1. Prepared By Tarjan Pathak 141200105059 Harsh Patel 141200105031 Savan Kanani 141200105014 On Concept of Fluid Pressure Subject:- Fluid Flow Operation (2130502) Department of Chemical Engineering

2. Pressure at any point in a static fluid not fcn of x,y,or z Pressure in vertical only depends on  of the fluid P =  h + P o Gauge pressure: relative to atmospheric pressure: P =  h Thus for h = 10 ft, P = 10(62.4) = 624 psf This becomes 624/144 = 4.33 psi P = 14.7 psi corresponds to 34 ft 10 ft

3. What is the pressure at point A? At point B?  G = 42.43 lbs/ft 3 SG = 0.68  W = 62.4 lbs/ft 3 At point A: P A =  G x h G + P O = 42.43 x 10 + P O 424.3 lbs/ft 2 gage At point B: P B = P A +  W x h W = 424.3 + 62.4 x 3 611.5 lbs/ft 2 gage Converting P B to psi: (611.5 lbs / ft 2 ) / (144 in 2 /ft 2 ) = 4.25 psi Pressure in a Tank Filled with Gasoline and Water

4. Barometer (Hg) - Toricelli 1644 Piezometer Tube U-Tube Manometer - between two points Aneroid barometer - based on spring deformation Pressure transducer - most advanced

5. Rules of thumb:  When evaluating, start from the known pressure end and work towards the unknown end  At equal elevations, pressure is constant in the SAME fluid  When moving down a monometer, pressure increases  When moving up a monometer, pressure decreases  Only include atmospheric pressure on open ends

6. Find the pressure at point A in this open u- tube monometer with an atmospheric pressure P o P D =  W x h E-D + P o P c = P D P B = P C -  Hg x h C-B P A = P B Simple Example: P =  x h + P O

7. Thank you