1.  Start with the coefficient of 5x 3 y 2.  Cube your result.  Add the digits of your answer together.  Take the cube root of your answer.  Add the sum of the exponents in 6ab 2.

2.  14-3 Worksheet (odd problems)  Page 762 13 – 21 (odd)

3. A.0.1 B.0.2 C.0.25 D.0.3 The probability distribution shows the probabilities of different types of weather occurring on a particular day. Ariana’s soccer game will be canceled if there is rain or snow. What’s the probability that the game will be cancelled?

4.  Maximum occurs at the mean.  Mean, Median and Mode are equal  Population mean and Standard Deviation can be used to determine probabilities Since the histogram is high on the right and low on the left, the data are negatively skewed.

5. A normal distribution of data has a mean of 66 and standard deviation of 11. Find the probability that random value x is less than 44, that is P(x < 44). µ = 66 and  = 11 µ – 2 , that is 66 – 2(11) or 44 Answer: P(x < 44) = 2.5%

6.  A. PACKAGING Students counted the number of candies in 100 small packages. They found that the number of candies per package was normally distributed, with a mean of 23 candies per package and a standard deviation of 1 piece of candy. About how many packages had between 22 and 24 candies? 23 2422 2521 2026 About 68 packages contained between 22 and 24 pieces. B. What is the probability that a package selected at random had more than 25 candies? The probability that a package selected at random had more than 25 candies is about 2.5%.

7.  Page 776 5 - 15

8. The Interquartile Range is the difference between the upper quartile and lower quartile. In this example, the interquartile range is 11 - 4 = 7

9.  You can use also calculate this using your TI-84 calculator. Place the data into L1 using STATS, EDIT function. Then analyze the data using STATS, CALC, 1: 1-Var Stats. The first screen (at left) gives = Mean (average) and = Standard Deviation. The second screen provides the Med = Median, Q1 = lower quartile value, and Q3 = upper quartile value.  So, using the TI-84 calculator, you can quickly find the interquartile range by using Q3 – Q1. In this example 11 – 4 = 7.

10.  The following represents the body temperatures of healthy students. 96.7 98.0 98.3 98.5 98.8 99.9 1. Find the average temperature. (tenths) (98.37) 2. Find the standard deviation. (tenths) (0.96) 3. What percent of the students have a temperature below 100.29? (97.5) 4. What percentage is between 96.45 and 99.33? (81.5)

11.  Page 776 5 - 15