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Chapter 6 Ohm’s Law, Work, Energy and Power. ResistanceCurrentVoltage 4Ω4Ω4A 16V.

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Presentation on theme: "Chapter 6 Ohm’s Law, Work, Energy and Power. ResistanceCurrentVoltage 4Ω4Ω4A 16V."— Presentation transcript:

1 Chapter 6 Ohm’s Law, Work, Energy and Power

2 ResistanceCurrentVoltage 4Ω4Ω4A 16V

3 ResistanceCurrentVoltage 4Ω4Ω2A 8V

4 ResistanceCurrentVoltage 5Ω5Ω.2A 1V

5 ResistanceCurrentVoltage 4mΩ4mA 16uV Try to do in your head without a calculator

6 ResistanceCurrentVoltage 4MΩ5uA 20uV

7 ResistanceCurrentVoltage 2kΩ3mA 6V

8 ResistanceCurrentVoltage 3A 6V 2Ω2Ω

9 ResistanceCurrentVoltage 3A 6V __kΩ

10 ResistanceCurrentVoltage 2mA 10mV 5Ω5Ω

11 ResistanceCurrentVoltage __MΩ2mA 10mV.000005

12 ResistanceCurrentVoltage __kΩ2mA 10mV.005

13 ResistanceCurrentVoltage 2mA 10x10 -4 V __MΩ.0000005 5 x 10 -7 MΩ

14 Random Video of the Day

15 Work What is work? Motion must take place for work to take place What is the unit for work? Joule (J) (This is also the same unit for Energy) Work takes place when electrical energy is converted to mechanical energy and vice versa What about electrical work? (no motion involved?) 1 Joule = Energy required to raise 1 Coulomb of charge through a potential difference of 1 Volt

16 Work What is the equation for work? W = Q * V Work = Charge * Voltage Joules = Coulombs * Volts

17 Power What is Power? Power is how much work can be done in a specific amount of time (Like MPH) Units for Power is Watts (W) (Like MPH) P = Work / Time

18 Power Equation for Power Power = Voltage * Current Power = Work / Time P = V * I Power = Q * V / Time Power = I * Time * V / Time Remember W = Q*V Remember I = Q/t Thus Q = I*t Power = I * V

19 Power See how Power also equals: P = V 2 /R P = I 2 * R

20 Power P = ? Watts I = 6 Amps V = 3 Volts P = V 2 /R P = I 2 * R P = V * I P = 18 Watts

21 Power P = 18 Watts I = 6 Amps V = 3 Volts P = V 2 /R P = I 2 * R P = V * I R = ? Ω R =.5 Ohms

22 Power P = ? Watts I = 5 Amps V = ? Volts P = V 2 /R P = I 2 * R P = V * I R = 10 Ohms P = 250 Watts V = 50 Volts

23 Power P = ? Watts V = 3 Volts P = V 2 /R P = I 2 * R P = V * I R = 9 Ω P = 1 Watts

24 Power P = 32 Watts P = V 2 /R P = I 2 * R P = V * I R = 2 Ω I = ? A I = 4 Amps

25 Power P = ? P = V 2 /R P = I 2 * R P = V * I I = ? P = 20W I = 2A

26 Power P = ? P = V 2 /R P = I 2 * R P = V * I R = ? P = 2W R = 50 Ohm

27 April 2014 0 - 426kWh 426 - 553kWh 553 – 851 kWh 851+ kWh 14¢ 19¢ 27¢ 31¢ Sept 2014 600kwHr = $107.57 600kwHr = $96.46

28 Oct 2014 600kwHr = $108

29 1.A load operates at 48V and draws 30mA. What is its resistance? 2.What voltage is dropped across a 1MΩ resistor when 6uA of current is flowing through it? 3.A device draws 2.5A from a 100V source. What current will it draw from a 200V source? 4.If a DC power supply can deliver 2A of current at 12V, what is the maximum available power? 5.The voltage drop of a 22kΩ resistor is 18V. How much power is the resistor dissipating? 6.A 50Ω load dissipates 100W of power. How much voltage is across the load? 7.How much current does a 60W light bulb draw from a 120V source? 8.How much will it cost to light a 13W light bulb for 30 days at a cost of $0.18 per kWhr? 9.Calculate the maximum voltage drop a 1kΩ, ¼ watt resistor should handle in constant operation? Assume a 100% safety factor. 10.How much current for the resistor above? Practical Ohm’s Law Questions

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