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Pressure and Volume. Scientists look for patterns in nature.

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Presentation on theme: "Pressure and Volume. Scientists look for patterns in nature."— Presentation transcript:

1 Pressure and Volume

2 Scientists look for patterns in nature.

3 Pressure and Volume Are these two values related?

4 Pressure and Volume Are these two values related? P + V P – V P x V P ÷ V

5 Pressure and Volume Robert Boyle (1627-1691)

6 Pressure and Volume

7 If you double the pressure, you cut the volume in half.

8 Pressure and Volume Boyle’s Law: PV = K

9 Pressure and Volume Boyle’s Law: PV = K P 1 V 1 = P 2 V 2

10 Volume and Temperature

11 What happens to the volume of a gas as it warms up or cools down?

12 Volume and Temperature Jacques Charles (1746-1823)

13 Volume and Temperature Are these two values related? V + T V – T V x T V ÷ T

14 Volume and Temperature Charles’s Law: V/T = K V 1 /T 1 = V 2 /T 2

15 Volume and Temperature Charles’s Law: V/T = K V 1 /T 1 = V 2 /T 2 (Temp must be in o Kelvin)

16 Volume and Temperature T Kelvin = 273 + T Celcius

17 Pressure and Temperature

18 Joseph Gay-Lussac

19 Pressure and Temperature Gay-Lussac’s Law: P/T = K P 1 /T 1 = P 2 /T 2 (Temp must be in o Kelvin)

20 Example Problems All three of these laws predict changes. P 1 V 1 = P 2 V 2 V 1 /T 1 = V 2 /T 2 P 1 /T 1 = P 2 /T 2

21 Example Problems You will be given three of the four values. Plug them in and solve for the fourth.

22 Example Problems A gas sample at 40.0 o C occupies a volume of 2.32 L. If the temperature is raised to 75.0 o C, what will the volume be, assuming the pressure remains constant?

23 Example Problems A gas sample at 40.0 o C occupies a volume of 2.32 L. If the temperature is raised to 75.0 o C, what will the volume be, assuming the pressure remains constant?

24 Example Problems T 1 = 40.0 o C V 1 = 2.32 L T 2 = 75.0 o C V 2 = ?

25 Example Problems T 1 = 40.0 o C V 1 = 2.32 L T 2 = 75.0 o C V 2 = ? V 1 /T 1 = V 2 /T 2

26 Example Problems T 1 = 40.0 o C 40.0 + 273 = 313 V 1 = 2.32 L T 2 = 75.0 o C75.0 + 273 = 348 V 2 = ? V 1 /T 1 = V 2 /T 2

27 Example Problems T 1 = 313 o K 40.0 + 273 = 313 V 1 = 2.32 L T 2 = 348 o K75.0 + 273 = 348 V 2 = ? V 1 /T 1 = V 2 /T 2

28 Example Problems 2.32 L ? ------------ = ------------ 313 o K 348 o K V 1 /T 1 = V 2 /T 2

29 Example Problems 2.32 L 348 o Kx ------------ = ? 313 o K V 1 /T 1 = V 2 /T 2

30 Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K V 1 /T 1 = V 2 /T 2

31 Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense?

32 Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense? A small rise in temperature caused a small increase in volume.

33 Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense? A small rise in temperature caused a small increase in volume. Yes, it makes sense.

34 Homework Read section 14.1 Do problems 1, 2, 6, 7, 9, 10 Your next test will involve problems like these..


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