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6. Pushdown Automata CIS 5513 - Automata and Formal Languages – Pei Wang
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Pushdown automata: idea Context-Free Languages can be accepted by pushdown automata A pushdown automaton is an ɛ -NFA with a stack with unlimited capacity Its transition function also takes the top of the stack into account, and may change the top item in the stack It accepts at a final state or an empty stack
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Pushdown automata: definition A pushdown automaton (PDA) P = (Q, Σ, Γ, δ, q 0, Z 0, F) where Γ (Gamma): A finite stack alphabet δ: Q×(Σ {ε})×Γ → 2 Q×Γ*, a transition function that specifies the set of possible next state and the new content at the top of the stack Z 0 Γ, the start symbol in stack The other components are like in an ɛ -NFA
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Example: transition table A PDA for the binary language {ww r }: P = ({q 0,q 1,q 2 }, {0, 1}, {Z 0,0,1}, δ, q 0, Z 0, {q 2 }) 1. δ(q 0, 0, Z 0 ) = {(q 0, 0Z 0 )}; δ(q 0, 1, Z 0 ) = {(q 0, 1Z 0 )} 2. δ(q 0, 0, 0) = {(q 0, 00)}; δ(q 0, 0, 1) = {(q 0, 01)}; δ(q 0, 1, 0) = {(q 0, 10)}; δ(q 0, 1, 1) = {(q 0, 11)} 3. δ(q 0, ɛ, Z 0 ) = {(q 1, Z 0 )}; δ(q 0, ɛ, 0) = {(q 1, 0)}; δ(q 0, ɛ, 1) = {(q 1, 1)} 4. δ(q 1, 0, 0) = {(q 1, ɛ )}; δ(q 1, 1, 1) = {(q 1, ɛ )} 5. δ(q 1, ɛ, Z 0 ) = {(q 2, Z 0 )}
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Example: transition graph
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Instantaneous descriptions of PDA The configuration, or instantaneous description (ID), of a PDA: ( q, w, r ), where q is the state, w is the remaining input, and r is the stack contents Here “state” only specifies the “control unit”, not the stored “data” in stack If the value of δ (q, a, X ) contains ( p, α ), then the ID transition is ( q, aw, Xβ ) ( p, w, αβ ), for arbitrary w and β
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ID transitions: an example
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Properties of ID transitions ID transition with multiple moves is shown as * Symbols may be added or removed to input or stack in ID transitions
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Exercise 6.1.1 Solution
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Two types of acceptance A PDA can define a language in two ways
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Equivalence of the two types Proof: P F can be obtained by adding an ɛ -transition to a final state whenever the stack in P N is empty, with the help of a new stack-symbol below Z 0 Proof: P N can be obtained by popping out all stack symbols in final states in P F, with the help of a new stack-symbol below Z 0
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Exercises for Section 6.2 6.2.1(a): Design a PDA to accept {0 n 1 n | n ≥ 1} 6.2.2(a): Design a PDA to accept {a i b j c k | i = j or j = k} Solutions: http://infolab.stanford.edu/~ullman/ialcsols/sol6.html#sol62
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CFG to PDA From a given CFG G = ( V, T, Q, S ), a P N = ({q}, T, V T, , q, S ) can accept L( G ) by simulating the leftmost derivation to expand the symbols in stack to match the input When P N is in ID (q, y, Aα) where A is a variable and there is a rule A→β in Q, the next ID can be (q, y, βα). Remove the common prefix of βα and y. Repeat until the stack is empty
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CFG to PDA: example
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PDA to CFG : simple case If a PDA is P = ({q}, Σ, Γ, δ, q, Z), the equivalent CFG G = (Γ {S}, Σ, R, S), where R contains S → Z, and for each (q, Y 1 Y 2 …Y k ) in δ(q, a, X), R contains X → aY 1 Y 2 …Y k, where k ≥ 0, and Y i can be a variable, a terminal, or ε
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PDA to CFG: general case Use a grammar variable [pXq] to represent the state change from p to q for the popping out of a stack symbol X
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PDA to CFG (cont.)
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PDA to CFG: example
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PDA to CFG: example (cont.) 6.10: δ(q, i, Z) = {(q, ZZ)}; δ(q, e, Z) = {(q, ε)}
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Exercises for Section 6.3 Solutions: http://infolab.stanford.edu/~ullman/ialcsols/sol6.html#sol63http://infolab.stanford.edu/~ullman/ialcsols/sol6.html#sol63
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Deterministic pushdown automata A PDA is deterministic (DPDA), if Each δ(q, a, X) has at most one element If δ(q, a, X) is nonempty, then δ(q, ɛ, X) must be empty
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PDA, DPDA, and DFA The languages accepted by DPDA are between those of PDA and DFA DPDA accept all regular languages, but only the context-free languages that have unambiguous CFG
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