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Linear Programming Operations Management Dr. Ron Lembke
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Motivating Example Suppose you are an entrepreneur making plans to make a killing over the summer by traveling across the country selling products you design and manufacture yourself. To be more straightforward, you plan to follow the Dead all summer, selling tie-dyed t-shirts and screenprinted sweatshirts.
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Example You are really good with tie-dye, so you earn a profit of $25 for each t-shirt. The sweatshirt screen-printed sweatshirt makes a profit of $20. You have 4 days before you leave, and you want to figure out how many of each to make before you head out for the summer. You plan to work 14 hours a day on this. It takes you 30 minutes per tie dye, and 15 minutes to make a sweatshirt.
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Example You have a limited amount of space in the van. Being an engineer at heart, you figure: If you cram everything in the van, you have 40 cubic feet of space in the van. A tightly packed t-shirt takes 0.2 ft 3 A tightly packed sweatshirt takes 0.5 ft 3. How many of each should you make?
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Summary 14hrs / day Van:40.0 ft 3 4days Tshirt:0.2 ft 3 30min / tshirt Sshirt:0.5 ft 3 15min / Sshirt How many should we make of each?
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Trial and Error Use up all of the space? Sweatshirts: 40/0.5 = 80. 80*20 = $1,600 T-shirts: 40/0.2 = 200! 200*25 = $5,000 cool! Use all of your time? Ss: 56/0.25 = 224. 224 * $20 = $4,480 Ts: 56/0.5 = 112. $25*112 = $2,800 Fill it with Tshirts? Only time to make 112 Spend all your time making Ss? Only space for 80
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Trial and Error STSpaceTimeProfitsComments 8004020$1,600<< 56hr 020040100$5,000> 56 hrs 224011256$4,480> 40 cu ft 011222.456$2,800<< 40 cu ft
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Improving the Solution (0,112) all time is used, van not full $2,800 Look for a compromise solution What if make one less T? Frees up 0.5 hrs, revenue goes down $25 In 0.5hrs, could make 2 S, brings in $40 more Same amt of time, $15 more! 1 T less frees up 0.2 ft 3 2 S add 1.0 ft 3 Increase 0.8 ft 3 van wasn’t full, so no problem Trade 1 T for 2 S, gain $15! $2,815
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Improving Solution Keep making trade. How many times? Use up 0.8 more space At (0,112) using 22.4, so 40 – 22.4 = 17.6 avail 17.6/0.8 = 22 Make trade 22 times (0,112) + 44S – 22T = (44,90) Space 44*0.5 + 90*0.2 = 22+18 = 40 cu ft Time 44*0.25 + 90*0.5 = 11 + 45 = 56 hrs Van is full, all the time is used Profits 44*20 + 90*25 = 880 + 2250=$3,130
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Write down the problem We could express the problem like this: Max20S+25T s.t.0.5S+0.2T<=40 0.25S+0.5T<=56 S>=0 T>=0 Space Time
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Linear Programming What we have just done is called “Linear Programming.” Has nothing to do with computer programming Invented in WWII to optimize military “programs.” “Linear” because no x 3, cosines, x*y, etc.
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Standard Form Linear programs are written the following way: Max3x+4y s.t.x+y<=10 x+2y<=12 x>=0 y>=0
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Standard Form Linear programs are written the following way: Max3x+4y s.t.x+y<=10 x+2y<=12 x>=0 y>=0 Objective Function Constraints LHS (left hand side) RHS (right hand side) inequalities Non-negativity Constraints Objective Coefficients
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Summary Solved a linear program Wrote the problem mathematically, in “standard form” Solved the problem using trial and error
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