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Module 7: Genetics Notes
Who is Gregor Mendel? Principle of Independent Assortment: The inheritance of one trait has no effect on the inheritance of another trait. The “Father of Genetics” Contemporary Approaches to Genetics. Module 7. Genetic Notes ©2013 Educurious Partners. All rights reserved.
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Traits Genetics: The study of how traits are passed from parent to offspring. Examples: dimples in your cheek and chin, curly hair, eye color, etc.
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Traits are determined by the genes on the chromosomes
Traits are determined by the genes on the chromosomes. A gene is a segment of DNA that determines a trait. Might determine your eye color Centromere Might determine your predisposition to Type I Diabetes Image adapted from and
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Chromosomes come in homologous pairs, so genes come in pairs.
Homologous pairs have matching genes – one from the female parent and one from male parent. Example: Humans have 46 chromosomes, or 23 pairs. One set from dad: 23 in sperm One set from mom: 23 in egg
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One pair of homologous chromosomes:
Gene for earlobe (detached earlobe) Image from Gene for earlobe (attached earlobe) Alleles: Different genes (possibilities) for the same trait. Example: attached or detached earlobes
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Dominant and Recessive Genes
A gene that prevents the other gene from “showing” is dominant. A gene that does NOT “show” even though it is present is recessive. Symbols for dominant gene: uppercase letter – T recessive gene: lowercase letter – t Image from Dominant color (black and white) Recessive color (white)
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Important: Always use the same letter to represent alleles.
Example: Straight thumb is dominant to hitchhiker’s thumb T = straight thumb t = hitchhiker’s thumb Important: Always use the same letter to represent alleles. For example, DON’T use S = straight, h = hitchhiker’s Straight thumb = TT Straight thumb = Tt *Hitchhiker’s thumb = tt *You must have 2 recessive alleles for a recessive trait to “show.”
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Both genes of a pair are the same: homozygous or purebred
TT – homozygous dominant tt – homozygous recessive One dominant and one recessive gene: heterozygous or hybrid Tt – heterozygous Images from BB – Black Bb – Black w/ brown gene bb – brown
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Genotype and Phenotype
Combination of genes an organism has (actual gene makeup): genotype Example: TT, Tt, tt Physical appearance resulting from gene makeup: phenotype Example: green eyes or not green eyes Images from
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Punnett Squares and Probability
Used to predict the possible gene makeup of offspring: Punnett square Example: Black fur (B) is dominant to white fur (b) in mice Cross a heterozygous male with a homozygous recessive female. Black fur (B) White fur (b) Heterozygous male Homozygous recessive female Images created by Educurious. White fur (b) White fur (b)
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Male = Bb X Female = bb Bb b bb B Female gametes: N (One gene in egg)
Possible offspring: 2N Male gametes: N (One gene in sperm) Write the ratios in the following orders: Genotypic ratio homozygous : heterozygous : homozygous dominant recessive Phenotypic ratio dominant : recessive Genotypic ratio = 2 Bb : 2 bb 50% Bb : 50% bb Phenotypic ratio = 2 black : 2 white 50% black : 50% white
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Now it’s your turn: Cross 2 hybrid mice and give the genotypic ratio and phenotypic ratio:
Bb X Bb B b BB Bb bb B b Genotypic ratio = 1 BB : 2 Bb : 1 bb 25% BB : 50% Bb : 25% bb Phenotypic ratio = 3 black : 1 white 75% black : 25% white
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Bb X Bb Man = Bb Woman = Bb B b BB Bb bb B b
Example: A man and woman, both with brown eyes (B), have a blue-eyed (b) child. What are the genotypes of the man, woman and child? Bb X Bb Man = Bb Woman = Bb B b BB Bb bb B b
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Crossing involving 2 traits: Dihybrid crosses
Example: In rabbits, a black coat (B) is dominant over brown (b), and straight hair (H) is dominant to curly (h). Cross 2 hybrid rabbits and give the phenotypic ratio for the first generation of offspring. Possible gametes: BbHh X BbHh BH BH Bh Bh bH bH bh bh Gametes BH Bh bH bh BBHH BBHh BbHH BbHh BBhh Bbhh bbHH bbHh bbhh Phenotypes - 9:3:3:1 9 black and straight 3 black and curly 3 brown and straight 1 brown and curly
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BBHH X BBHh BH Bh BBHH BBHh
Example: In rabbits, a black coat (B) is dominant over brown (b), and straight hair (H) is dominant to curly (h). Cross a rabbit that is homozygous dominant for both traits with a rabbit that is homozygous dominant for a black coat and heterozygous for straight hair. Then give the phenotypic ratio for the first generation of offspring. BBHH X BBHh Possible gametes: BH BH Bh BH Bh Gametes Phenotypes: BBHH BBHh 100% black and straight Gametes (Hint: Only design Punnett squares for the number of possible gametes.)
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Sex Determination People: 46 chromosomes or 23 pairs
22 pairs are homologous (look alike) – called autosomes – these determine body traits 1 pair is the sex chromosomes – it determines sex (male or female) Females – sex chromosomes are homologous (look alike): label XX Males – sex chromosomes are different: label XY This is a sequence of a male’s DNA. See the XY chromosome? Image from
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Incomplete Dominance and Codominance
When one allele is NOT completely dominant over another (they blend) the result is incomplete dominance. Example: In carnations, the color red (R) is incompletely dominant over white (W). The hybrid color is pink. Give the genotypic and phenotypic ratio from a cross between 2 pink flowers. RW X RW R W RR RW WW R Image adapted from W Genotypic = RR : 2 RW : 1 WW Phenotypic = 1 red : 2 pink : 1 white
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When both alleles are expressed the result is codominance.
Example: In certain chickens, black feathers are codominant with white feathers. Heterozygous chickens have black-and-white speckled feathers. Image from
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Sex-linked Traits Genes for these traits are located only on the X chromosome (NOT on the Y chromosome). X-linked alleles always show up in males, whether dominant or recessive, because males have only one X chromosome.
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Examples of recessive, sex-linked disorders:
Colorblindness: the inability to distinguish between certain colors You should see a pink P. Image from Color blindness is the inability to distinguish the differences between certain colors. The most common type is red-green color blindness, where red and green are seen as the same color.
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XN Xn XNXN XNXn XNY XnY XN Y
Example: Give the expected phenotypes of the children of a female who has normal vision but is a carrier for colorblindness, and a male with normal vision. N = normal vision n = colorblindness XN X XN Y XN Xn XNXN XNXn XNY XnY XN Image from Y Phenotype: 2 normal vision females 1 normal vision male 1 colorblind male
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2. hemophilia: blood won’t clot
Image from - openly available
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