Quantum Theory and the Electronic Structure of Atoms

Quantum Theory and the Electronic Structure of Atoms
Chapter 7

Relationship of Quantum Theory and role of electrons
In chemistry, the role of electrons in an atom is understood better by the quantum theory -How many electrons are present in a particular atom -What energies do individual electrons possess -Where in the atom can electrons be found 2

The Wave Nature of Light
A wave can be characterized by its wavelength and frequency. The wavelength, l (lambda), is the distance between any two adjacent identical points of a wave. The frequency, n (nu), of a wave is the number of wavelengths that pass a fixed point in one second. 2

Properties of Waves Wavelength (l) is the distance between identical points on successive waves. Amplitude is the vertical distance from the midline of a wave to the peak or trough. Frequency (n) is the number of waves that pass through a particular point in 1 second (Hz = 1 cycle/s). The speed (u) of the wave = l x n

The product of the frequency, n and the wavelength, l would give the speed of the wave in m/s. In a vacuum, the speed of light, c, is 3.00 x 108 m/s. Therefore, So, given the frequency of light, its wavelength can be calculated, or vice versa. 2

Speed of light (c) in vacuum = 3.00 x 108 m/s
Maxwell (1873), proposed that visible light consists of electromagnetic waves. Electromagnetic radiation is the emission and transmission of energy in the form of electromagnetic waves. Speed of light (c) in vacuum = 3.00 x 108 m/s All electromagnetic radiation ln = c

What is the wavelength of yellow light with a frequency of 5.09 x 1014 s-1? (Note: s-1, commonly referred to as Hertz (Hz) is defined as “cycles or waves per second”.) If c = nl, then rearranging, we obtain l = c/n 2

What is the frequency of violet light with a wavelength of 408 nm? If c = nl, then rearranging, we obtain n = c/l. 2

The range of frequencies or wavelengths of electromagnetic radiation is called the electromagnetic spectrum. Visible light extends from the violet end of the spectrum at about 400 nm to the red end with wavelengths about 800 nm. Beyond these extremes, electromagnetic radiation is not visible to the human eye. 2

high energy short low energy wavelength long wavelength
Electromagnetic Spectrum high energy short wavelength low energy long wavelength

l x n = c l = c/n l = 3.00 x 108 m/s / 6.0 x 104 Hz l = 5.0 x 103 m
A photon has a frequency of 6.0 x 104 Hz. Convert this frequency into wavelength (nm). Does this frequency fall in the visible region? l n l x n = c l = c/n l = 3.00 x 108 m/s / 6.0 x 104 Hz l = 5.0 x 103 m l = 5.0 x 1012 nm Radio wave

Quantum Effects and Photons
Planck’s Quantization of Energy (1900) According to Max Planck, when solids are heated, they emit electromagnetic radiation over a wide range of wavelengths. where h (Planck’s constant) is assigned a value of 6.63 x J. s He proposed that an atom could emit or absorb energy only in discrete quantities, like small packages, and quantum is the smallest quantity of that energy for electromagnetic radiation. The energy E, of a single quantum of energy is given by, 2

By the early part of twentieth century, the wave theory of light seemed to be well entrenched. In 1905, Albert Einstein proposed that light had both wave and particle properties as observed in the photoelectric effect Einstein based this idea on the work of Max Planck. 2

Photoelectric Effect The energy of the photons proposed by Einstein would be proportional to the observed frequency, and the proportionality constant would be Planck’s constant. In 1905, Einstein used this concept to explain the “photoelectric effect.” 2

Photoelectric Effect The photoelectric effect is the ejection of electrons from the surface of a metal when light shines on it. Electrons are ejected only if the light exceeds a certain “threshold” frequency. Violet light, for example, will cause potassium to eject electrons, but no amount of red light (which has a lower frequency) has any effect. 2

Photoelectric Effect Einstein’s assumption that an electron is ejected when struck by a single photon implies that it behaves like a particle. When the photon hits the metal, its energy, hn is taken up by the electron. The photon ceases to exist as a particle; it is said to be “absorbed.” 2

Photoelectric Effect The “wave” and “particle” pictures of light should be regarded as complementary views of the same physical entity. This is called the wave-particle duality of light. The equation E = hn displays this duality; E is the energy of the “particle” photon, and n is the frequency of the associated “wave.” 2

Photon is a “particle” of light
hn Light has both: wave nature particle nature KE e- Photon is a “particle” of light hn = KE + W KE = hn - W

E = 6.63 x 10-34 (J•s) x 3.00 x 10 8 (m/s) / 0.154 x 10-9 (m)
When copper is bombarded with high-energy electrons, X rays are emitted. Calculate the energy (in joules) associated with the photons if the wavelength of the X rays is nm. E = h x n E = h x c / l E = 6.63 x (J•s) x 3.00 x 10 8 (m/s) / x 10-9 (m) E = 1.29 x J

Radio Wave Energy (6.626 x 10-34 J.s) x (1.255 x 106 s-1) =
What is the energy of a photon corresponding to radio waves of frequency x 10 6 s-1? Solve for E, using E = hn, and four significant figures for h. (6.626 x J.s) x (1.255 x 106 s-1) = 8.316 x J 13

The Bohr Theory of the Hydrogen Atom
Prior to the work of Niels Bohr, the stability of the atom could not be explained using the then-current theories. In 1913, using the work of Einstein and Planck, he applied a new theory to the simplest atom, hydrogen. Before looking at Bohr’s theory, we must first examine the “line spectra” of atoms. 2

Atomic Line Spectra When a heated metal filament emits light, we can use a prism to spread out the light to give a continuous spectrum-that is, a spectrum containing light of all wavelengths. The light emitted by a heated gas, such as hydrogen, results in a line spectrum-a spectrum showing only specific wavelengths of light. 2

Line Emission Spectrum of Hydrogen Atoms

The emission spectrum of hydrogen lead to the modern understanding of the electronic structure of the atom. emission spectrum - light emitted when a substance is excited by an energy source.

n (principal quantum number) = 1,2,3,…
Bohr’s Model of the Atom (1913) e- can only have specific (quantized) energy values light is emitted as e- moves from one energy level to a lower energy level En = -RH ( ) 1 n2 n (principal quantum number) = 1,2,3,… RH (Rydberg constant) = 2.18 x 10-18J

The Bohr Atom 8 Initial understanding of the atom by Niels Bohr
Electrons exist in fixed energy levels surrounding the nucleus. Quantization of energy Promotion of electron occurs as it absorbs energy Excited State Energy is released as the electron travels back to lower levels. Relaxation

Orbit - what Bohr called the fixed energy levels.
Ground state - the lowest possible energy state.

n = 1, 2, 3, … The orbits are also identified using “quantum numbers”
When the electron relaxes (c) the energy released is observed as a single wavelength of light.

E = hn E = hn

Bohr’s Postulates Bohr set down postulates to account for (1) the stability of the hydrogen atom and (2) the line spectrum of the atom. 1. Energy level postulate An electron can have only specific energy levels in an atom. 2. Transitions between energy levels An electron in an atom can change energy levels by undergoing a “transition” from one energy level to another. 2

Bohr’s Postulates Bohr derived the following formula for the energy levels of the electron in the hydrogen atom. Rh is a constant (expressed in energy units) with a value of 2.18 x J. 2

Bohr’s Postulates When an electron undergoes a transition from a higher energy level to a lower one, the energy is emitted as a photon. From Postulate 1, 2

Bohr’s Postulates If we make a substitution into the previous equation that states the energy of the emitted photon, hn, equals Ei - Ef, Rearranging, we obtain 2

Bohr’s Postulates Bohr’s theory explains not only the emission of light, but also the absorbtion of light. When an electron falls from n = 3 to n = 2 energy level, a photon of red light (wavelength, 685 nm) is emitted. When red light of this same wavelength shines on a hydrogen atom in the n = 2 level, the energy is gained by the electron that undergoes a transition to n = 3. 2

A Problem to Consider Calculate the energy of a photon of light emitted from a hydrogen atom when an electron falls from level n = 3 to level n = 1. 2

( ) ( ) ( ) Ephoton = DE = Ef - Ei 1 Ef = -RH n2 1 Ei = -RH n2 1
nf = 1 ni = 3 nf = 2 ni = 3 Ef = -RH ( ) 1 n2 f nf = 1 ni = 2 Ei = -RH ( ) 1 n2 i i f DE = RH ( ) 1 n2

Why is e- energy quantized?
De Broglie (1924) reasoned that e- is both particle and wave. l = h mu u = velocity of e- m = mass of e-

Quantum Mechanics Bohr’s theory established the concept of atomic energy levels but did not thoroughly explain the “wave-like” behavior of the electron. Current ideas about atomic structure depend on the principles of quantum mechanics, a theory that applies to subatomic particles such as electrons. 2

Quantum Mechanics The first clue in the development of quantum theory came with the discovery of the de Broglie relation. In 1923, Louis de Broglie reasoned that if light exhibits particle aspects, perhaps particles of matter show characteristics of waves. He postulated that a particle with mass m and a velocity v has an associated wavelength. The equation l = h/mv is called the de Broglie relation. 2

Quantum Mechanics If matter has wave properties, why are they not commonly observed? The de Broglie relation shows that a baseball (0.145 kg) moving at about 60 mph (27 m/s) has a wavelength of about 1.7 x m. This value is so incredibly small that such waves cannot be detected. 2

Quantum Mechanics If matter has wave properties, why are they not commonly observed? Electrons have wavelengths on the order of a few picometers (1 pm = m). Under the proper circumstances, the wave character of electrons should be observable. 2

What is the de Broglie wavelength (in nm) associated with a 2
What is the de Broglie wavelength (in nm) associated with a 2.5 g Ping-Pong ball traveling at 15.6 m/s? l = h/mu h in J•s m in kg u in (m/s) l = 6.63 x kg.m2 /s (2.5 x 10-3kg x 15.6 m/s) l = 1.7 x m = 1.7 x nm

Chemistry in Action: Electron Microscopy
A light microscope uses visible light and an arrangement of lenses to magnify images of small samples. While an electron microscope uses a particle beam of electrons to illuminate the specimen and produce a magnified image and has a greater resolving power.

Schrodinger Wave Equation
In 1926 Schrodinger wrote an equation that described both the particle and wave nature of the e- Wave function (Y) describes: . energy of e- with a given Y . probability of finding e- in a volume of space Schrodinger’s equation can only be solved exactly for the hydrogen atom. Must approximate its solution for multi-electron systems.

Quantum Mechanics Heisenberg’s uncertainty principle it is impossible to know both position and velocity simultaneously. . 2

Quantum Mechanics Although we cannot precisely define an electron’s orbit, we can obtain the probability of finding an electron at a given point around the nucleus. Erwin Schrodinger defined this probability in a mathematical expression called a wave function, denoted y (psi). The probability of finding a particle in a region of space is defined by y2. 2

Quantum Numbers and Atomic Orbitals
According to quantum mechanics, each electron is described by four quantum numbers. Principal quantum number (n) (main levels) Angular momentum quantum number (l) (shape) Magnetic quantum number (ml) (orientation) Spin quantum number (ms) (electron spin) 2

Arrangement of Electrons in Atoms
Electrons in atoms are arranged as SHELLS (n) SUBSHELLS (l) ORBITALS (ml)

Arrangement of Electrons in Atoms
Each orbital can be assigned no more than 2 electrons! This is tied to the existence of a 4th quantum number, the electron spin quantum number, ms.

Electron Spin Quantum Number, ms
Can be proved experimentally that electron has a spin. Two spin directions are given by ms where ms = +1/2 and -1/2.

Electron Spin Quantum Number
Diamagnetic: NOT attracted to a magnetic field Paramagnetic: substance is attracted to a magnetic field. Substance has unpaired electrons.

QUANTUM NUMBERS n ---> shell 1, 2, 3, 4, ...
l ---> subshell 0, 1, 2, ... n - 1 ml ---> orbital for a given value of l, ml = -l, …., 0, …. +l

QUANTUM NUMBERS Sublevel, l = 0 to n-1 If n=1, l = 0 n=2, l =0,1

l ---> subshell 0, 1, 2, ... n - 1 ml ---> orbital for a given value of l, ml = -l, …., 0, …. +l If l = 1, ml = -l , 0 , +l; if l = 2, ml = -2,-1,0,+1,+2 if l = 3, ml = ? ms ---> electron spin +1/2 and -1/2

l ---> subshell 0, 1, 2, ... n - 1 ml ---> orbital -l l ms ---> electron spin +1/2 and -1/2

Schrodinger Wave Equation
principal quantum number n n = 1, 2, 3, 4, …. distance of e- from the nucleus n=1 n=2 n=3

Quantum Numbers and Atomic Orbitals
The principal quantum number(n) represents the “shell number” in which an electron “resides.” The larger the n is, the greater the distance of the electron in the orbital from the nucleus the larger the orbital. Higher the energy 2

Electron Density

Quantum Numbers (n, l, ml, ms)
n – principal quantum number (main energy level) l - angular momentum quantum number (sublevel) ml – magnetic quantum number ms – electron spin quantum number

Quantum Numbers l = 0 to ( n-1) n = 1, l = 0 n = 2, l = 0, 1
l = s orbital l = p orbital l = d orbital l = f orbital Ml = 2l + 1

l = 0 (s orbitals) l = 1 (p orbitals)

l = 2 (d orbitals)

Pauli Exclusion Principle
No two electrons in the same atom can have the same set of 4 quantum numbers. That is, each electron in an atom has a unique address of quantum numbers.

Electrons in Atoms TOTAL = 8e- When n = 1, then l = 0
this shell has a single orbital (1s) to which 2e- can be assigned. When n = 2, then l = 0, 1 2s orbital e- three 2p orbitals 6e- TOTAL = 8e-

Electrons in Atoms five 3d orbitals 10e- TOTAL = 18e-
When n = 3, then l = 0, 1, 2 3s orbital e- three 3p orbitals 6e- five 3d orbitals 10e- TOTAL = e-

Electrons in Atoms five 4d orbitals 10e- TOTAL = 32e-
When n = 4, then l = 0, 1, 2, 3 4s orbital e- three 4p orbitals 6e- five 4d orbitals 10e- seven 4f orbitals 14e- TOTAL = 32e-

Assigning Electrons to Atoms
Electrons generally assigned to orbitals of successively higher energy. For H atoms, E = - C(1/n2). E depends only on n. For many-electron atoms, energy depends on both n and l.

( ) Energy of orbitals in a single electron atom (H) 1 En = -RH n2
Energy only depends on principal quantum number n n=3 n=2 En = -RH ( ) 1 n2 n=1

Order of orbitals (filling) in multi-electron atom
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s

Energy of orbitals in a multi-electron atom
Energy depends on n and l n=3 l = 2 n=3 l = 1 n=3 l = 0 n=2 l = 1 n=2 l = 0 e- in 4s less energy, more stable than 3d n=1 l = 0

Orbital Energy Levels in Multi-electron Systems
3d 4s 3p 3s Energy 2p 2s 1s 3

in the orbital or subshell
Electron configuration is how the electrons are distributed among the various atomic orbitals in an atom. number of electrons in the orbital or subshell 1s1 principal quantum number n angular momentum quantum number l Orbital diagram 1s1 H

Aufbau Principle Here are a few examples.
Using the abbreviation [He] for 1s2, the configurations are Z=4 Beryllium 1s22s2 or [He]2s2 Z=3 Lithium 1s22s1 or [He]2s1 2

Aufbau Principle With boron (Z=5), the electrons begin filling the 2p subshell. Z=5 Boron 1s22s22p1 or [He]2s22p1 Z=6 Carbon 1s22s22p2 or [He]2s22p2 Z=7 Nitrogen 1s22s22p3 or [He]2s22p3 Z=8 Oxygen 1s22s22p4 or [He]2s22p4 Z=9 Fluorine 1s22s22p5 or [He]2s22p5 Z=10 Neon 1s22s22p6 or [He]2s62p6 2

Aufbau Principle With sodium (Z = 11), the 3s sub shell begins to fill. Z=11 Sodium 1s22s22p63s1 or [Ne]3s1 Z=12 Magnesium 1s22s22p63s2 or [Ne]3s2 Then the 3p sub shell begins to fill. Z=13 Aluminum 1s22s22p63s23p1 or [Ne]3s23p1 [Ne]3s23p6 or 1s22s22p63s23p6 Argon Z=18 2

Aufbau Principle The “building up” order corresponds for the most part to increasing energy of the subshells. By filling orbitals of the lowest energy first, you usually get the lowest total energy (“ground state”) of the atom. Now you can see how to reproduce the electron configurations of Table 7.3 using the Aufbau principle. Remember, the number of electrons in the neutral atom equals the atomic number, Z. 2

What is the electron configuration of Mg?
Mg 12 electrons 1s < 2s < 2p < 3s < 3p < 4s 1s22s22p63s2 = 12 electrons Abbreviated as [Ne]3s2 [Ne] 1s22s22p6 What are the possible quantum numbers for the last (outermost) electron in Cl? Cl 17 electrons 1s < 2s < 2p < 3s < 3p < 4s 1s22s22p63s23p5 = 17 electrons Last electron added to 3p orbital n = 3 l = 1 ml = -1, 0, or +1 ms = ½ or -½

Outermost subshell being filled with electrons

Configurations and the Periodic Table
Note that elements within a given family have similar configurations. For instance, look at the noble gases. Helium 1s2 Neon 1s22s22p6 Argon 1s22s22p63s23p6 Krypton 1s22s22p63s23p63d104s24p6 2

Note that elements within a given family have similar configurations. The Group IIA elements are sometimes called the alkaline earth metals. Beryllium 1s22s2 Magnesium 1s22s22p63s2 Calcium 1s22s22p63s23p64s2 2

Electrons that reside in the outermost shell of an atom - or in other words, those electrons outside the “noble gas core”- are called valence electrons. These electrons are primarily involved in chemical reactions. Elements within a given group have the same “valence shell configuration.” This accounts for the similarity of the chemical properties among groups of elements. 2

The following slide illustrates how the periodic table provides a sound way to remember the Aufbau sequence. In many cases you need only the configuration of the outer electrons. You can determine this from their position on the periodic table. The total number of valence electrons for an atom equals its group number. 2

Hund’s Rule Hund's rule: every orbital in a subshell is singly occupied with one electron before any one orbital is doubly occupied, and all electrons in singly occupied orbitals have the same spin

Shielding Effect The shielding effect describes the decrease in attraction between an electron and the nucleus in any atom with more than one electron shell For the same n, the shielding effect increases in the electron as, s<p<d<f Electron in s more closer to nucleus than p.

Homework ch-7 Examples and practice exercises
7.8,7.16,7.20,7.28,7.34,7.48,7.56,7.58,7.61,7.65,7.69,7.70,7.72,7.74,7.76,7.78,7.79,7.89,7.92,7.98,7.130

Quantum Theory and the Electronic Structure of Atoms

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