steels. In this case an isothermal section at a constant temperature is used.

6 Lever Arm Rule Determine the AMOUNTS of each phase use the Inverse Lever Arm Rule. Amount of solid = wa-wl/ws-wl Amount of liquid = ws-wa/ws-wl Amount of solid at 1300C is therefore / = 8/13 = 0.615= 61.5% Amount of liquid at 1300C is therefore / = 5/13 = = 38.5%

7 Change Average Composition 50%
Determine the AMOUNTS of each phase use the Inverse Lever Arm Rule. Amount of solid = wa-wl/ws-wl Amount of liquid = ws-wa/ws-wl Amount of solid at 1300C is therefore / = 5/13 = 0.385= 38.5% Amount of liquid at 1300C is therefore / = 8/13 = = 61.5%

8 Microstructures and Composition

9 Lead Tin Microstructures
38.1%Pb 61.9% Sn 90 %Pb 10%Sn 70% Pb 30%Sn 50%Pb 50%Sn

10 Lead Tin Microstructures
15%Pb 85%Sn Equiaxed Single Phase Grain Structure

11 Homework Using the Cu-Ni phase diagram, for a Cu-Ni what are the compositions of the phases at 1400, 1300 and 1200 C and what phases would be present. Using the Pb- Sn phase diagram,what are the compositions for points “a,c and e” on the diagram?


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