1. (Mon) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a stein with a mass of 900 g with a force of 11.55 N from rest for 0.5 s, what will be the stein’s speed when he stops pushing? (10 min / 5 pts)

2. F = ma a = F/m a = 11.55 N / 0.9 kg a = 12.83 m/s² v f = v i + at v f = 0.0 m/s + (12.83 m/s²)(0.5 s) v f = 6.42 m/s

3. (Tue) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein so that it has a speed of 6.42 m/s on a frictionless bar 1 m tall, how far will the stein travel horizontally after it falls off the end of the bar? (10 min/5 pts)

4. (Tue) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein so that it has a speed of 6.42 m/s on a frictionless bar 1 m tall, how far will the stein travel horizontally after it falls off the end of the bar? In the “Y” direction X Dir Y Dir ΔxΔx Vi Vf a ΔtΔt 6.42 m/s 0 m/s² 1.0 m 0 m/s -9.81 m/s² Δx = vi + ½at² 1m = 0m/s + (0.5)(-9.81m/s²)(t²) (1m)/(4.905m/s²) = t² 0.2 s² = t² 0.45 s = t 0.45 s In the “X” direction Δx = vt Δx = (6.42m/s)(0.45s) Δx = 2.89 m

5. (Wed) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein with an initial speed of 6.42 m/s on a bar with a coefficient of friction of 0.3, how far will the stein travel before it stops? (10 min / 10 pts)

6. Fg = ma FX DirY Dir Fg Fn Ff Net Fg = (0.9 kg)(-9.81m/s²) Fg = -8.83 N -8.83 N Fn = -Fg 8.83 N Ff = μ Fn Ff = (0.3)(8.83 N) Ff = 2.65 N -2.65 N 0 N -2.65 N F = ma F/m = a (-2.65N)/(0.9kg) = a -2.94 m/s² = a vf² = vi² + 2aΔx 0 m/s = (6.42m/s)² + (2)(-2.94m/s²)(Δx) (-41.22 m²/s²)/(-5.88 m/s²) = Δx Δx = 7.0 m

7. (Thu) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein from rest to 6.42 m/s for 0.5 s, how much work did Bert do to push the stein? (8 min / 5 pts)

8. v f = v i + at Method #1 6.42 m/s = 0 m/s + a(0.5 s) 12.84 m/s² = a F = ma F = (0.9kg)(12.84 m/s²) F = 11.556 N vf² = vi² +2aΔx (6.42m/s)² = (0m/s)² +(2)(12.84m/s²)Δx 1.605m = Δx W = Fd W = (11.556 N)(1.605 m)W = 18.55 J Method #2 W = ΔKE W = KEf - KEi W = ½mv f ² - ½mv i ² W = ½(0.9kg)(6.42m/s)² - 0 W = 18.55 J (Thu) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. If Bert pushes a 0.9 kg stein from rest to 6.42 m/s for 0.5 s, how much work did Bert do to push the stein? (8 min/5 pts)

9. (Fri) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. Ernie rigs the glass to leak soda to throw off Bert. If Bert pushes a 0.9 kg stein at 6.42 m/s at the start, and 0.4 kg soda leaks out, what is the final speed for the stein (assume frictionless bar)? (7 min / 5 pts)

10. ρi = ρf m 1 v 1 = m 2 v 2 (0.9 kg)(6.42 m/s) = (0.5 kg)(v 2 ) 11.56 m/s = v 2 (Fri) Bartenders Bert and Ernie are playing Soda Stein Shuffleboard on the bar. Ernie rigs the glass to leak soda to throw off Bert. If Bert pushes a 0.9 kg stein at 6.42 m/s at the start, and 0.4 kg soda leaks out, what is the final speed for the stein (assume frictionless bar)? (7 min/5 pts)

11. End of Week Procedures 1.Add up all the points you got this week 2.Put the total number of points out of 30 points you earned at the top of your page (no total, lose 5 points) 3.List any dates you were absent or tardy (and why) 4.Make sure your name and period # is on the top of the page (no name, no credit) 5.Turn in your papers