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Published byCalvin Ramsey Modified over 8 years ago
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Motion Graph Rapid Fire
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What is the velocity from 0-2 s ?
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Answer = 2 m/s
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Describe the motion from 2 s to 5 s.
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Answer = Still
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From 5 s to 8 s the object is: (accel away) (accel towards)
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Answer = Accelerating away
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What is the final position?
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Answer = 6m
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This is the p vs t graph for a football player tackling a ball carrier. What is located at 0m?
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Answer = The running back (the guy he was trying to tackle)
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Describe what happened.
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Answer = The player slowly ran towards the ball carrier, then accelerated towards the ball carrier to run at a faster speed, and then tackled him.
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What direction is the object moving from t=3s to t=5s?
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Answer = Left (negative 2.5 m/s)
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What does the straight line on a V vs t graph indicate?
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Answer = constant velocity
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What is the final position of the object? How do I find it?
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Answer = I take the area under the curve to find the answer to be: 9m-4m+3m = 8m
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If I were to change this graph to a position vs time graph, what would the slope be from 3s to 5s?
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Answer = -2 m/s
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What does the sloped line from 2s to 4s represent?
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Answer = positive acceleration (1m/s 2 )
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What is the acceleration from 7s to 8s?
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Answer = -3 m/s 2
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How can I find the velocity of the object using an acceleration vs time graph?
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Answer = find the area under the curve.
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Last question… What is the velocity of the object at the end of this motion graph?
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Answer = 9 m/s- 9 m/s + 1 m/s = 1m/s
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