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DC Series Circuits Solving circuits step by step.

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Presentation on theme: "DC Series Circuits Solving circuits step by step."— Presentation transcript:

1 DC Series Circuits Solving circuits step by step

2 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  RT = R1 + R2 + R3 12K +22K +15K 49K Ohms

3 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V

4 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V ? I = E / R I = 48 / 49K 48 / 49000 =.0009795

5 Wait a minute! What in tarnation is 0.0009795? Move three places to the right and you have 0.9795m That is still smaller than one. Move three more to the right, 979.5  Round to three places and we have 980  I = Amps, or 980  A

6 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V ? I = E / R I = 48 / 49K 48 / 49000 = 980  A Amps

7 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A Since current is the same in all parts of a series circuit:

8 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = 12000 x 0.000980 Cancel three places left and right of the decimal, leaving 12 x 0.980 = 11.76 The answer is 11.76, rounded off = 11.8 Volts

9 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = 22000 x 0.000980 Cancel three places left and right of the decimal, leaving 22 x 0.980 = 21.56 11.8V The answer is 21.56, rounded off = 21.6

10 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A E = I x R E = 15000 x 0.000980 Cancel three places left and right of the decimal, leaving 15 x 0.980 = 14.7 11.8V The answer is 14.7, rounded off =14.7 21.6V 14.7V Double-check Add volts 11.8 + 21.6 + 14.7 = 48.1

11 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = 0.000980 x 11.8 P = 0.011564, or11.6 m Watts

12 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = 0.000980 x 21.6 P = 0.021168, or21.2 m 11.6 mW

13 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = 0.000980 x 14.7 P = 0.014406, or14.4 m 11.6 mW 21.2 mW

14 R1R1 I1I1 E1E1 P1P1 R2R2 I2I2 E2E2 P2P2 R3R3 I3I3 E3E3 P3P3 RTRT ITIT ETET PTPT 12K  22K  15K  22K  15K  49K  48V 980  A 11.8V 21.6V 14.7V P IE P = I x E P = 0.000980 x 48 P = 0.04704, or47.0 m 11.6 mW 21.2 mW 14.4 mW Double-check 11.6 + 21.2 + 14.4 = 47.247.0 mW


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