1. Pre-Calculus 2-6B: Page 161 #’s 27-38odd, 41,49

2. 27) Find an equation in the form y=a(x-x1)(x-x2)

3. Vertex (0,-2), passing through (3,25) y = 3(x – 0)2 – 2
Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions.
Vertex (0,-2), passing through (3,25)
y = 3(x – 0)2 – 2

4. 31)Vertex (3,1), x-intercept of 0 y = -1/9(x – 3)2 + 1
Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions.
31)Vertex (3,1), x-intercept of 0 y = -1/9(x – 3)2 + 1

5. Find the standard equation of a parabola that has a vertical axis and satisfies the given conditions.
33) x-intercepts -3 and 5, highest point has y-coord 4 y = -1/4(x – 1)2 + 4

6. Find the maximum vertical distance d between the parabola and the line for the green region
35)

7. 37) D(h)= h h –
24.72 km

8. Max distance from ground. 424 ft
41) An object is projected vertically upward from the top of a building with an initial velocity of 144 ft/sec. Its distance s(t) in feet above the ground after t sec is given by the equation: h=-16t t + 100
Max distance from ground ft
Height of the building ft

9. Equation of the parabola y = 1/500x2 + 10
49) One section of a suspension bridge has its weight uniformly distributed between twin towers that are 400 ft apart and rise 90 ft above the horizontal roadway. A cable strung between the tops of the towers has the shape of a parabola, and its center point is 10 feet above the roadway. Suppose coordinate axes are introduced, as shown in the figure.
Equation of the parabola
y = 1/500x2 + 10
9 equally spaced vertical cables are used to support the bridge. Find the total length of these supports.
282 ft