1. Pen Tool McGraw-Hill Ryerson Pre-Calculus 11 Chapter 1 Sequences and Series Section 1.3 Click here to begin the lesson

2. Pen Tool McGraw-Hill Ryerson Pre-Calculus 11 Teacher Notes 1. This lesson is designed to help students conceptualize the main ideas of Chapter 1. 2. To view the lesson, go to Slide Show > View Show (PowerPoint 2003). 3. To use the pen tool, view Slide Show, click on the icon in the lower left of your screen and select Ball Point Pen. 4. To reveal an answer, click on or follow the instructions on the slide. To reveal a hint, click on. To view the complete solution, click on the View Solution button. Navigate through the lesson using the and buttons. 5. When you exit this lesson, do not save changes.

3. Pen Tool Geometric Sequences In a geometric sequence, the ratio of consecutive terms is a constant. This constant is called the common ratio. Chapter 1 13, 26, 52, 104, 208,... 84, 72, 60, 48, 36,... 5, 11, 17, 23, 29,... 5, 10, 20, 40, 80,... 100, 80, 64, 51.2, 40.96,... Which of the following is a geometric sequence? Use the pen tool to indicate your choice by placing a in the box.

4. Pen Tool Geometric Sequences For each of the following geometric sequences, state the common ratio and the general term in the form t n = t 1 r n – 1. Chapter 1 Geometric Sequence Common Ratio AnswersGeneral TermAnswers 4, –8, 16, –32,...–2t n = 4(–2) n – 1 100, 20, 4, 0.8,...0.2t n = 100(0.2) n – 1 80, 40, 20, 10,...0.5t n = 80(0.5) n – 1 2, 8, 32, 128,...4t n = 2(4) n – 1

5. Pen Tool Geometric Sequences Janice is enlarging an image using computer software. The length of the image is 150 pixels and the enlargement she makes is 110% of the original. What is the length of the image after 4 enlargements? Express your answer to the nearest pixel. Chapter 1 Click here for the solution. Answer The length of the image after 4 enlargements is 220 pixels.

6. Pen Tool The following pages contain solutions for the previous questions. Click here to return to the start

7. Pen Tool Solutions t 1 = 150 r = 1.1 n = 5 t n = t 1 r n – 1 t 5 = 150(1.1) 5 – 1 t 5 = 150(1.1) 4 t 5 ≈ 219.6 The length of the image after 4 enlargements is approximately 220 pixels. Go back to the question