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CHAPTER 3 The Experimental Basis of Quantum Physics
3.1 Discovery of the X Ray and the Electron 3.2 Determination of Electron Charge 3.3 Line Spectra 3.4 Quantization 3.5 Blackbody Radiation 3.6 Photoelectric Effect 3.7 X-Ray Production 3.8 Compton Effect 3.9 Pair Production and Annihilation All related to quantization Quantum mechanics
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Quantum? Quantum mechanics?
Quantum is the Latin word for amount and, in modern understanding, means the smallest possible discrete unit of any physical property, such as energy or matter. (WhatIs.com) (quantus = how much, quantum = noun form of quantus) Quantum : 1.양자 2.몫 3.분량 (Daum 영어사전) What are quantized? Energy (discrete energy levels), mass & charge quantization
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Quantum mechanics Classical theory Why are things quantized?
Relativity Why are things quantized? ??? Size Quantum mechanics Why is QM important here? Quantization is more visible in microscopic world Practically, quantum effect easily observable for… Electrons (thus atoms) and light. Speed
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Contents … Chapter 3 : The Experimental Basis of Quantum Physics
Chapter 4 : Structure of the Atom Chapter 5 : Wave Properties of Matter and Quantum Mechanics I Chapter 6 : Quantum Mechanics II Chapter 7 : The Hydrogen Atom Chapter 8 : Atomic Physics
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X Ray “Cathode rays” well known to scientists (first observed by Johann Hittorf in 1869) They are something to do with atoms Their properties were under intense investigation during the 1890s. X-ray discovered by Röntgen in 1895, 1901 Nobel prize in physics
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J. J. Thomson’s Cathode-Ray Experiment (1897)
Cathode rays – particles (Thomson) or wave (Hertz)? Cathode rays were negatively charged particles Discovery of electrons (1897)
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Thomson’s experiment to determine e/m
Send electrons through a region containing a magnetic field perpendicular to an electric field 1906 Nobel prize
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Calculation of e/m An electron moving through the electric field is accelerated by a force: Electron angle of deflection: The magnetic field deflects the electron against the electric field force. The magnetic field is adjusted until the net force is zero. Charge to mass ratio:
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3.2: Determination of Electron Charge
Millikan oil drop experiment
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Calculation of the oil drop charge
Used an electric field and gravity to suspend a charged oil drop Magnitude of the charge on the oil drop Mass is determined from Stokes’s relationship of the terminal velocity to the radius and density Thousands of experiments showed that there is a basic quantized electron charge C
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3.3: Line Spectra Chemical elements produce unique wavelengths of light when burned or excited in an electrical discharge. Advances in grating technology key to the success (Henry Rowland) Thousands of ruling lines per cm
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Optical Spectrometer Diffraction creates a line spectrum pattern of light bands and dark areas on the screen. Wavelengths of these line spectra allow identification of the chemical elements and the composition of materials.
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Balmer Series nm (where k = 3,4,5… and k > 2)
In 1885, Johann Balmer found an empirical formula for wavelength of the visible hydrogen line spectra in nm: nm (where k = 3,4,5… and k > 2)
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Rydberg Equation As more scientists discovered emission lines at infrared and ultraviolet wavelengths, the Balmer series equation was extended to the Rydberg equation: (n = 2)
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3.5: Blackbody Radiation
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Equivalence of blackbody and hole on cavity
looks like is equivalent to Blackbody Light that goes in through the hole never comes out This is as if it is fully absorbed => blackbody Hole = blackbody
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Emission power from the hole & radiation energy in the cavity
This is what we can calculate This is what we want to know Radiation energy density u(l,T) Emission power density I(l,T) I(l,T) = c u(l,T), where c is a geometrical factor (independent of l and T) The blackbody radiation problem reduces to calculation of u(l,T)
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Expected energy of a mode
There are light waves with different wave lengths However, only standing wave-like modes are allowed in the cavity Let’s focus on this particular mode (blue)… Each mode is equivalent to a vibrating string Or a pendulum (oscillator) = = Wave length (l) or frequency (n) of the mode is fixed However, the amplitude A can be varied Energy of the mode is proportional to A2, E A2 Since A can be of any value, E is continuous
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Mode & oscillator & mean energy
Mean energy (energy expectation value) <E>? E large E ~ 0 Energy continuous, anywhere between 0 and infinity Nature prefers lower energy Boltzmann told us that the probability ratio between states with energy E1 and E2 is P1/P2=exp[-(E1-E2)/kBT] Energy expectation <E> = kBT (equi-partition theorem) Energy E Probability density p(E)
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Counting # of modes ky kx The volume between k and k+dk is 4pk2dk
# of modes within the volume is (4pk2dk)/(p/L)3 Let us N(l)dl be the # of modes within l and l+dl Then, N(l)dl = (4pk2dk)/(p/L)3 or N(l)=(4k2L3/p2)(dk/dl) N(l)=(16L3/l2)(2p/l2)=32pL3/l4
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Rayleigh-Jeans Formula
I(l,T) = c u(l,T) u(l,T) = (# of modes within l and l+dl) x (energy expectation of each mode) = N(l) x kBT “The ultraviolet catastrophe”, one of the outstanding exceptions that classical physics could not explain.
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Planck’s trick h = 6.6261 × 10−34 J·s
Don’t like probability ‘density’ and integration Energy E Probability density p(E) Energy E Probability Pn(En) To get the result for continuous energy, simply send h 0. Planck found that h=finite fits the data! h = × 10−34 J·s
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3.6: Photoelectric Effect
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Experimental Results
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3.7: X-Ray Production In a sense, an inverse process of photoelectric effect An energetic electron passing through matter will radiate photons and lose kinetic energy Bremsstrahlung, The final energy of the electron determined from the conservation of energy is There is maximum frequency (minimum wave length) for given electron kinetic energy
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Inverse Photoelectric Effect
Duane-Hunt limit : the limit in the X-ray wave length The photon wavelength depends only on the accelerating voltage and is the same for all targets.
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Compton effect
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