1. Impedance Transformation

2. Resistance of Inductor R=R sh (L/W) – R sh is the sheet resistance – Rsh is 22 mOhms per square for W=6um. – If the outer diameter is 135 um, the length is approximately 135um x4=540 um. – R=22 mOhms x (540/6)=1.98 Ohms Q=(ωL)/R=(2π2.4G0.336 nH)/1.98 Ω=2.56

3. Include Resistor In the Tank Circuitry Q=2.427/(3.076-1.888)=2.04 Inclusion of parasitic resistance reduces the circuit Q from 10.

4. Problem The gain drops significantly when the resistive loss in the inductor is accounted for.

5. Assignment Redesign the circuit so that it meet the following specifications: – fo=2.4 GHz – Q(circuit quality factor)>7 – Av=Vout/Vin=-6 dB – Rs=50 Ohms

6. Design Constraints Design constratins: – Av=R p /(R s +R p ) – R p =R ind (1+Q ind *Q ind ) – Qcirc=ω o (R p *R s /(R p +R s ))C=ω o A v R s C – ω o =1/sqrt(LC) – Q ind =ω o L/R ind

7. Submission Check List Determine the Qind that achieves the Av. Submit the circuit schematic Submit AV as a function of frequncy from 1M to 10 GHz.