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Unit III - Acid/Base - Chapter 15
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15. x. Relate [H+], [OH-], and Kw in an aqueous solution. [Readings 17
15.x. Relate [H+], [OH-], and Kw in an aqueous solution. [Readings 17.2,17.6 Problems 2]
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15.1. Define acids and bases in terms of Arrhenius and Brönsted-Lowry theories and identify the conjugate acid-base pairs. [Readings Problems]
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Arrhenius Theory of Acids/Bases
Acid -- H+ in water solution Base -- OH- in water solution Works well for substances like NaOH and HCl What about NH3?
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Brönsted-Lowry Theory of Acids/Bases (1923)
Acid -- Proton Donor Base -- Proton Acceptor
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HCl (aq) <=> H+ (aq) + Cl- (aq) -or-
Hydrolysis Reactions HCl (aq) <=> H+ (aq) + Cl- (aq) -or- H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid hydrolysis HCl is the proton donor, thus the acid H2O is the proton acceptor, thus, the Bronsted-Lowry base
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Conjugate Acid-Base Pairs
H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) Species that differ only by a proton are conjugates of each other Cl - is the conjugate base of HCl H2O is the conjugate base of H3O+
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Practice Write the balanced equation of NH3 dissolving in water.
NH3 + H2O ––> NH OH- Identify the conjugate acid-base pair H2O and OH- Identify the conjugate base-acid pair NH3+ and NH4+
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Auto Ionization of water
H2O(l) <==> H+(aq) + OH-(aq) Kw = [H+] [OH-] = 1.0 x @ 25°C in pure water [H+] = [OH-] = 1.0 x 10-7 M at this concentration only one water molecule in 556 million is ionized.
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[H+] = 10-7 M neutral [OH-] = 10-7 M
Kw = [H+] [OH-] = 1.0 x 10-14 [H+] = 10-7 M neutral [OH-] = 10-7 M increase [H+] [H+] > 10-7 M acid [OH-] < 10-7 M increase [OH-] [H+] < 10-7 M base [OH-] > 10-7 M
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What is the nature of H+(aq)
Hydronium Ion H O H O + H H - O O H H
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Alternative View H O hydrated proton + H H3O hydronium ion
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H+ H3O+ H2O(l) <==> H+(aq) + OH-(aq) Kw = [H+] [OH-] = 1.0 x @ 25°C H2O(l) + H2O(l) <==> H3O+(aq) + OH-(aq) Kw = [H3O+] [OH-] = 1.0 x @ 25°C
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Why Not.... H5O2+ H O + H O H
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Why Not.... H7O3+ . H O + H H O H O H O H
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3.2. Determine the pH of an aqueous solution from the [H+] (or the [OH-]) and vv. [Readings 17.6 Problems 32,34,36]
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pH - a shorthand method of expressing [H+] of dilute solutions
pH = -log [H+] pH of pure water? [H+]=1x10-7 pH = -log (1x10-7) pH = 7
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Kw = [H+] [OH-] = 1.0 x 10-14 [H+] = 10-7 M; pH = 7 neutral
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What is the pH of a [OH-] = 1.8 x 10-5?
[H+] = Kw / [OH-] pH = -log [H+] Answer 9.26
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Kw = [H+] [OH-] = 1.0 x 10-14 [H+] = 10-7 M; pH = 7 neutral [OH-] > 10-7 M; [H+] < 10-7 M; pH >7 Base
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If the pH of a solution= 2.6; what is the [H+]?
Answer 2.5 x 10-3 M
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Kw = [H+] [OH-] = 1.0 x 10-14 [H+] = 10-7 M; pH = 7 neutral [OH-] > 10-7 M; [H+] < 10-7 M; pH >7 Base [H+] > 10-7 M; [OH-] < 10-7 M; pH <7 Acid
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Effective pH Range 0-7 --Acid 7 -- Neutral Base What is the pH of a 2 M [H+]? Answer
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3. 4. Recognize and construct conjugates of acids or bases
3.4. Recognize and construct conjugates of acids or bases. [Readings 17.3 Problems 12,18,20]
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Conjugates H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid base
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H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid base
Conjugates H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid base Conjugates
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H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid base
Conjugates H2O + HCl (aq) <=> H3O+ (aq) + Cl- (aq) acid base Conjugates
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The Hydrolysis of Benzoic Acid
HC7H5O2 Write the equation. HC7H5O2(aq) + H2O(l) <==> H3O+ (aq) + C7H5O2 -(aq) Identify acids, bases, and conjugates.
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The Hydrolysis of Benzoic Acid
HC7H5O2 Write the equation. HC7H5O2(aq) + H2O(l) <==> H3O+ (aq) + C7H5O2 -(aq) Identify acids, bases, and conjugates. Base Acid conjugate
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The Hydrolysis of Benzoic Acid
HC7H5O2 Write the equation. HC7H5O2(aq) + H2O(l) <==> H3O+ (aq) + C7H5O2 -(aq) Identify acids, bases, and conjugates. Base Acid conjugate
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The Hydrolysis of Ammonia
NH3 is a base. H2O(l) + NH3(aq) <==> NH4+ (aq)+ OH-(aq)
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The Hydrolysis of Ammonia
NH3 is a base. H2O(l) + NH3(aq) <==> NH4+ (aq)+ OH-(aq) Acid Base
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The Hydrolysis of Ammonia
NH3 is a base. H2O(l) + NH3(aq) <==> NH4+ (aq)+ OH-(aq) H2O(l) as acid or base. Acid Base
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The Hydrolysis of Ammonia
NH3 is a base. H2O(l) + NH3(aq) <==> NH4+ (aq)+ OH-(aq) H2O(l) as acid or base. Base Hydrolysis Acid Base
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3. 5. Determine the [H+] and pH of a strong acid or base solution
3.5. Determine the [H+] and pH of a strong acid or base solution. [Readings 17.4 Problems 34]
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Hydrolysis of HCl H2O + HCl (aq) --> H3O+ (aq) + Cl- (aq)
I M M M pH = 1.0 F M M M K = large - Strong Acid conjugate Cl- -- according to B/L is a base
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3.6. Determine and relate equilibrium concentrations, [H+], pH and Ka values for weak acids (also, same for Kb values for weak bases). [Readings 17.5 Problems 40,42,44]
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Hydrolysis of HC7H5O2 H2O + HC7H5O2 (aq) <==> H3O+ (aq) + C7H5O2 - (aq) I M M M pH = 2.6 C M M M E M M M KA = [H3O+] [C7H5O2 - ] / [HC7H5O2 ] = 6.4 x Weak Acid conjugate C7H5O according to B/L is a base
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Strong Acids vs. Weak Acids
Strong Acids: HCl, HBr, HI, H2SO4, HNO3, HClO4 Strength is a measure of the extent of dissociation. Conjugates of weak acids are weak bases (v.v.). Conjugates of strong acids (or bases) are neutral. Examples of weak acids: Molecules -- HC2H3O2 Anions -- HSO4- Cations -- NH4+ Fe+3
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Strong Bases vs. Weak Bases
Strong Base: NaOH (s) --> Na+ (aq) + OH- (aq) K = Strong Bases: hydroxides of group I and II. Weak Base: C5H5N (aq) + H2O <==> C5H5N H+ (aq) + OH-(aq) KB = [C5H5N H+] [OH-] / [C5H5N] = 1.7 x 10 -9 Examples of weak bases: Molecules -- NH Anions -- F- Tables of values of KA and KB -- see page A20-22.
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3.7. Determine the [H+] and pH of weak acids or bases from initial concentrations. [Readings 17.7 Problems 46,48,50]
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What is the pH of a 1.0 M solution of C5H5N?
Is C5H5N acid or base, weak or strong? If strong acid (e.g. HCl) pH =0 If strong base (e.g. NaOH) pH =14 Must be weak! Look on KA and KB tables. KB = 1.7 x 10 -9
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3.8. Construct an ordered list of strongest to weakest (or vv) acids or bases. [Readings 17.3 Problems 22,24,26]
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Acid/Base Relative Strengths
In water solutions all strong acids are equally strong and all strong bases are equally strong. Weak acids and bases have relative strengths measured by their equilibrium constants. The stronger the acid or base the weaker the conjugate.
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Example Problem HI, K+, HC2H3O2, H2O2, HNO2
Rank the following in order of acid strength from largest to smallest. HI, K+, HC2H3O2, H2O2, HNO2
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3.9. Determine the Kb for a weak base, given the Ka value of its conjugate acid (vv). [Readings 17.6 Problems 66]
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Conjugate KA, KB relationships
HCN (aq) + H2O (l) <==> H3O+ (aq) + CN- (aq) KA=6.2x10-10 CN- (aq) + H2O (l) <==> OH- (aq) + HCN (aq) KB=? ______________________________________ 2 H2O (l) <==> H3O+ (aq) + OH- (aq) Kw=1.0x10-14 KA = [H3O+ ] [CN-] / [HCN ] KB = [OH-] [HCN ] / [CN-] Kw = [H3O+] [OH-] [H3O+ ] [CN-] / [HCN ] x [OH-] [HCN ] / [CN-] = [H3O+] [OH-] therefore: KA KB = Kw ; KB = Kw / KA KB = 1.0x10-14 / 6.2x10-10 = 1.6x10-5
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3. 11. Qualitatively determine the acidic or basic properties of salts
3.11. Qualitatively determine the acidic or basic properties of salts. [Readings 17.8 Problems 60,61]
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The interaction of acids and bases
Acid + Base --> Salt + Water SA SB WA SB SA WB WA WB
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Examples: Strong Weak Acid HCl HCN; KA= 6.2x10-10 Base NaOH NH3; KB= 1.8x10-5
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Strong Acid + Strong Base
NaOH + HCl --> NaCl + H2O NaOH --> Na+ + OH- SB N H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Strong Base
NaOH + HCl --> NaCl + H2O NaOH --> Na+ + OH- SB N H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Strong Base
NaOH + HCl --> NaCl + H2O NaOH --> Na+ + OH- SB N H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Strong Base
NaOH + HCl --> NaCl + H2O NaOH --> Na+ + OH- SB N H2O + HCl --> H3O+ + Cl- SA N NaCl -- Neutral Salt
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The interaction of acids and bases
Acid + Base --> Salt + Water SA SB N WA SB SA WB WA WB
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Weak Acid + Strong Base NaOH + HCN --> NaCN + H2O NaOH --> Na+ + OH- SB N H2O + HCN --> H3O+ + CN- WA WB
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Weak Acid + Strong Base NaOH + HCN --> NaCN + H2O NaOH --> Na+ + OH- SB N H2O + HCN --> H3O+ + CN- WA WB
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Weak Acid + Strong Base NaOH + HCN --> NaCN + H2O NaOH --> Na+ + OH- SB N H2O + HCN --> H3O+ + CN- WA WB
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Weak Acid + Strong Base NaOH + HCN --> NaCN + H2O NaOH --> Na+ + OH- SB N H2O + HCN --> H3O+ + CN- WA WB NaCN -- Basic Salt
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The interaction of acids and bases
Acid + Base --> Salt + Water SA SB N WA SB B SA WB WA WB
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Strong Acid + Weak Base NH3 + HCl --> NH4Cl H2O + NH3 --> NH4+ + OH- WB WA H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Weak Base NH3 + HCl --> NH4Cl H2O + NH3 --> NH4+ + OH- WB WA H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Weak Base NH3 + HCl --> NH4Cl H2O + NH3 --> NH4+ + OH- WB WA H2O + HCl --> H3O+ + Cl- SA N
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Strong Acid + Weak Base NH3 + HCl --> NH4Cl H2O + NH3 --> NH4+ + OH- WB WA H2O + HCl --> H3O+ + Cl- SA N NH4Cl -- Acidic Salt
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The interaction of acids and bases
Acid + Base --> Salt + Water SA SB N WA SB B SA WB A WA WB
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Weak Acid + Weak Base NH3 + HCN --> NH4CN H2O + NH3 --> NH4+ + OH- WB WA KB= 1.8x KA= 5.6x10-10 H2O + HCN --> H3O+ + CN- WA WB KA= 6.2x KB= 1.6x10-5
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Weak Acid + Weak Base NH3 + HCN --> NH4CN H2O + NH3 --> NH4+ + OH- WB WA KB= 1.8x KA= 5.6x10-10 H2O + HCN --> H3O+ + CN- WA WB KA= 6.2x KB= 1.6x10-5
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Weak Acid + Weak Base NH3 + HCN --> NH4CN H2O + NH3 --> NH4+ + OH- WB WA KB= 1.8x KA= 5.6x10-10 H2O + HCN --> H3O+ + CN- WA WB KA= 6.2x KB= 1.6x10-5
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Weak Acid + Weak Base NH3 + HCN --> NH4CN H2O + NH3 --> NH4+ + OH- WB WA KB= 1.8x KA= 5.6x10-10 H2O + HCN --> H3O+ + CN- WA WB KA= 6.2x KB= 1.6x10-5 NH4CN -- Basic Salt
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The interaction of acids and bases
Acid + Base --> Salt + Water SA SB N WA SB B SA WB A WA WB depends on relative strengths
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Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- Conjugate NaOH
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- Conjugate NaOH SB
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- N Conjugate NaOH SB
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- N Conjugate Conjugate NaOH SB HCHO2
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- N Conjugate Conjugate NaOH SB HCHO2 WA
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- N B Conjugate Conjugate NaOH SB HCHO2 WA
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Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2-
Self Test Sodium Formate -- NaCHO2 NaCHO2 --> Na+ + CHO2- B N B Conjugate Conjugate NaOH SB HCHO2 WA
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3-
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- NaOH
Conjugate NaOH
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- NaOH SB
Conjugate NaOH SB
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- N NaOH SB
Conjugate NaOH SB
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- N NaOH SB
Conjugate Conjugate NaOH SB HNO3
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- N NaOH SB
Conjugate Conjugate NaOH SB HNO3 SA
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- N N NaOH SB
Conjugate Conjugate NaOH SB HNO3 SA
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Self Test Sodium Nitrate -- NaNO3 NaNO3 --> Na+ + NO3- N N N NaOH
Conjugate Conjugate NaOH SB HNO3 SA
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Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - Conjugate NH3
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - Conjugate NH3 WB
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - A Conjugate NH3 WB
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - A Conjugate Conjugate NH3 WB HBr
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - A Conjugate Conjugate NH3 WB HBr SA
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - A N Conjugate Conjugate NH3 WB HBr SA
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Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br -
Self Test Ammonium Bromide -- NH4Br NH4Br--> NH4+ + Br - A A N Conjugate Conjugate NH3 WB HBr SA
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3. 10. Determine the pH of a salt solution. [Readings 17
3.10. Determine the pH of a salt solution. [Readings 17.8 Problems 62,64]
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What is the pH of a solution of 3.45 g of NaNO2 in 250 mL of solution?
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3. 12. Identify acids and bases using Lewis theory. [Readings 17
3.12. Identify acids and bases using Lewis theory. [Readings Problems 74]
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Self Test Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl-
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Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl-
Self Test Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl- Conjugate HCl
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Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl-
Self Test Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl- Conjugate HCl SA
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Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl-
Self Test Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl- N Conjugate HCl SA
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Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl-
Self Test Iron (III) Chloride -- FeCl3 FeCl3 --> Fe+3 + 3Cl- N Conjugate Conjugate ? HCl SA
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Fe+3 tests as an acid +3 Fe .. O .. H High Charge to Size Ratio
Al+3, Fe+3 are two best examples H O .. ..
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Lewis Theory of Acids and Bases
Acid -- Electron Pair Acceptor Base -- Electron Pair Donor C N - . A l + 3
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Comparing Theories H + O - : . . . + - H : O H . . . . + - H : O H . .
B/L Theory Lewis . . Arrhenius + - H : O H . . . . + - H : O H . .
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3. 13. Determine the pH of weak and strong polyprotic acids
3.13. Determine the pH of weak and strong polyprotic acids. [Readings 17.9 Problems 72]
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Self Test Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3-
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Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3-
Self Test Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3- Conjugate NaOH
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Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3-
Self Test Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3- Conjugate NaOH SB
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Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3-
Self Test Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3- N Conjugate NaOH SB
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Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3-
Self Test Sodium Bicarbonate -- NaHCO3 NaHCO3 --> Na+ + HCO3- N Conjugate Conjugate NaOH SB ?
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HCO Acid or Base? HCO3- + H2O <==> H3O+ + CO3-2 HCO3- + H2O <==> H2CO3 + OH-
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HCO3- + H2O <==> H3O+ + CO3-2
HCO Acid or Base? HCO3- + H2O <==> H3O+ + CO3-2 HCO3- + H2O <==> H2CO3 + OH- H O C
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HCO3- + H2O <==> H3O+ + CO3-2
HCO Acid or Base? HCO3- + H2O <==> H3O+ + CO3-2 HCO3- + H2O <==> H2CO3 + OH- KA2 = 5.6 x 10-11 KB = Kw / KA1 = 1 x / 4.3 x 10-7 = 2.3 x 10-8 H O C
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H2CO3 + H2O <==> H3O+ + HCO3-
Polyprotic Acids H2CO3 + H2O <==> H3O+ + HCO3- HCO3- + H2O <==> H3O+ + CO3-2 KA1 = 4.3 x 10-7 KA2 = 5.6 x 10-11
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What is the pH of Polyprotic Strong Acids
H2SO4 + H2O --> H3O+ + HSO4- KA1 = large HSO4- + H2O --> H3O+ + SO KA2 = 1.2 x 10-2 Depends on Concentration-- if 1M the second H+ makes almost no difference at lower concentrations second H+ makes a larger contribution
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What is the pH of Polyprotic Weak Acids
H3PO4 + H2O --> H3O+ + H2PO4- KA1 = 7.5 x 10-3 H2PO4- + H2O --> H3O+ + HPO4-2 KA2 = 6.2 x 10-8 HPO H2O --> H3O+ + PO KA3 = 4.8 x 10-13 Second H+ makes almost no difference
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