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Warm Up: 1)Given: AB bisects <CAD, AE bisects <BAD, and AC bisects <MAD. If m<CAD = 48, find: a. m<MAB b. m<BAE A D E B C M 12° 24° 48° 72° 12°

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Presentation on theme: "Warm Up: 1)Given: AB bisects <CAD, AE bisects <BAD, and AC bisects <MAD. If m<CAD = 48, find: a. m<MAB b. m<BAE A D E B C M 12° 24° 48° 72° 12°"— Presentation transcript:

1 Warm Up: 1)Given: AB bisects <CAD, AE bisects <BAD, and AC bisects <MAD. If m<CAD = 48, find: a. m<MAB b. m<BAE A D E B C M 12° 24° 48° 72° 12°

2 Proving Theorems Reasons Used in Proofs –Given Information –Definitions –Postulates (These include properties from Algebra) –Theorems that have already been proved

3 StepsReasons Given 1. 2. 3. 4. Addition Property of Equality Segment Addition Postulate Substitution Property Given: RT and PQ intersect at S so that RS = PS and ST = SQ Prove: RT = PQ R Q P T S RS = PS; ST = SQ RS + ST = PS + SQ RS + ST = RT; PS + SQ = PQ RT = PQ

4 StepsReasons Given 1. 2. 3. 4. Angle Addition Postulate Substitution Property Reflexive Property Given: Prove: O D C B A 3 21 5. Subtraction Property of Equality

5 Midpoint Theorem If M is the midpoint of AB, then AM = 1/2AB and MB = 1/2AB ABM Given: M is the midpoint of AB k Prove: AM = 1/2AB; MB = 1/2AB StatementsReasons 1. k 2. k3. 4. 5. k 6. M is the midpoint of AB Given AM = MBDefinition of a midpoint AM + MB = ABSegment Addition Postulate AM + AM = AB, or 2AM = ABSubstitution Property AM = 1/2ABDivision Prop. Of Equality MB = 1/2ABSubstitution Property


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