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Pressure and Volume
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Scientists look for patterns in nature.
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Pressure and Volume Are these two values related?
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Pressure and Volume Are these two values related? P + V P – V P x V P ÷ V
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Pressure and Volume Robert Boyle (1627-1691)
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Pressure and Volume
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If you double the pressure, you cut the volume in half.
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Pressure and Volume Boyle’s Law: PV = K
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Pressure and Volume Boyle’s Law: PV = K P 1 V 1 = P 2 V 2
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Volume and Temperature
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What happens to the volume of a gas as it warms up or cools down?
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Volume and Temperature Jacques Charles (1746-1823)
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Volume and Temperature Are these two values related? V + T V – T V x T V ÷ T
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Volume and Temperature Charles’s Law: V/T = K V 1 /T 1 = V 2 /T 2
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Volume and Temperature Charles’s Law: V/T = K V 1 /T 1 = V 2 /T 2 (Temp must be in o Kelvin)
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Volume and Temperature T Kelvin = 273 + T Celcius
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Pressure and Temperature
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Joseph Gay-Lussac
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Pressure and Temperature Gay-Lussac’s Law: P/T = K P 1 /T 1 = P 2 /T 2 (Temp must be in o Kelvin)
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Example Problems All three of these laws predict changes. P 1 V 1 = P 2 V 2 V 1 /T 1 = V 2 /T 2 P 1 /T 1 = P 2 /T 2
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Example Problems You will be given three of the four values. Plug them in and solve for the fourth.
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Example Problems A gas sample at 40.0 o C occupies a volume of 2.32 L. If the temperature is raised to 75.0 o C, what will the volume be, assuming the pressure remains constant?
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Example Problems A gas sample at 40.0 o C occupies a volume of 2.32 L. If the temperature is raised to 75.0 o C, what will the volume be, assuming the pressure remains constant?
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Example Problems T 1 = 40.0 o C V 1 = 2.32 L T 2 = 75.0 o C V 2 = ?
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Example Problems T 1 = 40.0 o C V 1 = 2.32 L T 2 = 75.0 o C V 2 = ? V 1 /T 1 = V 2 /T 2
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Example Problems T 1 = 40.0 o C 40.0 + 273 = 313 V 1 = 2.32 L T 2 = 75.0 o C75.0 + 273 = 348 V 2 = ? V 1 /T 1 = V 2 /T 2
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Example Problems T 1 = 313 o K 40.0 + 273 = 313 V 1 = 2.32 L T 2 = 348 o K75.0 + 273 = 348 V 2 = ? V 1 /T 1 = V 2 /T 2
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Example Problems 2.32 L ? ------------ = ------------ 313 o K 348 o K V 1 /T 1 = V 2 /T 2
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Example Problems 2.32 L 348 o Kx ------------ = ? 313 o K V 1 /T 1 = V 2 /T 2
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Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K V 1 /T 1 = V 2 /T 2
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Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense?
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Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense? A small rise in temperature caused a small increase in volume.
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Example Problems 2.32 L 348 o Kx ------------ = 2.58 L 313 o K Does the answer make sense? A small rise in temperature caused a small increase in volume. Yes, it makes sense.
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Homework Read section 14.1 Do problems 1, 2, 6, 7, 9, 10 Your next test will involve problems like these..
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