1. BALANCING CHEMICAL EQUATIONS

2. BALANCE THIS ON YOUR WHITEBOARD ___SiO + ___Cl 2  ___SiCl 4 + ___O 2

3. BALANCE THIS ON YOUR WHITEBOARD _4__SiO + _2__Cl 2  _1__SiCl 4 + _2__O 2

4. COMPLETE THE 3 PROBLEMS HANDED TO YOU. DONE? TRY THE BACK.

5. COMPLETE THIS ON YOUR WHITEBOARD  Water can be created through the process of electolysis. In this reaction, water is produced by reacting hydrogen and oxygen gas. Write a balanced equation for this reaction.

6. 2 H 2 (G) + O 2 (G)  2 H 2 O (G)  Water can be created through the process of electolysis. In this reaction, water is produced by reacting hydrogen and oxygen gas. Write a balanced equation for this reaction.

7. COMPLETE THE BACK OF THE BALANCING PRACTICE

8. MOLE CONCEPT REVIEW

9. SHORT VIDEO

10. WHITEBOARD EXPECTATIONS 1. Raise your board up when I count down to 1 (not before!) 2. Everyone answers every question 3. If the answer is multiple choice, write out the whole answer. If it is a free response question, write in a complete sentence.

11. QUESTION #1  1 mole of carbon will be: A. 1 atom B. 16 atoms C. 12.01 atoms D. 6.022x10 23 atoms

12. QUESTION #1  1 mole of carbon will be: A. 1 atom B. 16 atoms C. 12.01 atoms D. 6.022x10 23 atoms

13. QUESTIONS #2  1 mole of carbon will be: A. 1 gram B. 16 grams C. 12.01 grams D. 6.022x10 23 grams

14. QUESTIONS #2  1 mole of carbon will be: A. 1 gram B. 16 grams C. 12.01 grams D. 6.022x10 23 grams

15. QUESTION #3  1 mole of water molecules will be: A. 18.02 grams B. 6.022x10 23 representative particles C. 3 atoms D. Both A and B E. Both A and C

16. QUESTION #3  1 mole of water molecules will be: A. 18.02 grams B. 6.022x10 23 representative particles C. 3 atoms D. Both A and B E. Both A and C

17. QUESTION #4 Given the following question, which of the equivalence statements below would you use to complete the conversion? Convert 5.033 moles of nitrogen gas, N 2, to grams of nitrogen gas. A. 1 mole of N 2 = 6.022 x 10 23 molecules of N 2 B. 1 mole of N 2 = 14.01 grams of N 2 C. 1 mole of N 2 = 28.02 grams N 2 D. 14.01 grams of N 2 = 6.022x10 23 molecules N 2

18. QUESTION #4 Given the following question, which of the equivalence statements below would you use to complete the conversion? Convert 5.033 moles of nitrogen gas, N 2, to grams of nitrogen gas. A. 1 mole of N 2 = 6.022 x 10 23 molecules of N 2 B. 1 mole of N 2 = 14.01 grams of N 2 C. 1 mole of N 2 = 28.02 grams N 2 D. 14.01 grams of N 2 = 6.022x10 23 molecules N 2

19. QUESTION #5  If you had 1 mole of O 2 molecules in a container. What other information will you automatically know about that sample based on the mole concept?

20. QUESTION #5  If you had 1 mole of O 2 molecules in a container. What other information will you automatically know about that sample based on the mole concept? The number of molecules, 6.022 x 10 23 molecules The mass, 31.998 grams

21. QUESTION #6 A student began answering the question below before getting stuck. What conversion factor would she put in this question? Do NOT solve. Convert 6.09 moles of Chlorine gas, Cl 2, to grams. 6.09 moles Cl 2 x _______________ = grams Cl 2

22. QUESTION #6 A student began answering the question below before getting stuck. What conversion factor would she put in this question? Do NOT solve. Convert 6.09 moles of Chlorine gas, Cl 2, to grams. 6.09 moles Cl 2 x _70.906 grams Cl 2____ = grams Cl 2 1 mole Cl 2

23. QUESTION #7 A student began answering the question below before getting stuck. What conversion factor would he put in this question? Do NOT solve. Convert 99.8 grams of silver to atoms of silver. 99.8 grams Ag x ________________ = atoms Ag

24. QUESTION #7 A student began answering the question below before getting stuck. What conversion factor would he put in this question? Do NOT solve. Convert 99.8 grams of silver to atoms of silver. 99.8 grams Ag x 6.022 x 10 23 atoms Ag = atoms Ag 107.87 grams Ag

25. STOICHIOMETRY

26. LET’S DO ONE TOGETHER CaH 2 + 2H 2 O  Ca(OH) 2 + 2H 2 Based on the equation above, calculate the moles of calcium hydroxide, Ca(OH) 2 produced by 38.09 grams of water and excess calcium hydride.

27. 1.058 moles Ca(OH) 2 CaH 2 + 2H 2 O  Ca(OH) 2 + 2H 2 Based on the equation above, calculate the moles of calcium hydroxide, Ca(OH) 2 produced by 38.09 grams of water and excess calcium hydride.

28. HOMEWORK  Both worksheets due at the beginning of next class