1. Module 7 Lesson 29 We will solve a variety of word problems involving area and perimeter using all four operations. MP 1: Make Sense of problems and persevere in solving them.

2. Problem of the Day Mrs. Bowcutt makes a quilt with an area of 64 square inches. She wants to trim the edge with lace. Can you figure out how much lace she will need? 64 square inches = 8 in x 8 in 8 + 8 + 8 + 8 = 32 inches Mrs. Bowcutt will need 32 inches of lace.

3. Multiply by 8 2 x 8 = _______ 7 x 8 = _____ 8 16 2432 48 40 56 64 72 80 9 x 8 = _______ 6 x 8 = _______ 4 x 8 = _______

4. Find the Perimeter On your white board or in your notebook, find the side lengths of the rectangle. 2 cm Perimeter = _____ Now find the perimeter. Write a number sentence if you need to. 14 cm Area = 10 square centimeters 5 cm

5. Find the Perimeter On your white board or in your notebook, find the length of the rectangle. 4 in Perimeter = _____ Now find the perimeter. Write a number sentence if you need to. 14 in Area = 12 square inches 3 in

6. Find the Perimeter On your white board or in your notebook, find the length of the rectangle. 3 m Perimeter = _____ Now find the perimeter. Write a number sentence if you need to. 22 m Area = 24 square meters 8 m

7. Concept Development O Today we are going to work on word problems involving AREA and PERIMETER. O How do we find AREA of a rectangle? O We MULTIPLY the two side lengths. O How do we find the PERIMETER of a rectangle? O We ADD all four side lengths. O Or we ADD 2L + 2W

8. Concept Development O To solve these problems we should use the Three-Step Approach to Solving – like we did yesterday. O Can anyone recall the steps we followed yesterday in solving our word problems?

9. Problem solving steps Read * Draw * Write 1.Read & Draw the problem Read the problem What can you draw? What conclusions can you make using the drawing? 2.Write & Solve an equation Use numbers to show your thinking and conclusions 3.Write a statement explaining your answer Use words to explain your answer and how it relates to the problem 4.Assess the reasonableness of your solution Ask yourself questions to make sure your answer makes sense: The question asks for … My answer matches the question because … The units I used make sense because … My answer is the right size (not too big or small) because …

10. Problem Solving You will need: Problem Set Pencil Your World Class Mathematician Skills!

11. Problem 1 Gia measures her rectangular garden and finds the width is 9 yards and the length is 7 yards. a. Estimate to draw Gia’s garden and label the side lengths. 8 in 7 yd 9 yd

12. Problem 1 Gia measures her rectangular garden and finds the width is 9 yards and the length is 7 yards. b. What is the area of Gia’s garden? 7 yd 9 yd Area = 63 square yards The area of Gia’s garden is 63 square yards. c. What is the perimeter of Gia’s garden? 7 + 7 + 9 + 9 = 14 + 18 = 32 yards The perimeter of Gia’s garden is 32 yards.

13. Problem 2 Elijah draws a square with side lengths of 8 centimeters. a. Estimate to draw Elijah’s square and label the side lengths. 8 in 8 cm

14. Problem 2 b. What is the area of Elijah’s Square? 8 cm Area = 64 square centimeters. c. What is the perimeter of Elijah’s square? 4 x 8 cm = 32 cm The perimeter of Elijah’s square is 32 yards. Elijah draws a square with side lengths of 8 centimeters. The area of Elijah’s square is 64 square centimeters.

15. Problem 3 The area of Mason’s rectangular painting is 72 square inches. The width of the painting is 8 inches. a. Estimate to draw Mason’s painting and label the side lengths. 8 in ? in. 8 in Area = 72 square inches

16. Problem 3 The area of Mason’s rectangular painting is 72 square inches. The width of the painting is 8 inches. b. What is the side length of the painting? 8 in 9 in. 8 in Area = 72 square inches

17. Problem 3 The area of Mason’s rectangular painting is 72 square inches. The width of the painting is 8 inches. c. What is the perimeter of the painting? 9 in. 8 in Area = 72 square inches (2 x 9) + (2 x 8) = 18 + 16 = 34 inches The perimeter of Mason’s painting is 34 square inches.

18. Problem 3 d.Mason’s mom hangs the painting on a wall that already has two of Mason’s other paintings. The areas of the other paintings are 64 square inches and 81 square inches. What is the total area of the wall covered with Mason’s paintings? 64 + 81 + 34 = 179 square inches Mason’s paintings cover 179 square inches of the wall. 64 square inches81 square inches 34 square inches

19. Problem 4 The perimeter of Jillian’s rectangular bedroom is 34 feet. The length of her bedroom is 9 feet. a. Estimate to draw Jillian’s bedroom and label the side lengths. 9 ft. ? ft. Perimeter = 34 feet Remember! Perimeter = (2 x L) + (2 x W)

20. Problem 4 The perimeter of Jillian’s rectangular bedroom is 34 feet. The length of her bedroom is 9 feet. b. What is the width of Jullian’s bedroom? 9 ft. ? ft. Perimeter = 34 feet Remember! Perimeter = (2 x L) + (2 x W) Side lengths = ½ 34 = 9 + W = 17 = 9 + W = 17 = 9 + 8 Jillian’s bedroom is 8 feet wide.

21. Problem 4 The perimeter of Jillian’s rectangular bedroom is 34 feet. The length of her bedroom is 9 feet. c. What is the area of Jullian’s bedroom? 9 ft. 8 ft. Area = 8 x 9 = 72 square feet The area of Jillian’s bedroom is 72 square feet.

22. Problem 4 d.Jillian has a 4-foot by 6-foot rug in her room. What is the area of the floor that is not covered by the rug? 9 ft. 8 ft. What information can we use to figure out how much floor is NOT covered by the rug? We know the room is 72 square feet. We can use the side lengths of the rug to figure out its area 6 ft 4 ft

23. Problem 4 d.Jillian has a 4-foot by 6-foot rug in her room. What is the area of the floor that is not covered by the rug? 9 ft. 8 ft. 72 – 24 = 48 square feet. The area not covered by the rug is 48 square feet. 6 ft 4 ft

24. Exit Ticket for this lesson: Next to your name write and circle the number of problems you were able to solve on your own. Example:You got all 4 problems right with no help: 4 You got 2 problems right on your own, but needed to correct 2 when we went over them: 2